TUGAS MEKANIKA TEKNIK
MENCARI REAKSI PERLETAKAN
Raja Darma Basa Marpaung
04-2018-1-03193
ARSITEKTUR 2018
1
.
ΣMA = 0 ΣMD = 0ΣMA = -VD(8) + P2(5) + P1(3) ΣMD = +VA(8) - P1(5) – P2(3)
= -8VD + 20 + 18 = 8VA – 30 – 12
8VD = 38 8VA= 42
VD = 38
8 = 4,75 Ton Meter ↑ VA= 42
8 = 5,25 Ton Meter ↑
ΣV = VA - P1 - P2 +VD
= 5,25 – 6 - 4 + 4,75 = 0
2.
ΣMA = 0 ΣMD = 0ΣMA = -VD(12) + Q1(9) + P1(2) ΣMD = +VA(12) – P1(10) – Q1(3)
= -12VD + 1080 + 4 = 12VA - 20 - 360 12 VD = 1084 12VA = 380
VD = 1084
12
=
90,33
T/M ↑ VA = 38012
=
31,67 T/M ↑ΣV = VA - P1 – Q1 +VD
= 31,67 – 2 – 120 + 90,33 = 0
3.
ΣMB = 0ΣMB = -VE(7) + Q2’(7,75) + Q2(6,5) + P2(5) + Q1(1,5) – P1(1,5)
= -7VE + 69,75 + 39 + 21,5 + 20,25 – 3,45 7VE = 147,05
VE =
147,05
7
= 21,7142571 Ton/Meter ↑ΣME = 0
ΣME = VB(7) – Q1(5,5) – P1(8,5) – P2(2) – Q2(0,5) + Q2’(0,75)
= 7VB – 74,25 – 19,55 – 8,6 – 3 + 6,75 7VB = 95,65
VB = 95,65
7
=
13,664285
Ton Meter ↑ΣV = VE - P1 – Q1– P2 - Q2- Q2’+VB
= 21,7142571 – 2,3 – 13,5 – 4,3 – 6 – 9 + 13,664285 = +0,2785 ↑
Keterangan : P1= 6 Ton P2= 4 Ton
Keterangan : P1= 2 Ton Q1 = 20 x 6
= 120 T/M
Keterangan :
P1= 2,3 Ton Q1P= 1,5 x 3 = 4,5 Ton/Meter
P2= 4,3 Ton Q2P= 2 x 3 = 6 Ton/Meter
Titik Terpusat :
Q1= 4,5 x 3 = 13,5 Ton/Meter