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6.1. 正弦定理の利⽤ No1 解答

1 c = , R =

( ) 3

2

6 3

2 2

2 b = 2, c = 2

( ) 2

3 a = 3 , ∠B = 60°

( ) 3

6.1. 正弦定理の利⽤ No2 解答

1 sin∠C = , cos∠C =

( ) 6

3

6 33

2 sin∠C = , sin∠B =

( ) 1

2

1 2

3 sin∠BAD =

( ) -

6

15 3

6.1. 正弦定理の利⽤ No3 解答

1 a = + 3, R = +

( ) 6 3 2

2 a = 4

( ) 3

3 ∠C = 45°, S = 3 ( )

6.2. 余弦定理の利⽤ No1 解答

1 a =

( ) 13

2 ∠B = 120°

( )

3 c = 2 + 2

( ) 2

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6.2. 余弦定理の利⽤ No2 解答

1 ∠C = 45°

( ) 2 b =

( ) 5

3 b =

( ) 3 +

2 21

6.2. 余弦定理の利⽤ No3 解答

1 b = - , ∠A = 45°

( ) 6 2

2 a =

( ) 6

3 b = 1, - 1

( ) 3

6.3. 正弦定理・余弦定理の三⾓形への利⽤(1) No1 解答

1 b =

( ) +

2

6 2

2 a = 2 + 2 のとき、∠C = 45°

( ) 3

a = 2 3- 2 のとき、∠C = 135°

3 a = 3 , b = 3 +

( ) 2 3

6.4. 正弦定理・余弦定理の三⾓形への利⽤(2) No1 解答

BD = 8, AD = 12

6.4. 正弦定理・余弦定理の三⾓形への利⽤(2) No2 解答

BD = 2 3, AC = 3

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6.5. 三⾓形の辺と⾓の⼤⼩ No1 解答

1 ∠B = 60°

( )

2 tan∠A =

( ) 5

11 3

6.5. 三⾓形の辺と⾓の⼤⼩ No2 解答

1 ∠C = 135°

( )

2 tan∠A =

( ) 1

3

6.6. 三⾓形の成⽴条件 No1 解答

1 2 < x < 4 ( )

2 2 < x < 2 , < x < 4

( ) 2 10

3 2 < x <

( ) 7

6.6. 三⾓形の成⽴条件 No2 解答

1 x > 3 ( )

2 x > 3 + 2

( ) 3

6.7. 三⾓形の⾯積 No1 解答

1 S =

( ) 3

2 ( )2 S = +

8

3 15

3 S =

( ) 2

3 ( )4 S = + 3

8 3

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6.7. 三⾓形の⾯積 No2 解答

1 S = 3

( ) ( )2 S = 6 6

3 S =

( ) 2

3 ( )4 S = 3 + 3

2 3

6.8. 四⾓形の⾯積 No.1 解答

1 S = 12 ( )

2 S =

( ) 77

4 3

6.8. 四⾓形の⾯積 No2 解答

1 S = 12

( ) 6

2 S = 10

( ) 3

6.9. 正多⾓形の⾯積 No1 解答

1 ( ) 3

2 3

2 2

( ) 2

6.9. 正多⾓形の⾯積 No2 解答

1 2

( ) 3

2 6 + 3

( ) 3

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6.9. 正多⾓形の⾯積 No3 解答

8 2- 8

6.10. 三⾓形の内接円・外接円 No1 解答

1 cos∠A = - , sin∠A =

( ) 1

4 4

15

2 S =

( ) 3

4 15

3 r =

( ) 6

15

4 R =

( ) 8

15 15

6.10. 三⾓形の内接円・外接円 No2 解答

1 r =

( ) 2

3 6

2 c =

( ) 7 ±

2

3 51

6.11. 円に内接する四⾓形 No1 解答

1 AC =

( ) 13

2 AD = - 1 +

( ) 10

3 S =

( ) 5 +

2

3 30

4 R =

( ) 39

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6.11. 円に内接する四⾓形 No2 解答

1 sin∠ =

( ) 2

7 6

2 S = 2

( ) 6

6.11. 円に内接する四⾓形 No3 解答

1 BD = 1 +

( ) 6

2 cos∠BAD =

( ) - 3

6 6

3 AB =

( ) 3 + 2

3 6

4 S =

( ) 4 + 7

3

3 2

6.12. 三⾓形の⾯積の最⼤値・最⼩値 No1 解答

1 ▵ADE = t 1 - 2t

( ) ( )

2 t = のとき、最⼤値

( ) 1

4

1 8

6.12. 三⾓形の⾯積の最⼩値 No2 解答

1 S = x - x + 1

( ) 11

4

3 2 3 2

3

2 x = のとき最⼩値

( ) 3

11

44 - 9 44

3

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