Short communication
An approximate analytic solution of the Blasius problem
Faiz Ahmad
a,*, Wafaa H. Al-Barakati
baCentre for Advanced Mathematics and Physics, National University of Science and Technology, EME Campus, Peshawar Road, Rawalpindi, Pakistan
bDepartment of Mathematics, Faculty of Science, King Abdulaziz University, P.O. Box 15905 Jeddah 21454, Saudi Arabia Received 19 September 2007; received in revised form 26 December 2007; accepted 31 December 2007
Abstract
The [4/3] Pade approximant for the derivative is modified so that the resulting expression has the required asymptotic behavior. This gives an analytical result which represents the solution of the classical Blasius problem on the whole domain.
Ó2008 Elsevier B.V. All rights reserved.
PACS: 47.15.Cb; 02.30.Mv
Keywords: Viscous flow; Blasius problem; Analytical solution; Pade approximation
1. Introduction
The two dimensional steady state laminar viscous flow over a semi-infinite flat plate is modeled by the non- linear two-point boundary valueBlasius problem
f000ðgÞ þ1
2fðgÞf000ðgÞ ¼0; gP0 ð1:1aÞ
fð0Þ ¼0; f0ð0Þ ¼0; f0ð1Þ ¼1 ð1:1bÞ
wheregandfðgÞare, respectively, the dimensionless coordinate and the dimensionless stream function. Bla- sius[1]found the following analytic solution for the problem
fðgÞ ¼X1
k¼0
1 2 k
Akrkþ1
ð3kþ2Þ!g3kþ2; ð1:2Þ
whereA0¼A1¼1 and
1007-5704/$ - see front matterÓ2008 Elsevier B.V. All rights reserved.
doi:10.1016/j.cnsns.2007.12.010
* Corresponding author. Tel.: +92 3455334211.
E-mail address:[email protected](F. Ahmad).
Available online at www.sciencedirect.com
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Ak ¼Xk1
r¼0
3k1 3r
ArAkr1; kP2: ð1:3Þ
In(1.2)rdenotes the unknown f00ð0Þ:In spite of the presence ofð3kþ2Þ!in the denominator, the above series converges only within a finite interval½0;g0whereg01:8894r , thus making it impossible to use(1.2)to findrby applying the last condition in(1.1b)for a largeg. Howarth[2]solved the Blasius problem numerically and foundr0:33206:Asaithambi [3]found this number correct to nine decimal positions as 0.332057336.
Although the Blasius problem is almost a century old, it is still a topic of active current research[4–11].
The series(1.2)fails to converge outside a finite interval. This difficulty is inherent in several physical prob- lems governed by a nonlinear differential equation in that although a solution exists over an unbounded domain, but a power series representation of the solution converges only within a finite interval. For such problems finding an analyticalsolution which is uniformly valid over the whole domain is of fundamental interest. For the Blasius problem such a solution did not exist until 1999, when Liao, in a land mark paper, published a solution by using the homotopy analysis method[5]. His 35th order solution differs from How- ath’s numerical solution[2], forgP5, only in the fourth decimal position. However, Liao’s solution contains a large number of terms so that an explicit expression for the 35th order solution will require several pages to write upon.
In this short note, we derive ashortanalytical expression for the derivative of the solution. The idea is to form a hybrid expression which takes care off0ðgÞnot only for smallgbut also whenggrows very large. The
½4=3Pade approximant forf0ðgÞis slightly modified to the effect that the resulting expression represents the function on the entire domain½0;1Þwith remarkable accuracy. The actual solution is found by a simple quad- rature. A comparison with the numerical results shows that our solution gives accurate results over the entire domain. For largegour expression yields results in agreement with the numerical up to four decimal positions.
We remark that whereas Liao’s solution is completely analytical, ours is partly numerical in that we make no attempt toevaluater, but use its value as found numerically in[2,3]or analytically by Liao[5]or Ahmad [8]. Also we use the numerical resultfð7Þ ¼5:27924. Our emphasis is on finding a simple expression capable of producing accurate results over the entire domain½0;1Þ.
2. Uniformly valid analytic solution
We start with the analytical solution(1.2)with four terms fðgÞ ¼rg2
2 r2g5
240þ 11r3g8
161;280 5r4g11
4;257;792þ ð2:1Þ
On differentiation, we get f0ðgÞ ¼rgr2g4
48 þ11r3g7
20;160 5r4g10
387;072þ ð2:2Þ
We shall use a Pade approximant to represent the above expression[12]. A Pade [4/3] approximant of(2.2) gives
f0ðgÞ ’rgþ5603 r2g4
1þ42011rg3 ð2:3Þ
In the above expression letr¼0:332057 and modify it by addingag5expðg421Þto the numerator as well as the denominator. Denote the new expression bygðgÞ.
We get
gðgÞ ¼0:332057gþ0:00059069g4þag5expðg421Þ
1þ0:00869674g3þag5expðg421Þ ð2:4Þ
The above step is motivated by the idea that the functiongwill representf0with fair amount of accuracy for smallg and g will quickly approach unity as g becomes large. The parameter a is to be chosen in such a
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manner that we get close agreement in sofar as possible in the transition from small g to large g. Also the choice of the exponential function is dictated by the following heuristic argument. Eq. (1.1a)can be written in the form
f000ðgÞ f00ðgÞ ¼ 1
2fðgÞ
An integration from 0 tog gives f00ðgÞ ¼rexp 1
2 Z g
0
fðuÞdu
ð2:5Þ For large u, f0ðuÞ !1, therefore, as an approximation we choose fðuÞ ¼u in (2.5) which gives f00ðgÞ rexpð12g2Þ:An integration fromg to1will give
1f0ðgÞ r Z 1
g
e12u2du ð2:6Þ
If we express the right side in the form of an asymptotic series and keep only the first term, we obtain f0ðgÞ 1þrexpð12g2Þ
g ð2:7Þ
An inspection of(2.4)shows that, for largeg,gðgÞ ¼f0ðgÞbehaves as required by(2.7).
If we chooseaso thatRb
0gðgÞdgis close to the value of the exact solution atbsuch thatgðbÞ 1, the inte- gral will continue to be close to the exact solution in ½b;1Þ. We arbitrarily selectb¼7 and find that with a¼2:88106
Table 1
Comparison of analytical and numerical results
g Approximate solution Numerical solution
0 0 0
0.4 0.0266 0.0266
0.8 0.1061 0.1061
1.2 0.2379 0.2379
1.6 0.4203 0.4203
2.0 0.6500 0.6500
2.4 0.9223 0.9223
2.8 1.2311 1.2310
3.2 1.5693 1.5691
3.6 1.9297 1.9295
4.0 2.3058 2.3057
4.4 2.6922 2.6924
4.6 2.8879 2.8882
4.8 3.0848 3.0853
5.0 3.2827 3.2833
5.2 3.4813 3.4819
5.4 3.6805 3.6809
5.6 3.8799 3.8803
5.8 4.0796 4.0799
6.0 4.2794 4.2796
6.4 4.6793 4.6794
6.8 5.0792 5.0793
7.0 5.2792 5.2792
7.4 5.6792 5.6792
8.0 6.2792 6.2792
10 8.2792 8.2792
20 18.2792 18.2792
100 98.2792 98.2792
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Z 7 0
gðgÞdg¼5:27923
while the exact value of the solution, found numerically, is 5.27924. We substitute the above value ofain(2.4) and expect that the resulting expression will provide an approximate analytical expression for the derivative of the solution on theentiredomain½0;1Þ. A comparison of the analytical results with the numerical inTable 1 justifies this expectation.
Witha¼2:88106;gðgÞbecomes
gðgÞ ¼0:332057gþ0:00059069g4þ0:00000288g5expðg421Þ
1þ0:00869674g3þ0:00000288g5expðg421Þ : ð2:8Þ
InTable 1, we compare the approximate resultsRg
0 gðuÞduwith the ones obtained by a numerical solution of the Blasius problem. We observe that the two results match to four decimal positions for 06g62:8:In the transition stage2:86g67:0 the two results agree to three decimal positions and even in this interval the max- imum error is less than two parts in ten thousand. ForgP7:0 the two results again match to four decimal positions. In view of this, we can claim that the functionRg
0gðuÞdurepresents the solution of the Blasius prob- lem on thewhole domain½0;1Þwith maximum error less than one part in five thousand.
Acknowledgement
Part of this work was done while the first author was at the King Abdulaziz University. He wishes to thank the University for its hospitality.
References
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