STANDARD IDEALS AND HOMOMORPHISM KERNEL OF A LATTICE Md. Abul Kalam Azad1, Md. Mizanur Rahman2 and Md. Zaidur Rahman1
1 Department of Mathematics, Khulna University of Engineering & Technology
2 Department of Mathematics, Rajshahi Govt. City College, Rajshahi
Received: 20 November 2010 Accepted: 15 December 2010 ABSTRACT
A meet semilattice together with the property that any two elements possessing a common upper bound have a suprimum. Standard ideal had extended to convex sub lattice by [7] & [11]. Here we generalize the characterization of standard ideals and also generalize the standard ideals, Homomorphism kernels and Isomorphism theorems. For any two lattice L1 and L2, a map :L1L2 is called an isotone, if for any
L y
x, , with xy implies
x y . Also the above mapping is called a meet homomorphism if for all,
x y
x y . Therefore meet homomorphism is an isotone. And since is isotone.
x
y x y
. Therefore
x
y exist by upper bound property of L2 [2] & [3] have characterize those lattice whose all congruence are standard and neutral. Here we generalize characterization of this lattice whose all congruence are standard.1. INTRODUCTION
This Paper studies extensively standard ideal and homomorphism kernels. The idea of standard ideals in lattice was first introduced by [8], [10]. It had extended the ideal to convex sub lattices and proved many result on homomorphism by [7], [11] also [4] and [5].
A congruence of a lattice L is called standard if s for some standard ideal S of L. For any two lattice L1and L2, a map :L1L2 is called an isotone if for any x,yL, with xy implies
x y , also the above mapping is called a meet homomorphism if for all x,yL1,
xy
x y . Therefore meet homomorphism is an isotone. And since is an isotone.
x y xy
. Therefore
x y exsit by upper bound property of L2.Latif in his thesis have introduce the concept of standard n-ideals of a lattice. We conclude this paper with some more properties of standard and neutral ideals. We also extended the result of Cornish and A.S.A Noor [1] , we also show that If I is an arbitrary ideal and S is standard ideal then IS and IS are principal, then I itself principal.
Secondly we have discussed Homomorphism, kernel and stadard ideals. Gratzer and Schmitd in [8] were translate several thorem of Group theory to lattice theory. Here we have generalized so of their result, we have shown that if S is a standard ideal of a lattice L, then s the extension of
S to I
L and
S is the restriction of S to the lattice L. Then we have shown that in a sectionally complemented lattice all congruences are standard. We also show that in a relatively complemented lattice L with 0, if every standard ideal of L is generated by a finite number of standard elements, then the congruence lattice C
L is Boolean.Finally we have generalized two results of [2] and [3] regarding lattices all of whose congruence are standard.
We know that the set of all standard ideals of a lattice L is a sub lattice of I
L . Also the congruence S where S is standard form a sub lattice of
I
L
, and SS is an isomorphism. Suppose is a congruence relation of L. defines in the natural way a homomorphism of I
L under which I J
I,JI
L
if and only if to any xI there exists a,bJ such that x y
and conversely. We call this congruence relation the extension of to I
L .On the otherhand any congruence relation of I
L induces a congruenc relation of L under which xy if and only if
x
y
. This is called the restriction of to L.Thirdly in [8] Gratzer and Schmidt have proved Isomorphism theorem for standard ideal in lattices. In their paper they have translated several theorems of group theory to lattice theory using ideal, standard ideal, factor group and group operation. Here we generalze isomorphism theorem.
an International Journal
* Corresponding author: [email protected] KUET@JES, ISSN 2075-4914/01(2), 2010
We refer the reader to [3] [4] [5] [6] for a necessary background on this paper.
Theorem 1.1: Let S be an ideal in a lattice L. Then the following conditions are equivalent.
(i) S is a standard ideal.
(ii) The binary relation S , defined by xy S if and only if
x
x y
xa
y
x y
yb
for some a,bS is a congruence relation.iii) The binary relation defined by xy
, if and only if for all tL,
xt
tc
yt
tc
for some cS is a congruence .
iv) For each ideal K,
S K s k
: sk exists, and sS and kK. Moreover, (ii) and (iii) represent the same congruence, viz.
S , the smallest congruence of L having S as congruence class.Proof:
(i) implies (ii). If (i) holds, then the relation JK
S
J,KI
L
if and only if J
JK
JS
and K
JK
KS
is a congruence on I
L .Then S/L restriction to L is a congruence on L and x y
S /L if and only if
x x y
xS
and
y
xy
y
S
. Thus to prove (ii), it is sufficient to prove that
x
xy
x
S
implies
x y
x a
x for some aS. This is proved by induction. By the property of the supremum of two ideals,
0
x Ln
S x y
x Where L0
xy
x
S
and Ln
tL:t pq;pq exists and1
,qAn
p for n=1,2,...n. Indeed, we show by induction that
xy
x
S
t:t
x y
xa
for some aS
. If tL then t
x y
or t
x
S. In the first instance, t xy
xy
xs
for any sS and in the second instance
x y
x t
x t
t and tS. Thus the result holds for n0. Suppose the result hold for n-1 for some n1. Let tL, then tpq with p,qLn1 so p
xy
xs1
and
x y
x s2
q for some s1,s2S.
Then t
x y
xs1
xs2
xy
xs
.For some sS (Since
xs1
xs2
s and is in S, it is of the form
xs
for some sS. Thus, we have
xy
x
s
t:t
xy
xs
for some sS; in effect , x
xy
xa
for someS
a and so x
xy
xa
; as required.ii) Implies (iii) , Let xy
S
. Since
S is a congruence, xt yt
S
for any tL, and so
x y t
x t a
t
x and yt
xyt
xtb
for some a,bS.Then Observe that
ta
tb
S. Thus, x y
Conversely, if x y
then for any tL,
xt
tc
yt
tc
for some cS. Choosing xt and ty, we have x
xy
xc
and y
x y
yc
respectively.Thus xy
S
and is congruence
Siii) Implies (iv). Let T
sk:skexists and sS and kK
. Suppose xsk,sS,kK Clearly
S
k k
s and so xx
sk
xk
S
. Hence for all tL,
xt
tc
xkt
tc
for some cS. Choosing tx, we obtain
x k
x c
x and so xT . But T is closed under existent finite suprima. It follows that T is an ideal of L and T SK.
iv) Implies (i). Let x J
SK
. Then xJ and x
sk
. So xsk for suitable Ss and kK. Then, x
xs
xk
and so x
JS
JK
. The reverse inclusion is obvious. Thus J
SK
JS
JK
; S is a standard ideal. The last part is clear from the proof of (ii) implies (iii). Now we give another characterization of standard ideals of a lattice. This is a generalization of [8, Theorem 2] which is also a nice improvement of the theorem 1.1. Theorem 1.2: For an ideal S of a Lattice L, the following conditions are equivalent;
(i) S is a standard ideal.
ii) The equality I
SK
IS
IK
holds if I and K are principal ideals.(iii) If for the principal ideals I and J the inequality JSI holds , then J
IS
JI
iv) The relation
S of L defined by x y
S
if and only if x
xy
xa
, x y y b
y
for some a,bS is a congruence relation.Proof:
(i) Implies (ii) is obvious, from the definition of the standard ideal.
(ii) Implies (iii) is clear.
iii) Implies (iv). Obviously the relation is an equivalence relation. Let xy and x y
S then
y b
x
y for some bS. Suppose for some tL, ytexists. Then xt exists. Hence,
x t
y b
x t
y t
b
y t ty
thus yt
xt
yt
b
So xt yt
S
. Now, ytx
yb
x
S, So
yt
x
S.Then by (iii)
yt
xyt
Syt
, 0
xt
S
yt
. Then a similar proof of (i) imlies (ii) of Theorem.1.1 shows that yt
xt
yta
; for some aS.Thus
S is a congruence relation.(iv) implies (i) holds by theorem 1.1.
We conclude this section with the following result, which is a generalization of a well known result of lattice theory of [8, Lemma 8]
Theorem 1.3: Let I be an arbitrary and be a standard ideal of the lattice L. If IS and IS are principal, then I itself is principal.
Proof: Let IS
a
and I S
b
. Then by theorem 1.1 axs for some xI and sS. Since ab and xa so xb exists by the upper bound property of L.
We claim that I
xb
. Of course
xb
I. For the reverse inequality let tI . Since t,xba, so again by the upper bound property of L, wtxb exists and wL. Then
a
S
w
S
xb
S
x
a
i.e. S
w
S
xb
.Further,
b
SIS
w
S
xb
S
b
b
, and so S
w
S
xb
. This two equalities imply that
w
xb
as S is standard and so wxb
xb
. Since tw,t
xb
and hence I
xb
, this complete the proof. Theorem 1.4: Homomorphic image of relatively complemented lattice is relatively complemented.
Proof: :L1L2 be an onto homomorphism and suppose L1 is relatively complemented.
Let
x1,y1 be any interval in L2 since is onto homomorphism, images x and y for x1,y1 respectively such that (x) x1 and x y(ax1 y1).Thus
x,y is an interval in L1.Let b
x1,y1
x, y
be any element then as before a pre-image a of b. s, t
a b and .y a x
Now L1 relatively complemented implies that a has a complement a1 relative to
x1,y .i.e.
1 1 1
1
1 1
1 1
) ( , ) (
) ( ) ( ) ( ), ( ) ( ) (
,
y a b x a b
y a a x a a
y a a x a a
) (a1
is complement of b relative to
x1,y1 .Thus each element in any interval in L2 has complement, going us the required result.
Theorem 1.5: :L1L2 is an onto homomorphism where L1, L2 are lattices and 01 is least element of L2 then kernel is an ideal of L.
Proof: Since is onto, 01L2, thus ker as pre image of 01 exists in L1 . Now a,bker
(a)01 (b) (ab) (a) (b)0101 abker
Again aker , lL gives
a 01 Also (al)(a)(l)01l01 alker Hence ker is an ideal of L Theorem 1.6: Let S be the a standard ideal. Then , is the extension of S to I
L and S is the restriction of S to the lattice.Proof: Let
S be the extension of
S to I
L and I J
S
.We suppose IJ . Choosing a,yI . We can find an xI
yx
with x y
S and so there exists any
Sx with yx
ySxy
. The ideal S1 generated by the ySxy satisfies S1S and IS1J . Hence IJ
. On the other hand, if IJ
S then IS1J with a suitable S1S. Then for anyJ
y it follows that yIS and so for any yJ it follows that yI S and so
y s
x s x
y for some sS as S is standard.
Thus xy
S
[ theorem 1.1] and hence
S S.To prove the 2nd assertion, suppose
a
b
S . Then
a
a
b
S
ab
S and hence
a
ab
S1 for suitable S1S. Then a
ab
S and since S is standard [theorem 1.1].So a
ab
as1
for some s1S.Similarly, we can show that b
ab
bs2
for some s2S. Thus ab
S .Hence S is the restriction of S to L.
Theorem 1.7: Let L be a sectionally complemented lattice. Then every homomorphism kernel of L is a standard ideal and every standard ideal is the kernel of precisely one congruence- relation.
Proof: Suppose the ideal I of L is homomorphism kernel induced by the congruence relation . Let ab
, Lb
a, then aba
and 0aba. Since L is sectionally complemented, so there exits c; such that0
b c
a and
ab
ca. This implies 0
ab
cacc
. Since I is a homomorphism kernel, so cI. Moreover, a
ab
c
ab
ac
; similarly, we can show that
a b
a d
b for some d I. Therefore I is a standard ideal.
At the same time we have proved that if I is the kernel of the homomorphism induced by , then I
. Hence every standard ideal is the kernel of Precisely one congruence relation. Thus we have the following corollary;Corollary 1.8: In a sectionally complemented lattice all congruencies are standard.
We know, an ideal
s
is standard if and only if s is a standard element. Moreover, we can easily show that an ideal Generated by finite number of standard elements is standard.Theorem 1.9: Let L be a relatively complemented lattice with 0. If every standard ideal of L is generated by a finite number of standard elements, then C
L , the congruence lattice is Boolean. Moreover, the converse of this is not true.Proof: Let C
L with ww1 where w and w1 are the smallest and the largest congruence respectively. Since L is relatively complemented, So by above,
S for some standard ideal S. Then
0
SL.Since every standard ideal is generated by a finite number of standard elements , so there exist standard elements a1...am and b1...bn Such that S
a1...am
and L
b1...bn
. Then
0
a1...am
b1... ...bn
since
a1...am
b1...bn
at least one of b
a1...am
. Suppose b ,b ...bIr2
1 1
1 are the only elements
b1...bn
. such that they do not belong to
a1...am
. Then of course
a1...am
b1...bn
L set C1k
a1b1
k ...
am b1
k for each k,r k
1 , Then
IK K
I b
c
o and each
IK
c is standard . Since L is sectionally complemented, there exist
IK
d such that cIK dIK 0 and cIK dIK bIK. Since each diK is standard.
Now cI (a1...am]
K for each k.
Thus
aI...am
dII...dIr
c1I...cIr
dII...d1K
I
.........
...r
.
...I.... r
,r r I
I
I I I I
I I I
I
b b
b b
d c d
c
and so
A a a
b b
d d
a a
m I
I I
I I
m r I
r I
] ...
( ] ...
...
(
] ...
...
( ....
..
..
1.
Also, as each
a
1 is standard. So
aI...am
dIK
ai am
dIK
bIK
...
aI bIK ...... ambIK
dIK
,
aI bIK ambIK
dIK
...
0
. cIK dIK Then using the standardness of each ,
IK
d we have
aI......am
dI......dIK
0
Thus we obtain a standard ideal T
dI1...dIr
of Lsuch that
T is the complement of . Therefore C
L is Boolean.For the converse statement, consider the following lattice L Here it is easy to see that C
L is Boolean.
a d
L , , which is of course a standard ideal. But both a and d are not standard elements of L. [5] and [6] have characterized those Lattices whose all congruence are standard and neutral.
our following theorems give characterizations to those lattice whose all congruence are standard and neutral.
These are certainly generalizations of above authors work.
Theorem 1.10: Let L be a lattice. Then the following conditions are equivalent.
(i) All congruence of L are standard.
(ii) L has a zero and for x,yL there exists aL such that, a0
xy,x
.Proof: (i) implies (ii) since the smallest congruence w of L is standard .L must have a zero.
Let x,yL, then
xy,x
I , for some standard ideal I.i.e. x
xy
I , where I is standard , hence x
xy
xa
.for some aI Hence a0
xy,x
.(ii) implies (i). Let be a congruence and I
0. Suppose x y
. Then by (ii) there exists aL such that x
xy
xa
and a0
x y,x
. Since
xy,x
, so a0
and Hence aI . Similarly y
xy
yb
for some bI .Thus I is a standard ideal and
I , and so (i) holds. Theorem 1.11: Let L be a lattice. Then the following conditions are equivalent.
(i) All congruence of L are neutral.
(ii) L has a zero and satisfies the condition:
, ,
, ,
; ) (
)
(t y t z t x y z L
x implies existence of
a L
.Such that) , (
), (
) (
) (
)
(t a a t y a t z x y a o x y x
x
e
d
a b c
0
Figure 1.1
(iii) L has a zero and satisfies the condition
L z y x d t z t y
t
x ( ) ( ) ; , , , , implies the existence of
a L
suchthat x (t a) (t a y) (y ((t a) x)), a 0(x y, x).
Proof: (i) implies (ii) L must have a zero of w
0 . Let x (t y) (t z);t, x, y, z L .Then
x y,x
I for some neutral ideal I. since I is standard , by the above theorem there exists aI such thatx ( x y ) ( x a
I)
Now
x a
I ( t y ) ( t z ) , a
I I , ( x a
I] I ,
and
xa1
(ty)(tz)]. Hence
xa1
I
t y
tz
I
ty
I
tz
as I is neutral.Therefore xa1 pq, for somepI
ty
and qI
tz
.Thus pty, qtz and p,qI. Hence ppty and qqtz. Let pqa , then xa1a
pt y
qtz
at y
atz
a. Hence a
at y
atz
, aI.But then a
xy
a
xa1
x y
a
xa1
xy
ax.Thus
at
xaxa
x y
at y
atz
x y
and a0
x y, x
I as aI.(ii) implies (iii) . Let x,y,z,tL and x
t y
tz
, then there exists aL such that a0
xy,x
and x
ta
aty
atz
x y
.Now x
ta
aty
atz
y
x
ta
aty
atz
xy
x
ta
, hence x
ta
atz
y
x
ta
. Thus (iii) holds.(iii)implies (i). Let
be any congruence of L. Suppose xy and xy
. Let I
0. Since xy x yx so by (iii) with tzx there exists an aLsuch that x
xa
axx
y
x
xa
xa
y i,e x
xa
y. Where, a0
xt,x
. [since theorem 1.1]Hence I is a standard ideal and
I . Now it suffices to show that all standard ideals of L are neutral. Let I be a standard ideal of L and
J K
I
x for some ideals J and K. Then xI and xJK ThenxLm for some
0,1,2,3
m where A0 JK . Lm
t pq:pq exist and p,qLm1
Suppose xL0. Then xI and xJ or xK , and so x
IJ
IK
. Now we will use the induction. Suppose yLm1, and yI implies that y
IJ
IK
. Since xLm, xpq for suitable p,qLm1. set tpq. Then x
t p
tq
. Then by (iii) there exists bL such that
t b
b t q
p
t b
x
x , b0
x p,x
. Since x,x p,0I and I is a Homomorphism kernel, we get bI . Hence x
tb
I.Further
x
tb
p
x
tb
q
x
tb
p
btq
x
tb
. Putting
t b
x
a , we get xa
a p
aq
with aINow both a p,ar are members of I and Lm1. Thus both a p,aq belongs to
IJ
IK
, and so x
I J
IK
.Hence I is neutral.
Theorem 1.12: Let k an ideal in a lattice. Then the following condition are holds.
(i) k is a standard ideal.
(ii) The binary relation
k , defined by xy
x
if and only if x
xy
xa
,
x y
y b
y for some a,bk is a lattice congruence.
(iii) The binary relation , define by x y
if and only if for all tS
xt
tc
yt
tc
for some ck, is a lattice congruence.(iv) For each ideal H, kH
kh: kh exists and kK,hH
. Theorem 1.13 : Let L be a lattice with the smallest element 0 in which each initial segment is a complemented lattice. Then the map K
K is a lattice isomorphism of the lattice of standard ideals of L on to the lattice congruence of L.Proof: Let be a lattice-congruence of L and J
xL:x0
. Of course J is an ideal. Suppose
ba and let c and d be respective complements of ab in
a
and
b
. Then
0
c a c a b
c and ddb0
. Also a
ab
ac
and b
ab
bd
with c,dJ.
Conversely, these last relations imply ab
. Hence by the above theorem J is a standard ideal and
H J .
The remainder follows from corollary: The standard ideals of a lattice L form a distributive sub lattice of the ideal-lattice J
L and the map K
K is a lattice embedding of this sub lattice into the distributive of all lattice congruence on L.The situation is more complex when it comes to permutability. We close this section with some result in this direction.
A lower semi lattice
L:
is called medial if the supremum
xy
ys
zx
exists when the suptema of each pair exist. Thus the medial lower semi lattice is a lattice and so will be referred to as medial lattice.Theorem 1.14: A mapping f:LM is an isomorphism if and only if f is isotone and has an isotone inverse.
Proof: Let f:LM be an isomorphism. Then f being one-one, onto f1exists and is one-one , onto. Again by definition of isomorphism, f will be isotone. We show f1:LMis also isotone.
Let y1,y2M where y1y2. Since f is onto, x1,x2L, s.t f
x1 y1, f
x2 y2
1 2 1
21
1 f y ,x f y
x
.
Now y1 y2 f
x1 f
x2 x1x2 [from the definition of isomorphism]
1 1
2 11 ,
f y f y f is isotone.
Conversely, let f be isotone such that f1 is also isotone , since f1exists, f is one-one, onto . Again, as f is isotone x1x2 f
x1 f
x2 , x1,x2L.Also f1 is isotone implies f
x1 x1 f
x2 f1
f
x1
f1
f
x2
x1x2, thus
1
22
1 x f x f x
x Hence f is an isomorphism.
Theorem 1.15: L/ is a lattice.
Proof: Of course L/is a meet semilattice. We need only to show that it has the upper bound property. Let
a,b c then
a a c ac
,
b b c bc
Now,
ac
bc
exists by the upper bound property of L. Hence
ac
bc
ac
bc
and so
a bexists. Therefore L/ is a lattice. If is a congruence of a lattice L, then the map :LL/ defined by
a
a is the natural homomorphism. This is known as the homomorphism induced by . For a standard ideal S of L we denote the quotient lattice L/
S , simply by L/S.Now we give the homomorphism theorem for lattices which is a generalization of [Lattice Theory First concepts by Gratzer theorem 11 p-26].
Theorem 1.16: Every homographic image at a lattice L is isomorphic to a suitable quotient lattice L. In fact if M
L
: is a homomorphism of L on to M and if
is the congruence relation of L defined by xy if and only if
x y then L/L1; an isomorphism is given by :
xq
x , xL.Proof: Since
is a homomorphism then it is easy to check that
is a congruence relation . To prove that is an isomorphism, we have to check that (i) is well defined. Let
x
y . Then x y
; thus
x p y x y . i.e. is well defined
(ii) is one - one,
x
y
x y then xy and so
x
y
i.e. is one - one .(iii) is on to : Let xL since
is onto. There is any yL with
y x . Thus
y
x i.e. is onto .(iv) Preserves the operations. i.e. is homomorphism . Let
x , y L/, therefore
x y
x y
xy
x y
x
y
, and finally for , Suppose
x
y exists.Then
x
y
t for some tL. so
x
t and
y
t . This implies
x
x
t
xt
,similarly
y
yt
.Then
x
y
xt
yt
x t
y t
t y t x
t y t x
y x
t y t
x
Hence is a lattice homomorphism and so it is an isomorphism
Theorem 1.17: [First isomorphism theorem for standard ideals]: Let L be a lattice, S be a standard ideal and I an arbitrary ideal of L Then SI is a standard ideal of I
and
IS
/SI/
IS
.Proof: We can use the first isomorphism theorem for universal algebra [12, Theorem 1.2], Then it remains to prove that every congruence class of IS may be represent by an element of I . so let xIS. Then since theorem 1.1 xis for some iI, sS. Moreover xisi
S .Hence congruence class that contains x may be represented by iI. That is
x i
S . Therefore
IS
/SI/
I S
. For the 2nd isomorphism theorem we need the following results. We omit the proofs as they are very trivial.
Lemma 1.18: Let the correspondence xx be lattice homomorphism of lattice L on to a lattice L. If s is standard element of L then s is a standard element of L.
Corollary 1.19: Let xx be lattice homomorphism of lattice L onto I . Let S be an ideal of L and denote by S the homomorphic image of S under this homomorphism. If S is standard in L then S is standard in L.
Theorem 1.20: [Second isomorphism theorem for standard ideals].
Let L be a lattice, S be an ideal and T be a standard ideal of L . ST. Then S is a standard ideal of L if and only if S/T is a standard ideal in L/T and in this case L/S
L/T
/ S/T
.Proof: First suppose that S is a standard ideal of L. let :LL/T be the natural mapping . Then xx is a lattice homomorphism and onto. So S is a standard ideal of L/T . Now SS/T . Hence S/T is a standard ideal of L/T .
Conversely, suppose that S/T is a standard ideal of L/T . We are to show that S is a standard ideal of L.
Let us define a relation
S by 1.1 (ii), suppose xy with x y
S
. Then x ys for some sS. Thus for anyu L
. if xu exists,then xu
yu
s. This implies xu yu
S
. To prove substitution property for , suppose a denotes the image of the element a under the homomorphism LL/T Suppose x y((S/T)).SinceT
S/ is standard in L/T , there is a suitable sS/T, such that xu (yu)s.
Further, since T is standard in L we can find aT such that xu
(yu)s
t. We put s1st and get
y u
s s S ux 1, 1 .. Hence
S is a congruence relation of L, and so by 1.1, S is standard.In above proof we have also shown that the congruence classes of L/T under
S/T
are the homomorphism image of those of L under
S . Then the second isomorphism theorem for universal algebra [12 theorem 1.4 finishes the proof.Thus in a lattice every standard ideal is a homomorphism kernel of at least one congruence relation and the congruence classes of L/T under
m S/T
are the homomorphism image of those of L under
H S . Also the theorem is the characterization of standard ideals of a lattice which I also the nice improvement and generalization of [8, theorem 2]REFERENCE
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