Technical Communication (CS300)
Nishi Mehta September 2, 2022
Abstract
The lecture is a discussion on Prime Numbers. Further we try to prove the claim that the set of all the prime numbers is an infinite set. This claim is proved using 3 different methods.
1 Introduction
Prime numbers are the numbers that are perfectly divisible by either 1 or the number itself.
The prime numbers are interesting because
• no other number can divide them.
• all the natural numbers are made up of prime numbers.
Let, the set P represent the set of all the prime numbers:
P ={2,3,5, ...}
the first question that arises is - is the set finite or infinite? So, the aim of this lecture is to prove that the set P contains infinite elements.
2 Proofs
2.1 Euclid’s Proof
This proof was given by Euclid and the proof is from ”The Book”.
Let’s assume the set P is finite such that P = {p1, p2, p3, ..., pn}. This means that all the other natural numbers are divisible by atleast one prime number. Let, k = p1p2p3..pn+ 1.
Then k is not divisible by any prime number. This contradicts the assumption that there are only n prime numbers.
Hence proved, that the set P is an infinite set.
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2.2 Proof 2
Again, let’s assume that there exist finite number of prime numbers andpis the largest prime number amongst them, also q is a prime number such that 2 < q < p and by Lagrange’s Theorem,
2p−1 = 0 mod q Let k be the first number such that 2k−1 = 1 modq From there the series will repeat
⇒ 20 modq, 21 mod q, 22 modq ...
⇒ 2k mod q, 2k+ 1 mod q, 2k+ 2 mod q ...
. .
⇒ 2m mod q
This means that m is divisible by q−1 (Fermat’s Theorem). Thus p is also divisible by q−1, since 2p−1 = 0 modq
⇒ q > p
This contradicts our assumption that p is the largest prime number.
Hence proved, there are infinite number of prime numbers.
2.3 Erd˝ os’ Proof
This proof was given by Erd˝os and takes into acount the idea that when Pn i=1
1
pi diverges, n→ ∞, where P ={p1, p2, ...pn}i the set of prime numbers.
Let’s us assume that the series Pn i=1
1
pi converges.
⇒ ∃k for which P
i+1 1 pi ≤ 12.
⇒ ∀N,P
i N pi ≤ N2. Let’s assume ∀n≤ N :
⇒ if, ∃pm;m≥k+ 1 and pm mod n= 0, then n∈Nbig orn is a big number.
⇒ else, n∈Nsmall orn is a small number.
Clearly, Nbig+Nsmall =N
There exists a number that is a small number ≤N, which is represented by ab2 where a is product of small prime numbers less than equal to pk.
Since there are K prime numbers less than or equal to pk, the number of distinct values of a≤2k. The number of values of b≤√
N. Therefor, Nsmall≤2k√
N.
⇒ Nbig ≤ N2
⇒ so we need to chhos anN for which Nsmall ≥ N2
⇒ N2 ≤2k√ N
2
⇒ N ≤22(k+1)
This contradicts because N cannot be less than 22(k+1). This means thatP
i 1
pi diverges.
Hence proved, that n → ∞or there are infinite number of prime numbers.
3 Conclusions
Based on these 3 proofs we can conclude that there exist infinite number of prime numbers or the set containing prime numbers is an infinite set.
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