• Tidak ada hasil yang ditemukan

General Physics 1 (Phys 110 : Mechanics)

N/A
N/A
Protected

Academic year: 2025

Membagikan "General Physics 1 (Phys 110 : Mechanics)"

Copied!
12
0
0

Teks penuh

(1)

General Physics 1

(Phys 110 : Mechanics)

CHAPTER 4

Motion in 2D and 3D

(2)

Phys 110

1. Position vector (𝒓):

Chapter 4 : Motion in 2D and 3D

Revision :

Lesson 5 of 5 Slide 1

𝒓 𝒕 = 𝒙 𝒕 π’Š + π’š 𝒕 𝒋 + 𝒛(𝒕)π’Œ

Particle’s motion in

2D

Position vector 1

Position vector 2

2. Displacement vector (βˆ†π’“):

(3)

Phys 110

3. Average Velocity (π’—π’‚π’—π’ˆ):

Chapter 4 : Motion in 2D and 3D

Revision :

Lesson 5 of 5 Slide 2

4. Instantaneous Velocity (Velocity) (𝒗):

direction of π’—π’‚π’—π’ˆ = direction of βˆ†π’“

direction of 𝒗 : along the tangent to path

(4)

Phys 110

5. Average Acceleration (π’‚π’‚π’—π’ˆ):

Chapter 4 : Motion in 2D and 3D

Revision :

Lesson 5 of 5 Slide 3

6. Instantaneous Acceleration (Acceleration) (𝒂):

direction of 𝒂 : not related to path

(5)

Phys 110

The horizontal Range:

The maximum height:

Chapter 4 : Motion in 2D and 3D

Revision :

Lesson 5 of 5 Slide 4

The Equation of path:

Vertical Motion (y-axis)

Horizontal Motion (x-axis)

Substitute:

𝒙 β†’ π’š

𝒂 β†’ π’‚π’š β†’ (βˆ’π’ˆ) 𝒗𝒐 β†’ π’—π’π’š β†’ π’—π’π’”π’Šπ’πœ½π’

𝒗 β†’ π’—π’š 𝑣π‘₯ = π‘£π‘œπ‘₯ π‘₯ βˆ’ π‘₯π‘œ = π‘£π‘œπ‘₯𝑑 π‘£π‘œπ‘₯ = π‘£π‘œπ‘π‘œπ‘ πœƒπ‘œ

7. Projectile Motion:

(6)

Phys 110

1. to define the uniform circular motion.

2. to identify the particle's velocity in the uniform circular motion.

3. to define the centripetal acceleration in magnitude and direction for a particle in uniform circular motion.

4. to calculate the time of revolution (period) for a particle in uniform circular motion.

5. to calculate the distance that the particle travels during one period in circular motion.

6. to determine the velocity and acceleration vectors in a

circular path in which the center at the origin of xy-plane.

Chapter 4 : Motion in 2D and 3D

Objectives covered in this lesson :

Lesson 5 of 5 Slide 5

Motion in 2D and 3D:

Uniform Circular Motion

(7)

Phys 110

Lesson 5 of 5 Slide 6

Chapter 4 : Motion in 2D and 3D

4-7 Uniform Circular Motion :

Circumference of circle = 2πœ‹π‘Ÿ

Period: is the time for a particle to go around a closed path exactly once.

(8)

In this motion:

Velocity’s:

magnitude (speed) = constant (does not change).

direction: changes but is always tangent to the circle in the direction of motion.

Acceleration’s:

magnitude = constant (but not zero).

direction: changes but is always directed towards the center of the circle.

centripetal acceleration = always directed radially inwards.

Phys 110

Lesson 5 of 5 Slide 7

Chapter 4 : Motion in 2D and 3D

4-7 Uniform Circular Motion :

(9)

Phys 110

Lesson 5 of 5 Slide 8

Chapter 4 : Motion in 2D and 3D

Answer: (a) βˆ’4 m/s 𝑖 , (b) βˆ’8 m/𝑠2 𝑗

4-7 Uniform Circular Motion :

(10)

Phys 110

Lesson 5 of 5 Slide 9

Chapter 4 : Motion in 2D and 3D

Sample Problem (4-10) :

(11)

Phys 110

Lesson 5 of 5 Slide 10

Chapter 4 : Motion in 2D and 3D

Sample Problem (4-10) :

(12)

Motion in 2D and 3D:

Uniform Circular Motion.

Phys 110

Lesson 5 of 5 Slide 11 (last)

Summary:

Any Questions?

Next lesson we will start Chapter 5 and will cover:

Section (5-1).

Section (5-2).

Section (5-3).

Section (5-4) without the β€œinertial reference frames”.

Section (5-5).

Section (5-6).

Chapter 4 : Motion in 2D and 3D

Referensi

Dokumen terkait