This shows that the variable v in the wave equation actually represents the speed of the wave. A represents the maximum value of the wave and is called the amplitude of the wave.
13 SOUND WAVES
If the displacement of the molecules varies as a function of position and time according to the equation. The speed of sound is proportional to the mass modulus of the medium through which sound travels.
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A car producing sound with a frequency of 1500 Hz approaches a stationary man with a speed of 35 m/s on a day when the temperature is 25°C. Download free ebooks at bookboon.com Click on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read moreClick on the ad to read more.
14 SUPERPOSITION
INTERFERENCE) OF WAVES AND STANDING WAVES
Wave Reflected from a Denser Medium
Since the speed of a wave depends only on the properties of the medium, the frequencies that can exist as a standing wave are also limited and the frequencies of the standing waves are given as n. Therefore, this is a standing wave with a node at one end and an antinode at the other end. An example of this is sound resonance in a tube that is closed at one end and open at the other.
It will have an antinode at the open end and a node at the closed end.
Wave Reflected from a less Dense Medium
Click the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick click the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read more. Download free eBooks at bookboon.com. a) Calculate the two possible frequencies of the unknown wave. The frequency of a beat is equal to the difference between the frequencies of the interfering waves.
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15 ELECTROMAGNETIC WAVE
Since the rectangle is small, the electric field can be assumed to be constant on the vertical paths (E(x)) on the left and E x dx. The line integrals of the magnetic field on the paths parallel to the x-axis are zero because the magnetic field is perpendicular to the paths. On the paths parallel to the y-axis, the magnetic field can be assumed to be approximately constant (B x on the left side and B x dx on the right side), because the rectangle is infinitely small.
Therefore, the line integral of the magnetic field on the closed path is given as.
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The ratio between these two equations shows that the ratio between the fields is equal to the ratio between their amplitudes. Download free ebooks at bookboon.com Click on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read more moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read moreClick on ad to read more.
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Click the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick click the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read moreClick the ad to read more. The energy density of an electromagnetic wave is the sum of the energy densities due to the electric field and the magnetic field. Therefore, the magnitude of the point vector is equal to the product of the speed of light and the electromagnetic energy density.
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For a certain harmonic electromagnetic wave with a frequency of 6.4e15 Hz, the amplitude of the electric field is 1.4e-3 N ⁄ C. For a certain harmonic electromagnetic wave with a frequency of 8.2e15 Hz, the amplitude of the electric field is 7.4e-3 N ⁄ C. Calculate the average the amount of electromagnetic energy that crosses a unit of rectangular area per unit of time.
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16 LIGHT AND OPTICS
Solution: Since the angle of incidence at the first mirror is 70°, the angle of reflection at the first mirror is 70°. The angle of refraction in water and the angle of incidence at the water-glass interface are equal because they are alternate interior angles. The angle of incidence for light rays falling on the boundary of this circular region is equal to the critical angle of the boundary.
As the light beam is incident on the denser medium (glass), what happens depends on the critical angle of the boundary.
17 MIRRORS AND LENSES
The image is between the focus and the center of curvature on the same side as the object. The image is off the center of curvature on the same side as the object. The image is further than twice the focal length on the other side of the lens.
All the other choices are not correct. the image is formed on the same side as the object.
18 WAVE PROPERTIES OF LIGHT
The experiment shows that bright (constructive interference) and dark (destructive interference) spots alternate on the screen. The graph on the screen is a representation of the light intensity observed on the screen. The interference pattern seen on the screen depends on the path difference between the two waves.
If the perpendicular distance between the source and the screen is 0.05 m, calculate the distance between the zero-order bright spot and the second-order bright spot on the screen.
ANSWERS TO PRACTICE QUIZZES
