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Akar Persamaan

(Roots of Equations)

Pertemuan – 2, 3

Mata Kuliah : Analisis Numerik Kode : CIV - 208

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Sub Pokok Bahasan :

Metode Biseksi

Metode Regula Falsi

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Years ago, we learned to use

the quadratic formula

to solve

The values calculated with

Eq. (1) are called the “roots”

of Eq. (2).

They represent the values of

x that make Eq. (2) equal to

zero.

(1

)

(2

)

a

ac b

b x

2

4 2

 

(4)

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Bracketing Methods

This topic on roots of equations deals with methods that

exploit the fact that a function typically changes sign in the vicinity of a root.

These techniques are called bracketing methods because

two initial guesses for the root are required.

As the name implies, these guesses must “bracket,” or be

on either side of, the root.

The particular methods described herein employ different

strategies to systematically reduce the width of the bracket and, hence, home in on the correct answer

Three methods classified as Bracketing Methods are :

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Graphical Method

A simple method for obtaining an

estimate of the root of the equation

f(x)=0 is to make a plot of the

function and observe where it

crosses the x axis.

This point, which represents the

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Example 1 :

Use the graphical approach to determine the real

root of :

Various values of x can be substituted

into the right-hand side of this

equation to compute f(x),

for example if x = 0, then

f(x) = 4(0)

3

– 6(0)

2

+ 7(0) – 2,3 =

− 2,3

Try for another value of x, and

tabulated the results

x f(x) 0 -2,3 0,1 -1,656 0,2 -1,108 0,3 -0,632 0,4 -0,204 0,5 0,2 0,6 0,604 0,7 1,032

 

x 4x3 6x2 7x 2,3

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These points are plotted in

Figure.

The x value as a horizontal

axes, and f(x) as a vertical

axes

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The validity of the graphical estimate can

be checked by substituting it

which is close to zero, and x = 0,45 said

as a root of

0,45

4

0,45

3 6

0,45

2 7

0,45

2,3 0,0005

f     

 

x 4x3 6x2 7x 2,3

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Bisection Method

When applying the graphical technique in

Example 1, we have observed that f(x)

changed sign on opposite sides of the root.

In general, if f(x) is real and continuous in

the interval from x

l

to x

u

and f(x

l

) and f(x

u

)

have opposite signs, that is,

f(x

l

)f(x

u

)<0

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Termination Criteria and Error Estimates

an approximate percent relative error ε

a

can be

calculated, as in

where x

rnew

is the root for the present iteration and

x

rold

is the root from the previous iteration.

The absolute value is used because we are usually

concerned with the magnitude of ε

a

rather than with

its sign.

When ε

a

becomes less than a prespecified stopping

criterion ε

s

, the computation is terminated.

%

x

x

x

new r

old r new

r

a

100

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Example 2 :

Use bisection to solve the same problem

approached graphically in Example 1, until

the approximate error falls below a stopping

criterion of

ε

s

=0.5%.

Root of equation

 

x 4x3 6x2 7x 2,3

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The False-Position Method

• A shortcoming of the bisection method is that, in dividing the interval from xl to xu into equal halves, no account is

taken of the magnitudes of f(xl) and f(xu).

• For example, if f(xl) is much closer to zero than f(xu), it is

likely that the root is closer to xl than to xu.

• An alternative method that exploits this graphical insight is to join f(xl) and f(xu) by a straight line.

• The intersection of this line with the x axis represents an improved estimate of the root.

• The fact that the replacement of the curve by a straight line gives a “false position” of the root is the origin of the name, method of false position, or in Latin, regula falsi.

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Using similar

triangles, the

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Example 3 :

Use the false-position method to

determine the root of the same

equation investigated in Example 1.

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Home work (Group)

Kerjakan soal dari buku Chapra Soal

no.

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For the bracketing methods, the root is located

within an interval prescribed by a lower and an

upper bound.

Repeated application of these methods always

results in closer estimates of the true value of the

root.

Such methods are said to be convergent because

they move closer to the truth as the computation

progresses

In contrast, the open methods are based on

formulas that

require only a single starting

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As

such,

they

sometimes diverge or

move away from the

true

root

as

the

computation

progresses (Fig. b).

However, when the

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Simple Fixed-Point Iteration

Open methods employ a formula to

predict the root.

Such a formula can be developed for

simple fixed-point iteration (or, as it is

also called, one-point iteration or

successive substitution) by rearranging

the function f(

x

)=0 so that

x

is on the

left-hand side of the equation:

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This transformation can be

accomplished either by algebraic

manipulation or by simply adding x

to both sides of the original

equation.

For example,

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The utility of Eq. (1) is that it provides a formula

to predict a new value of x as a function of an old

value of x.

Thus, given an initial guess at the root x

i

, Eq. (1)

can be used to compute a new estimate x

i+1

as

expressed by the iterative formula

x

i+1

=

g

(

x

i

)

(2)

the approximate error for this equation can be

determined using the error estimator

%

x

x

x

i

i i

a

100

1

1

 

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Example 1 :

Use simple fixed-point iteration to

locate the root of

The function can be separated directly and

expressed in the form

 

x 4x3 6x2 7x 2,3

f    

7

3 2 6

4 3 2

1

, x

x

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Starting with an initial guess of x

0

=0,

this iterative equation can be

applied to compute

Root of equation

 

x 4x3 6x2 7x 2,3

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The Newton-Raphson Method

Perhaps the most widely

used of all root-locating formulas is the Newton-Raphson equation.

If the initial guess at the

root is xi, a tangent can be

extended from the point [xi, f(xi)].

The point where this tangent

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the first derivative at x is equivalent

to the slope

Which can be rearranged to yield

Newton-Raphson formula :

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Example 2 :

Use the Newton-Raphson method to

estimate the root of

employing an initial guess of x

0

= 0

The first derivative of the function can be

evaluated as

f’

(

x

)= 12x

2

– 12x + 7, which

can be substituted along with the original

function into Eq. (3) to give

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Starting with an initial guess of x

0

=0, this

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Although the Newton-Raphson

method is often very efficient, there are situations where it performs poorly.

Fig. a depicts the case where an

inflection point [that is, f’’(x)=0] occurs in the vicinity of a root.

Fig. b illustrates the tendency of

the Newton-Raphson technique to oscillate around a local maximum or minimum.

Fig. c shows how an initial guess

that is close to one root can jump to a location several roots away.

Obviously, a zero slope [f’(x)=0] is

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The Secant Method

A potential problem in implementing the

Newton-Raphson method is the evaluation of

the derivative.

Although

this

is

not

inconvenient

for

polynomials and many other functions, there

are certain functions whose derivatives may be

extremely difficult or inconvenient to evaluate.

For these cases, the derivative can be

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Equation (4) is the formula for the

secant method.

Notice that the approach requires

two initial estimates of x.

However, because f(x) is not

required to change signs between

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Example 3 :

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The Difference Between the Secant and False-Position Methods

The Eqs. Above are identical on a term-by-term basis. Both use two initial estimates to compute an

approximation of the slope of the function that is used to project to the x axis for a new estimate of the root.

However, a critical difference between the methods is how

one of the initial values is replaced by the new estimate.

False-Position

Formula Secant Formula

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• Recall that in the false-position method the latest estimate of the root replaces whichever of the original values yielded a function value with the same sign as f(xr).

• Consequently, the two estimates always bracket the root.

• Therefore, the method always converges

• In contrast, the secant method replaces the values in strict

sequence, with the new value xi+1 replacing xi and xi replacing xi−1.

• As a result, the two values can sometimes lie on the same side of the root.

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Method xroot iteration ea(%)

Bisection 0,4512 10 0,4329 False Position 0,4506 4 0,3612 x=g(x) 0,44856 7 0,47396 Newton

Raphson 0,4501 6 0,001 Secant 0,4501 3 0,402

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Homework 1

Frekuensi alami dari getaran bebas (free vibration) balok

uniform yang terjepit pada salah satu ujungnya dan bebas pada ujung yang lain dapat dicari dari persamaan berikut

cos(L)cosh(L) = 1 Dengan :

L = panjang elemen balok = 2 meter

 = berat jenis elemen balok

n = frekuensi alami balok (rad/dt) EI = kekakuan lentur balok

Tetapkan 3 buah nilai n dari persamaan di atas. kemudian gunakan nilai  untuk menentukan frekuensi alami balok.

a

n n

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Homework 2

HItunglah panjang kurva (L), dari suatu lengkung / busur jalan dengan parameter – parameter :

PC = titik kurvatur, PT = titik tangensial, PI = titik perpotongan. Kurva mempunyai 7 elemen :

1. Radius kurva, R 2. Sudut lengkung, I 3. Jarak tangensial, T 4. Panjang kurva, L 5. Panjang busur, Lc 6. Ordinat tengah, M 7. Jarak luar, E

Hubungan antara kelengkungan dan jari – jari : Diketahui nilai :

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Homework 3

Hubungan antara debit air Q penampang saluran terbuka

berbentuk trapesium terhadap parameter geometri penampang adalah : m3/dt. Hitung besarnya y!

Gambar

Figure. 1.5
Fig. c shows how an initial guess

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