! "
# $ $ % ! ! &'()&
* ++ , $
Abstract. Given a commutative ring
R
with unit,R
-algebraA
andR
-coalgebraC
.
Triple(
A C
, ,
ψ
)
is called (weak) entwining structure if there isR
-linear mapψ
:
C
⊗
RA
→
A
⊗
RC
that fulfil some axioms. In the other hand, from algebraA
and coalgebraC
we can considerA
⊗
RC
as a leftA
-module canonically such that(
A C
, ,
ψ
)
is entwined structure if only ifA
⊗
RC
is aA
-coring. In particular, we obtain that(
A C
, ,
ψ
)
is a weak entwined structure if only ifR
A
⊗
C
is a weakA
-coring.Keywords : algebra, coalgebra, coring, entwining structure.
-
R
" ! - $ . / / 0 +1 % 234
R
5 ! %(
A
, ,
µ ι
)
R
5 ! %(
C
, ,
∆
ε
)
-(
A C
, ,
ψ
)
% - ! 6R
5:
C
RA
A
RC
ψ
⊗
→
⊗
6 $ % % . / / 0 + 2(4!
R
5 ! %A
R
5 ! %C
%R
5 $A
C
R
5 -A
⊗
RC
.
" !A
5(
)
:
A
RC
RA
A
RC
,
α
⊗
⊗
→
⊗
α
(
(
a
⊗
b
)
⊗
c
)
=
a
ψ
(
c
⊗
b
)
,
A
⊗
RC
(
A A
,
)
5% - %
A
⊗
RC
- + !$ . / / 0 + 274 - "% - - + ! - + - ! $ $
(
A C
, ,
ψ
)
- !R
A
⊗
C
A
5 ! ! " %(
)
(
)
:
I
A:
A
RC
A
RC
RC
A
RC
AA
RC
,
∆
AC
I
ε
⊗
∆
CA
I
⊗
ε
1
⊗ − ⊗
1
:
I
A:
A
RC
A
.
ε
=
⊗
ε
⊗
→
1 + ! + ! % - +! % 5 % 8 2)4 1 % 294:$ 1
-% - ! - ! % - + !
A
⊗
RC
.
( - ! " ! - + ! $ ! /
! % 8 . / / 0 + 234 2)4 1 % 294:$ 6
. / / 0 + 274 ! " - ! - + - ! $
7 - " % - - + - ! - + ! $
R
A
⊗
C
- + !A
⊗
RC
- ! $;9<' - ! % " $
"
C
"F
-∆
:
C
→
C
⊗
FC
ε
:
C
→
F
F
5 ! % $ ! % " " ! "! . / / 0 + 1 % 234$ - ! " %
! - + ! 8 . / / 0 + 234 2)4 1 % 294:$
!
A
- % " ! - $C
(
A A
,
)
(
A A
,
)
∆
:
C
→
C
⊗
AA
⊗
AC
,
(
∀ ∈
c
C
) ( )
∆
c
=
c
1⊗ ⊗
1
c
2(
A A
,
)
ε
:
C
→
A
∆
! ; "
c
∈
C
,
ε
( )
c c
1 2=
1 1
c
=
c
1ε
( )
c
2.
(
A A
,
)
C
∆
ε
.
C
A A
C
⊗
A
⊗
C
C
A A
:
C
RA
A
RC
,
ψ
⊗
→
⊗
ψ
(
c
⊗
a
)
=
a
ψ⊗
c
ψ,
,
.
a
ψ∈
A c
ψ∈
C
! ( "1 2 R R
,
c
⊗
a
⊗
a
∈ ⊗
C
A
⊗
A
c
⊗ ∈ ⊗
a
C
RA
,
;$
(
a a
1 2)
c
a a c
1 2ψ ϕ
ψ ψϕ
ψ
=
($
a
ψ⊗
c
1ψ⊗
c
2ψ=
a c c
ψϕ 1ϕ 2ψ 3$1
ψ⊗
c
ψ= ⊗
1
c
7$
a
ψε
( )
c
ψ=
ε
( )
c a
.
- + - ! ! - 3$;$
%
A
⊗
RC
%" " ;$ - ! > ! 2<4
1 % 294$
(
A
, ,
µ ι
)
R
(
C
, ,
∆
ε
)
R
!(
A C
, ,
ψ
)
"
R
ψ
:
C
⊗
RA
→
A
⊗
RC
,
(
a
c
)
a c
ψ ψψ
⊗
=
a
ψ∈
A
c
ψ∈
C
&( )
ab
c
a b c
ψ ϕ
ψ ψϕ
ψ
=
#
a
ψ(
c
ψ1⊗
1
)
⊗
c
ψ2=
a
ψϕ⊗
c
1ϕ⊗
c
2ψ $a
ψε
( )
c
ψ=
ε
( )
c
ψ1
ψa
%
1
ψ⊗
c
ψ=
ε
( )
c
1ψ1
ψ⊗
c
2.
R
5 % -R
5 ! %A
R
5 ! %C
%
A
⊗
RC
.
- % 6 % - 8- +: - !8- +: ! :
A
⊗
RC
.
1 - " ! $!
(
A
, ,
µ ι
)
R
(
C
, ,
∆
ε
)
R
!(
A C
, ,
ψ
)
8 :$