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Analytical Solution of

1D Single Phase Flow Equation

[ ]

Hoonyoung Jeong

Department of Energy Resources Engineering Seoul National University

[email protected] SNU ERE Hoonyoung Jeong

(2)

Assumptions in Analytical Solution of 1D Flow Equation

Homogeneous rock

Constant porosity and permeability

How different from isotropy?

Constant fluid viscosity Things that are needed to Derive a Flow Equation (for Reservoir Simulation)

Reservoir structure

1-dimension

Fluid properties

Single phase

✓Fluid compressibility (slightly compressible fluid)

Rock properties

✓Porosity

Permeability

Rock compressibility (slightly compressible rock)

Properties of rock and fluid

Capillary pressure

Relative permeability

Governing equation

Continuity equation

✓Constitutive equation

Darcy’s law

Boundary and initial conditions

[email protected] SNU ERE Hoonyoung Jeong

(3)

1D Flow Equation

𝜕

𝜕𝑥

𝑘𝜌 𝜇

𝜕𝑃

𝜕𝑥 + 1

𝜕𝑥𝜕𝑦𝜕𝑧

𝜕 𝜌𝑉𝑒𝑥𝑡

𝜕𝑡 = 𝜕 𝜙𝜌

𝜕𝑡

Use the Dirichlet condition for P

A location with 𝑉𝑒𝑥𝑡 is assumed to have infinite volume

✓𝑉𝑒𝑥𝑡 does not affect P, so it can be ignored

𝜕

𝜕𝑥

𝑘𝜌 𝜇

𝜕𝑃

𝜕𝑥 = 𝜕 𝜙𝜌

𝜕𝑡

𝑘

𝜇

𝜕𝜌

𝜕𝑥

𝜕𝑃

𝜕𝑥 + 𝜌 𝜕2𝑃

𝜕𝑥2 = 𝜌 𝜕𝜙

𝜕𝑡 + 𝜙 𝜕ρ

[email protected]𝜕𝑡

SNU ERE Hoonyoung Jeong

(4)

Analytical Solution

If 𝑃 𝑥 = 0, 𝑡 = 𝑃0 𝑃 𝑥 = 𝐿, 𝑡 = 𝑃𝐿 𝑃 𝑥, 𝑡 = 0 = 𝑃𝐿

𝑃 𝑥, 𝑡 = 𝑃0 + 𝑃𝐿 − 𝑃0 𝑥

𝐿 + 2

𝜋

𝑛=1

1

𝑛 exp − 𝑛2𝜋2 𝐿2

𝑘

𝜙𝜇𝐶𝑡 𝑡 sin 𝑛𝜋𝑥

[email protected]𝐿

SNU ERE Hoonyoung Jeong

(5)

Sensitivity Analysis

If 𝑃0 > 𝑃𝐿

Guess physically and mathematically

What if k is larger?

What if porosity is larger?

What if Ct is larger?

What if 𝜇 is larger?

𝑃 = 𝑃0 − 𝑃0 − 𝑃𝐿 𝑥 𝐿

𝜕2𝑃

𝜕𝑥2 = 𝜙𝜇𝐶𝑡 𝑘

𝜕𝑃

𝜕𝑡

[email protected] SNU ERE Hoonyoung Jeong

Referensi

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