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‹ˆˆ‡”‡–‹ƒŽ“—ƒ–‹‘•

͖͔͕͙͖͔͗ —†ƒ‡–ƒŽ•‘ˆ

(2)

Definition

A differential equation is an equation that contains an unknown function and some of its derivatives.

The order of a differential equation is the order of the highest derivative that occurs in the equation.

݀ݕ

݀ݔ ൌ ʹݔݕ ൅ ͳ

݀ݕ

݀ݐ ݐ݀ݕ

݀ݐ ݐ െ ͳ ݕ ݁

݀ݕ

݀ݔ

െ ͺݔ ݀ݕ

݀ݔ

൅ ͵ݔݕ ݔ െ ͳ

ן ߲ݑ

߲ݔ ߲ݑ

߲ݐ

߲ݑ

߲ݔ߲ݐ ൌ ͳ ൅ ߲ݑ

߲ݐ

(3)

Ordinary Differential Equations (ODE)

Partial Differential Equations (PDE)

݀ݕ

݀ݔ ൌ ʹݔݕ ൅ ͳ

݀ݕ

݀ݐ ݐ݀ݕ

݀ݐ ݐ െ ͳ ݕ ݁

݀ݕ

݀ݔ

െ ͺݔ ݀ݕ

݀ݔ

൅ ͵ݔݕ ݔ െ ͳ

ן ߲ݑ

߲ݔ ߲ݑ

߲ݐ ߲ݑ

߲ݔ߲ݐ ൌ ͳ ൅ ߲ݑ

߲ݐ

(4)

Solution of a differential equation

A function f is called a solution of a differential equation if the equation is satisfied when y = f(x) and its derivatives are

substituted into the equation.

If f is a solution of y' = xy, then ׊x א I, f'(x) = xf(x).

To solve a differential equation means finding all possible solutions of the equation.

The solution of y' = x is ݕ ݔ

ʹ ܥǤ

(5)

Exercise

1. Show that every member of the family of functions

is a solution of the differential equation

ݕ

ͳ ൅ ܿ݁

ͳ െܿ݁

ݕԢ ൌ ݕ െ ͳ ʹ Ǥ

(6)

Initial condition

Usually, we are not interested in a family of solutions (general solution). We want to find a particular solution that satisfies some additional requirement.

For example, it must satisfy a condition y(t0) = y0.

This is called an initial condition and the problem of finding a solution of this is called an initial-value problem.

(7)

Exercise

2. Find a solution of the differential equation that satisfies the initial condition y(0) = 2.

ݕԢ ൌ ݕ െ ͳ ʹ

(8)

General and specific solution

Consider

then y = e

2x

is a solution of this differential equation.

In addition, y = e

x

+ e

2x

is also one of the solution of this differential equation.

y

= Ce

x

+ e

2x

where C is a real number is a general solution of the differential equation.

y

= e

x

+ e

2x

is a specific solution for the differential equation.

݀ݕ݀ݔ ݕ ݁ଶ௫

(9)

Exercise

3. Show that y = xx-1 is a solution of the differential equation xy' + y = 2x.

(10)

'LUHFWLRQ)LHOGV

(11)

Direction Fields

Sketch of solutions: Guides to sketch the graphs of solutions to the differential equation

y ′ = + x y

Long-term behavior: how the solutions behave as x increases.

(12)
(13)

Exercise

9. Sketch the direction field for ݀ݕ݀ݔ ൌ › െ šǤ

10. Sketch the direction field for ݕ ൌ ሺݕ ݕ െ ʹሻሺͳ െ ݕ.

(14)

͝Ǥ͕͔Ǥ

Š––’ǣȀȀ–—–‘”‹ƒŽǤƒ–ŠǤŽƒƒ”Ǥ‡†—ȀŽƒ••‡•ȀȀ‹”‡…–‹‘ ‹‡Ž†•Ǥƒ•’š

(15)

)LUVW2UGHU'LIIHUHQWLDO(TXDWLRQV

(16)

)LUVW2UGHU'LIIHUHQWLDO(TXDWLRQV

݀ݕ

݀ݔ ൌ ݂ሺݕ ǡ ݔ ሻ

‡’ƒ”ƒ„އ‡“—ƒ–‹‘•

‹‡ƒ”‡“—ƒ–‹‘•

(17)

Separable equations

A separable equation is a first-order differential equation in which the expression y' can be factored as a function of x times the function of y. That means

We rewrite . It becomes

h(y) dy = g(x) dx

So that all y’s are on one side of the equation and all x’s are on the other side

݀ݕ

݀ݔ ݃ ݔ ݂ ݕ

݄ ݕ ͳ

݂ ݕ

݄ ݕ ݀ݕ න݃ ݔ ݀ݔ

(18)

Verification

We can verify that is the solution of

By using the Chain rule,

݀ݕ݀ݔ ݃ ݔ ݂ ݕ

݄ ݕ ݀ݕ න݃ ݔ ݀ݔ

݀

݀ݔ න݄ ݕ ݀ݕ ݀

݀ݔ න݃ ݔ ݀ݔ

݀ݕ න݀ ݄ ݕ ݀ݕ ݀ݕ

݀ݔ ݃ ݔ

݄ ݕ ݀ݕ

݀ݔ ݃ ݔ

(19)

Exercise

4. Solve the differential equation and find the solution with the initial condition y(0) = 1.

݀ݕ

݀ݔ ݔ ݕ

5. Solve the differential equation ݀ݕ

݀ݔ ݁ଶ௫ ͶݕǤ

(20)

Linear differential equation

A first order linear differential equation is one that can be put into the form

where P and Q are continuous functions on I.

Consider the first order linear differential equation xy' + y = 2x

LHS: xy' + y = (xy)' RHS:

Therefore, xy = x2 + C.

݀ݕ݀ݔ ܲ ݔ ݕ ܳ ݔ

ʹݔ݀ݔ ൌ ʹݔ ʹ ܥ

(21)

Exercise

6. Find the general solution of ݕԢ ൅ ͳ

ݔ ݕ ൌ ͵Ǥ

(22)

Integrating factor

To solve the first order linear differential equation, we multiply the suitable integrating factor, I(x).

to get

If we can find such a function I(x),

(I(x)y)' = I(x)Q(x).

Hence,

݀ݕ݀ݔ ܲ ݔ ݕ ܳ ݔ

ܫ ݔ ݀ݕ

݀ݔ ܲ ݔ ݕሻ ൌ ܫ ݔ ܳ ݔ Ǥ

ܫ ݔ ݕ නܫ ݔ ܳ ݔ ݀ݔ ܥǤ

(23)

Integrating factor

The property of I(x) is

I(x)P(x) = I'(x).

This is a separable differential equation,

Hence,

ͳ

ܫ ݔ ݀ܫ ݔ නܲ ݔ ݀ݔ

ސ פ ܫ ݔ פ ൅ܥ නܲ ݔ ݀ݔ ܫ ݔ ܣ݁׬ ௉ ௫ ௗ௫Ǥ

(24)

Exercise

7. Solve the differential equation ݀ݕ݀ݔ ൅ ͵ݔݕ ൌ ͸ݔǤ

8. Find the solution of the initial-value problem x2y' + xy = 1, x > 0 and y(1) = 2.

(25)

6\VWHPVRI)LUVW2UGHU/LQHDU'LIIHUHQWLDO(TXDWLRQV

(26)

6\VWHPVRI)LUVW2UGHU/LQHDU'LIIHUHQWLDO(TXDWLRQV

•›•–‡‘ˆŽ‹‡ƒ”ˆ‹”•–‘”†‡”†‹ˆˆ‡”‡–‹ƒŽ‡“—ƒ–‹‘•‹

—‘™•Šƒ•–Ї‰‡‡”ƒŽˆ‘”ǣ

ƒέ  •›•–‡‘ˆŽ‹‡ƒ”‡“—ƒ–‹‘•

™Š‡”‡–Ї…‘‡ˆˆ‹…‹‡–•ƒ‹Œǯ•ǡƒ†‰‹ ǯ•ƒ”‡ƒ”„‹–”ƒ”›ˆ—…–‹‘•‘ˆ–Ǥ

ˆ‡˜‡”›–‡”‰‹ ‹•…‘•–ƒ–œ‡”‘ǡ–Ї–Ї•›•–‡‹••ƒ‹†–‘„‡Š‘‘‰‡‡‘—•Ǥ

–Ї”™‹•‡ǡ‹–‹•ƒ‘Š‘‘‰‡‡‘—••›•–‡‹ˆ‡˜‡‘‡‘ˆ–Ї‰ǯ•‹•‘œ‡”‘Ǥ

(27)

šǯ š ‰

šǯ γšή‰

(28)

˜‡”›Ǧ–Š ‘”†‡”Ž‹‡ƒ”‡“—ƒ–‹‘‹•‡“—‹˜ƒŽ‡––‘ƒ•›•–‡‘ˆ ˆ‹”•–

‘”†‡”Ž‹‡ƒ”‡“—ƒ–‹‘•Ǥ

Ǧ–Š ‘”†‡”Ž‹‡ƒ”‡“—ƒ–‹‘ƒ†•›•–‡•‘ˆˆ‹”•–‘”†‡”Ž‹‡ƒ”‡“—ƒ–‹‘•

‘”‡šƒ’އǡ

(29)

‹˜‡ƒǦ–Š ‘”†‡”Ž‹‡ƒ”‡“—ƒ–‹‘

ƒ‡–Ї•—„•–‹–—–‹‘•ǣš͕ί›ǡš͖ί›ƍǡš͗ί›Ǝǡǥǡš ί›ȋΫ͕Ȍǡƒ†šƍ ί›ȋȌǤ

ЇƤ”•–Ϋ͕‡“—ƒ–‹‘•ˆ‘ŽŽ‘™–Š—•Ž›Ǥƒ•–Ž›ǡ•—„•–‹–—–‡–Їšǯ•‹–‘–Ї‘”‹‰‹ƒŽ

‡“—ƒ–‹‘–‘”‡™”‹–‡‹–‹–‘–ЇǦ–Š ‡“—ƒ–‹‘ƒ†‘„–ƒ‹–Ї•›•–‡‘ˆ–Їˆ‘”ǣ

(30)

Exercise

Convert the following equation into a system of first order equations

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