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Introduction to Materials Science and Engineering 21089201

Chedtha Puncreobutr

Department of Metallurgical Engineering Chulalongkorn University

Nucleation and Growth Kinetics

(2)

Phase transformation

Nucleation - The physical process by which a new phase is produced in a material. It is the initial process in crystallization.

Most phase transformations begin with the formation of numerous small particles of the new phase that increase in size until the transformation is

complete.

(3)

Nucleation

• Nucleation is the process of forming a nucleus

• It is the process in which ions, atoms, or molecules arrange themselves in a pattern characteristic of a crystalline solid, forming a site in which additional particles deposit as the crystal grows

• Some examples of phases that may form by way of nucleation in liquids are gaseous bubbles, crystals, or glassy regions.

• Creation of liquid droplets in saturated vapour is also characterized by nucleation

(4)

Nucleation mechanisms

• Homogeneous nucleation

Formation of a critically sized solid from the liquid by the clustering together of a large number of atoms at a high undercooling (without an external interface).

• Heterogeneous nucleation

Formation of a critically sized solid from the liquid on

an impurity surface.

(5)

Driving force

The change in free energy DG (function of the internal energy and enthalpy of the system) must be negative for a transformation to occur.

𝑻 > 𝑻𝒎 𝑻 < 𝑻𝒎

liquid solid

∆𝐺 = ∆𝐻 − 𝑇∆𝑆

∆𝐺 = 0 = ∆𝐻 − 𝑇

𝑚

∆𝑆

𝑎𝑡 𝑇𝑚 Undercooling:

∆𝑆 = ∆𝐻

𝑇

𝑚

= ∆𝐻

𝑓

𝑇

𝑚 entropy of fusion Temperature

Molar free energy (DG)

𝐺𝑆 𝐺𝐿

∆𝐺

𝑇𝑚 𝑇

∆𝑇

for small∆𝑇

∆𝐺 = ∆𝐻

𝑓

− 𝑇 ∆𝐻

𝑓

𝑇

𝑚

∆𝐺 ≅ ∆𝐻

𝑓

𝑇

𝑚

∆𝑇

∆𝑇 = 𝑇𝑚 − 𝑇

(6)

Homogeneous Nucleation

• Assume that nuclei of the solid phase form spontaneously in the interior of the liquid as atoms cluster together- similar to the packing in the solid phase.

• Also, each nucleus is spherical and has a radius r

• Free energy changes as a result of a transformation:

1) the difference between the solid and liquid phases (volume free energy, DG

V

)

2) the solid-liquid phase boundary

(surface free energy, DG

S

). ∆𝐺 = −𝑉

𝑠

∆𝐺

𝑣

+ 𝐴

𝑠𝑙

𝛾

𝑠𝑙
(7)

Homogeneous Nucleation & Energy Effects

DG

T

= Total Free Energy

= DG

S

+ DG

V

Surface Free Energy - destabilizes the nuclei (it takes energy to make an interface)

D G

S

4 r

2

 = surface tension

Volume (Bulk) Free Energy –

stabilizes the nuclei (releases energy)

D

D G

V

r

3

G 3

4

∆𝐺

𝑉

= − 4

3 𝜋𝑟

3

∆𝐻

𝑓

𝑇

𝑚

∆𝑇

(8)

Homogeneous Nucleation & Critical radius

∆𝐺 = −4

3𝜋𝑟3∆𝐻𝑓

𝑇𝑚 ∆𝑇 + 4𝜋𝑟2𝛾𝑆𝐿

𝑑∆𝐺

𝑑𝑟 = 0 at 𝑟

∆𝐺 = 16𝜋𝛾𝑆𝐿3𝑇𝑚 2 3∆𝐻𝑓2∆𝑇2 𝑟 < 𝑟

𝑟 > 𝑟

embryos - melt back nuclei - grow

(∆𝐺ℎ𝑜𝑚𝑜)

𝑟 = 2𝛾𝑆𝐿𝑇𝑚

∆𝐻𝑓∆𝑇 surface free energy α 𝑟2

volume free energy α 𝑟3∆𝑇

(9)

Homogeneous Nucleation & Critical radius

∆𝐺 = 16𝜋𝛾𝑆𝐿3𝑇𝑚 2 3∆𝐻𝑓2∆𝑇2 𝑟 = 2𝛾𝑆𝐿𝑇𝑚

∆𝐻𝑓∆𝑇  r* decreases as DT increases For typical DT r* ~ 10 nm

(10)

Critical Radius for the Solidification of Copper

Calculate the size of the critical radius and the number of atoms in the critical

nucleus when solid copper forms by homogeneous nucleation.

(11)

Rate of formation of homogeneous nuclei

r

Number of stable nuclei 𝑛 = 𝑛𝐿𝑒𝑥𝑝 −∆𝐺

𝑘𝐵𝑇

= Boltzmann’s constant 𝑘𝐵

𝑣𝑑 atomic vibration frequency

𝑝𝑐 probability of capturing an atom at the surface

(12)

Rate of formation of homogeneous nuclei

ሶ 𝑁

ℎ𝑜𝑚

= 𝑣

𝑑

𝑝

𝑐

𝑛

𝐿

𝑒𝑥𝑝 − 16𝜋 3

𝛾

𝑆𝐿3

𝑇

𝑚2

𝑘

𝐵

𝑇∆𝐻

𝑓2

∆𝑇

2

At high temperatures, the thermodynamic driving force for nucleation becomes less due to the lower undercooling and the number of critical clusters will be limited.

At low temperatures, the thermodynamic driving force for the nucleation is large due to the large undercooling, but the rate of diffusion of atoms to the nucleation site is reduced

(13)

Heterogeneous nucleation

(14)

Heterogeneous nucleation

When solidification is initiated from a foreign surface, i.e. solid particles suspended in liquid, oxide layers, or surface contact with a crucible wall, it is said to nucleate heterogeneously

Assuming a spherical cap shape of nucleus formed on a surface of foreign substrate

(15)

Heterogeneous nucleation

The positive interfacial energy term can be reduced by a factor

∆𝐺

ℎ𝑒𝑡𝑒𝑟

= 16𝜋𝛾

𝑆𝐿3

𝑇

𝑚 2

3∆𝐻

𝑓2

∆𝑇

2

𝑓(𝜃)

∆𝐺

ℎ𝑒𝑡𝑒𝑟

= ∆𝐺

ℎ𝑜𝑚𝑜

∙ 𝑓 𝜃

𝑓(𝜃)

 = wetting angle

𝑓(𝜃) geometric factor given by ratio of the

volumes of spherical cap and a full sphere of identical radius

Since the heterogeneous nucleation barrier is lower than that of homogeneous

nucleation, it is much easier for heterogeneous nucleation to occur during solidification.

(16)

Heterogeneous nucleation

∆𝐺ℎ𝑒𝑡𝑒𝑟 = 16𝜋𝛾𝑆𝐿3𝑇𝑚2

3∆𝐻𝑓2∆𝑇2 𝑓(𝜃)

= 16𝜋𝛾𝑆𝐿3𝑇𝑚 2 3∆𝐻𝑓2∆𝑇2

(17)

Heterogeneous nucleation

• Lower free energy for heterogeneous nucleation means a smaller energy to overcome during nucleation process, therefore, heterogeneous nucleation occurs more readily

• Much smaller degree of undercooling is required for heterogeneous

nucleation.

(18)

Growth

ሶ 𝐺 = 𝐶 𝑒𝑥𝑝 − 𝑄 𝑘

𝐵

𝑇

• Growth rate is determined by the rate of diffusion, and its temperature dependence is the same as for the

diffusion coefficient

• Growth step in a phase transformation begins once an embryo has exceeded the critical size and becomes a stable nucleus

• Particle growth occurs by long-range atomic diffusion

(19)

Growth

• Transformation occurs near melting point, low nucleation but high growth rate. Thus, resulting microstructure will consist few and relatively large particles (e.g. coarse grains)

• Nucleation will continue to occur simultaneously with growth of the new phase particles. At a specific temperature, the overall transformation rate is equal to some product of nucleation and growth rates

• The size of the product phase particles will depend on transformation temperature

• Conversely, for transformations at lower temperatures, nucleation rates are high and growth rates low, which results in many small particles (e.g., fine grains).

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