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Second Derivatives Belong to Lp (A,B) and Applications

This is the Published version of the following publication

Cerone, Pietro, Dragomir, Sever S and Roumeliotis, John (1998) An Ostrowski Type Inequality for Mappings whose Second Derivatives Belong to Lp (A,B) and Applications. RGMIA research report collection, 1 (1).

The publisher’s official version can be found at

Note that access to this version may require subscription.

Downloaded from VU Research Repository https://vuir.vu.edu.au/17108/

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RGMIA Research Report Collection, Vol. 1, No. 1, 1998

http://sci.vut.edu.au/ rgmia/reports.html

AN OSTROWSKI TYPE INEQUALITY FOR

MAPPINGS WHOSE SECOND DERIVATIVES

BELONG TO L

P

(AB) AND APPLICATIONS

P. CERONE, S.S. DRAGOMIR AND J. ROUMELIOTIS

Abstract. An inequality of the Ostrowski type for twice dierentiable map- pings whose derivatives belong toLp(ab) (p>1) and applications in Numerical Integration are investigated.

1 Introduction

The following inequality is well known in the literature as Ostrowski's integral inequality (see for example 1, p. 468])

Theorem 1.1.

Letf :I

R

!

R

be a dierentiable mapping onI(Iis the interior of I) and let ab 2 I with a< b:If f0 : (ab)!

R

is bounded, i.e.,

kf 0

k

1:= sup

t2(ab)jf

0(t)j<1 then we have the inequality:

f(x); 1

b;a b

Z

a

f(t)dt

"

14 +

;

x; a+2b

2

(b;a)2

#

(b;a)kf0k1 (1.1)

for allx2(ab):

The constant 14 is the best possible.

For a simple proof and some applications of Ostrowski's inequality to some special means and some numerical quadrature rules, we refer the reader to the recent paper 2] by S.S. Dragomir and A. Wang.

In 3], the same authors considered another inequality of Ostrowski type for

kk

p

;norm (p>1) as follows:

Theorem 1.2.

Let f : I

R

!

R

be a dierentiable mapping on I and

ab 2I

with a < b. If f0 2Lp(ab) p>11p +1q = 1 then we have the inequality:

f(x); 1

b;a b

Z

a

f(t)dt 1

b;a

"

(x;a)q+1+ (b;x)q+1

q+ 1

#1

q

kf 0

k

(1.2) p

Date.November, 1998

1991 Mathematics Subject Classication. Primary 26D15 Secondary 41A55.

Key words and phrases.Ostrowski's Inequality, Numerical Integration.

43

(3)

for allx2ab], where

kf 0

k

p :=

0

@ b

Z

a

jf(t)jpdt

1

A 1

p

is the Lp(ab);norm.

They also pointed out some applications of (1:2) in Numerical Integration as well as for special means.

In 1976, G.V. Milovanovic and J.E. Pecaric proved a generalization of Os- trowski inequality for n;times dierentiable mappings (see for example 1, p.

468]). The case of twice dierentiable mappings 1, p. 470] is as follows:

Theorem 1.3.

Let f : ab]!

R

be a twice dierentiable mapping such that

f

00 : (ab)!

R

is bounded on (ab) i.e., kf00k1 := sup

t2(ab)jf

00(t)j <1: Then we have the inequality:

12

f(x) + (x;a)f(a) + (b;x)f(b)

b;a

;

1

b;a b

Z

a

f(t)dt (1.3)

kf

00

k

4 (1 b;a)2

2

4 1 12 +

x; a+2b2

(b;a)2

3

5

for allx2ab]:

In this paper, we point out an inequality of Ostrowski type for twice dier- entiable mappings which is in terms of thekkp-norm of the second derivative

f

00 and apply it in Numerical Integration.

2 Some Integral Inequalities

The following inequality of Ostrowski type for mappings which are twice dier- entiable, holds:

Theorem 2.1.

Letf : ab]!

R

be a twice dierentiable mapping on(ab) and

f 00

2L

p(ab) (p>1):Then we have the inequality:

f(x); 1

b;a b

Z

a

f(t)dt;

x; a+b

2

f 0(x) (2.1)

2(b;a)(21 q+ 1)1q

h(x;a)2q+1+ (b;x)2q+1i1qkf00kp

(b;a)1+1qkf00kp 2(2q+ 1)1q for allx2ab]where 1p +1q = 1:

(4)

Ostrowski for Bounded Second Derivative Mappings in Lp(ab) 45

Proof. Let us dene the mappingK() : ab]2!

R

given by

K(xt) :=

8

>

>

>

<

>

>

>

:

(t;a)2

2 ift2ax] (t;b)2

2 ift2(xb]

:

Integrating by parts, we have successively,

b

Z

a

K(xt)f00(t)dt=

x

Z

a

(t;a)2

2 f00(t)dt+

b

Z

x

(t;b)2

2 f00(t)dt

= (t;a)2 2 f0(t)

x

a

; x

Z

a

(t;a)f0(t)dt+ (t;b)2 2 f0(t)

b

x

; b

Z

x

(t;b)f0(t)dt

= (x;a)2

2 f0(x);

2

4(t;a)f(t)jxa;

x

Z

a

f(t)dt

3

5

;

(b;x)2

2 f0(x);

2

4(t;b)f(t)jbx;

b

Z

x

f(t)dt

3

5

= 12h(x;a)2;(b;x)2if0(x)

;(x;a)f(x) +

x

Z

a

f(t)dt+ (x;b)f(x) +

b

Z

x

f(t)dt

= (b;a)

x; a+b

2

f

0(x);(b;a)f(x) +

b

Z

a

f(t)dt from which we get the integral identity

b

Z

a

f(t)dt= (b;a)f(x);(b;a)

x; a+b

2

f 0(x) +

b

Z

a

K(xt)f00(t)dt (2.2)

for allx2ab]:

RGMIA Research Report Collection, Vol. 1, No. 1, 1998

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Using (2:2), we have, by Holder's integral inequality, that

f(x); 1

b;a b

Z

a

f(t)dt;

x; a+b

2

f 0(x) (2.3)

= 1

b;a b

Z

a

K(xt)f00(t)dt 1

b;a 0

@ b

Z

a K

q(xt)dt

1

A 1

q

kf 00

k

p

= 1

b;a 2

4 x

Z

a

(t;a)2q 2q dt+

b

Z

x

(t;b)2q 2q dt

3

5 1

q

kf 00

k

p

= 1

b;a

"

(x;a)2q+1

2q(2q+ 1) +(b;x)2q+1 2q(2q+ 1)

#1

q

kf 00

k

p

= 1

2(b;a) 1 (2q+ 1)q1

h(x;a)2q+1+ (b;x)2q+1i1qkf00kp

and the rst inequality in (2:1) is proved. The second inequality is obvious taking into account that

(x;a)2q+1+ (b;x)2q+1(b;a)2q+1 for allx2ab]:

The following particular case for euclidean norms is interesting

Corollary 2.2.

Letf : ab]!

R

be as above andf002L2(ab):Then we have the inequality:

f(x); 1

b;a b

Z

a

f(t)dt;

x; a+b

2

f 0(x) (2.4)

(b;a)32 2

"

80 +1 1 2

;

x; a+2b

2

(b;a)2 +

;

x; a+2b

4

(b;a)4

# 1

2

kf 00

k2:

Proof. Apply inequality (2:1) for p=q= 2to get

f(x); 1

b;a b

Z

a

f(t)dt;

x; a+b

2

f 0(x) (2.5)

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Ostrowski for Bounded Second Derivative Mappings in Lp(ab) 47

2(b;1a)p5

h(x;a)5+ (b;x)5i12kf00k2: Denote t:=x;a+2b:Then

x;a=t+b;2ab;x= b;2a;t:

Let us compute

I := (x;a)5+ (b;x)5=

t+b;2a

5

+

b;a

2 ;t

5

:

We know that, for numbersAB2

R

,we have

A

5+B5= (A+B);A4;A3B+A2B2;AB3+B4

= (A+B)A4+B4;AB;A2+B2+A2B2

= (A+B)h;A2+B22;A2B2;AB;A2+B2i: Now, if we put A:=t+b;a2 B:= b;a2 ;tthen we get

A2+B2= 2t2+ (b;a)2

2 AB= (b;a)2 4 ;t2 and then

J :=;A2+B22;A2B2;AB;A2+B2

=

"

2t2+ (b;a)2 2

#2

;

"

t2;

(b;a)2 4

#2

;

"

(b;a)2 4 ;t2

#"

2t2+ (b;a)2 2

#

= 5t4+ 52 (b;a)2t2+ (b;a)4 16 = 5

"

t4+ 2

b;a

2

2

t2+ 15

b;a

2

4#

:

Consequently,

I = (b;a)

"

5

x; a+b

2

4

+ 52 (b;a)2

x; a+b

2

2

+ (b;a)4 16

#

= 5(b;a)5

"

80 +1 1 2

;

x; a+2b

2

(b;a)2 +

;

x; a+2b

4

(b;a)4

#

:

Finally, using the inequality (2:5), we get the desired result (2:4)

Remark 2.1.

Let f : ab]!

R

be as above . Then we have the midpoint inequality:

f

a+b 2

;

1

b;a b

Z

a

f(t)dt 1

8(2q+ 1)1q (b;a)1+1qkf00kp: (2.6)

RGMIA Research Report Collection, Vol. 1, No. 1, 1998

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Taking into account the fact that the mapping

h: ab]!

R

h(x) = (x;a)2q+1+ (b;x)2q+1 has the property that

inf

x2ab]h(x) =h

a+b 2

= (b;a)2q+1 22q and

sup

x2ab]h(x) =h(a) =h(b) = (b;a)2q+1

then, the best estimation we can get from (2:1) is that one for whichx= a+2b obtaining the inequality (2:6):

Remark 2.2.

If in(2:1) we choose x=awe get

f(a); 1

b;a b

Z

a

f(t)dt+b;2af0(a) (b;a)1+1q 2(2q+ 1)1q kf

00

k

p

and puttingx=bwe also get

f(b); 1

b;a b

Z

a

f(t)dt;b;2af0(b) (b;a)1+1q 2(2q+ 1)1q kf

00

k

p :

Summing the above two inequalities, using the triangle inequality and dividing by 2, we get the perturbed trapezoid formula

f(a) +f(b)

2 ;

b;a

4 (f0(b);f0(a)); 1

b;a b

Z

a

f(t)dt (b;a)1+1q 2(2q+ 1)1q kf

00

k

p :

(2.7)

Remark 2.3.

Ifp=q= 2, then we get for the euclidean norm, from (2:6)

f

a+b 2

;

1

b;a b

Z

a

f(t)dt

p5(b;a)32 40 kf00k2 (2.8)

and, from(2:7)

f(a) +f(b)

2 ;b;4 (a f0(b);f0(a)); 1

b;a b

Z

a

f(t)dt (2.9)

p5(b;a)32

10 kf00k2:

(8)

Ostrowski for Bounded Second Derivative Mappings in Lp(ab) 49

3 Applications in Numerical Integration

Let In : a = x0 < x1 < ::: < xn;1 < xn = b be a division of the interval,

i

2xixi+1] (i= 0:::n;1):We have the following quadrature formula:

Theorem 3.1.

Let f : ab]!

R

be a twice dierentiable mapping on (ab) whose second derivativef00: (ab)!

R

belongs toLp(ab) (p>1) i.e.,

kf 00

k

p:=

0

@ b

Z

a jf

00(t)pjdt

1

A 1

p

<1:

Then the following perturbed Riemann type quadrature formula holds:

b

Z

a

f(x)dx=A(ff0 In) +R(ff0 In) (3.1)

whereA(ff0 In) is given by

A(ff0 In) :=n;X1

i=0

h

i

f(i);n;X1

i=0

f 0(i)

i

; x

i+xi+1

2

h

i

and the remainder satises the estimation:

jR(ff0 In)j (3.2)

2(2q1+ 1)1q

n;X1

i=0(i;xi)2q+1+ (xi+1;i)2q+1

! 1

q

kf 00

k

p

2(2q+ 1)1 1=q

n;X1

i=0

h

2q+1

i

! 1

q

kf 00

k

p

for alli 2xixi+1] (i= 0:::n;1):

Proof. Apply inequality (2:1) on the interval xixi+1] (i= 0:::n;1) to get

f(i)hi;

x

i+1

Z

xi

f(t)dt;

i

; x

i+xi+1

2

f 0(i)hi

2(2q+ 1)1 1=q

h(i;xi)2q+1+ (xi+1;i)2q+1i1q

0

@ x

i+1

Z

xi jf

00(t)jpdt

1

A 1

p

for alli2f0:::n;1g:

RGMIA Research Report Collection, Vol. 1, No. 1, 1998

(9)

Summing over i from 0 to n;1 using the generalized triangle inequality and Holder's discrete inequality, we get:

jR(ff0 In)j

n;X1

i=0

f(i)hi;

i

; x

i+xi+1

2

f

0(i)hi;

xi+1

Z

x

i

f(t)dt

2(2q+ 1)1 1=q

n;X1

i=0

h(i;xi)2q+1+ (xi+1;i)2q+1i1q

0

@ xi+1

Z

xi jf

00(t)jpdt

1

A 1

p

2(2q+ 1)1 1=q

n;1

X

i=0

h(i;xi)2q+1+ (xi+1;i)2q+1i1q

q

! 1

q

0

B

@ n;1

X

i=0

0

B

@ 0

@ x

i+1

Z

xi jf

00(t)jpdt

1

A 1

p 1

C

A p

1

C

A 1

p

= 1

2(2q+ 1)1=q

n;X1

i=0

h(i;xi)2q+1+ (xi+1;i)2q+1i

! 1

q

kf 00

k

p

and the rst inequality in (3:2) is proved.

The last part is obvious from the fact that

(i;xi)2q+1+ (xi+1;i)2q+1h2iq+1 for alli2f0:::n;1g:

Now, if we consider the midpoint formula

M(fIn) :=n;X1

i=0

f

x

i+xi+1

2

h

i

then we have

b

Z

a

f(t)dt=M(fIn) +R(fIn) (3.3)

and the remainderR(fIn) can be estimated in terms of thep;norm of f00as follows:

jR(fIn)j 1 8(2q+ 1)1=q

n;1

X

i=0

h

2q+1

i

! 1

q

kf 00

k

(3.4) p

(10)

Ostrowski for Bounded Second Derivative Mappings in Lp(ab) 51

which is, in a certain sense, the best estimation we can obtain from (3:2): Also, we can construct the following perturbed trapezoid formula

T

p(ff0In) := 12n;Xi=01

f(xi) +f(xi+1)

2 hi+ 14n;Xi=01

h2

i(f0(xi);f0(xi+1)): Then we have

b

Z

a

f(t)dt=Tp(ff0In) +Rp(ff0In) (3.5)

and the remainder can be estimated (see the inequality (2:7) ) as follows:

jR

p(ff0In)j 1 2(2q+ 1)1=q

n;1

X

i=0

h

2q+1

i

! 1

q

kf 00

k

p

(3.6) :

Remark 3.1.

To derive the corresponding results for the euclidean normkf00k2, we put in the above p=q= 2:

We omit the details.

Remark 3.2.

The reader can obtain the corresponding quadrature formulae for equidistant partitioning by choosingxi=a+ib;an (i= 0:::n;1):

Remark 3.3.

If we consider equidistant partitioning ofab] then the perturbed trapezoid formula we considered above will involve the calculation forf0 only at the endpoints aandb , which is a good advantage for practical applications.

RGMIA Research Report Collection, Vol. 1, No. 1, 1998

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References

1] D.S. MITRINOVIC, J.E. PECARIC and A.M. FINK, Inequalities for Func- tions and Their Integrals and Derivatives, Kluwer Academic, Dordrecht, 1994.

2] S.S. DRAGOMIR and S. WANG, Applications of Ostrowski's inequality to the estimation of error bounds for some special means and some numerical quadrature rules, Appl. Math. Lett.,

11

(1998), 105-109.

3] S.S. DRAGOMIR and S. WANG A new inequality of Ostrowski's type in

L

p

;norm, submitted.

School of Communications and Informatics, Victoria University of Technology, PO Box 14428, Melbourne City MC, Victoria 8001, Australia.

E-mail address: fpc, sever, johnrg@matilda.vut.edu.au

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