Chapter IV: Formal Requirements on Costly Information
4.7 Conclusion
the private reports and make a decision with the maximum possible effort in hard information.
complicate the calculations and require the application and proof of the modified version of the revelation principle, but potentially it would lead to more interesting insights into the problem.
In order to incorporate the possibility of a biased committee, a potential extension of this paper would introduce a third party (AMA) as a principal whose goal is to maximize social welfare. However, the AMA can only choose effort levels conditional on the agentβs report of her private signal, while the decision about prices is still made by (potentially biased) committee members. In this case, each member of the committee would have the following utility function:
ππ =πΌπ1{πΛ=π»} + (1βπΌπ)1{πΛ=π},
whereπΌπmeasures how biased the committee memberπis towards the high prices. If πΌπ =0, there is no bias and the committee member is only concerned with fairness.
If πΌπ = 1, the committee member only gets utility from high prices; therefore, her preference is identical to the proposerβs preference in our setting. It would be interesting to observe how the expected outcome of the optimal mechanism changes with different bias levels of the committee and different voting rules.
A p p e n d i x A
CHAPTER II
Lemma 2
When the incumbent does not anticipate the external shock, the voterβs strategy is the best response i.f.f. she reelects the incumbent when
π¦ = π΄ and π’ > π’β
π΄
or
π¦ =π΅andπ’ > π’β
π΅
and votes for the challenger otherwise.
π’β
π΄ = 1βπβπΌ+π πΌ+π πβπ πΌπ 1βπ+π πβπΌπ π’β
π΅ = πΌβπ πΌβπΌπ+π πΌπ 1βπ+π πβπΌπ
.
Proof As discussed in text, this lemma simply follows from the bias rule. After observing utilityπ’ and policy choiceπ¦ β {π΄, π΅} posterior belief of the voter about the incumbents type is:
π(πΌ = π»|π’, π¦ = π΄) = π(π’|π» , π¦ = π΄)π(π»|π¦= π΄)
π(π’|π» , π¦ = π΄)π(π»|π¦= π΄) +π(π’|πΏ , π¦ = π΄)π(πΏ|π¦ = π΄) =
= π(π’β1)πΌ π
π(π’β1)πΌ(π+ (1β π) (π+ (1βπ)π)) + π(π’) (1βπΌ) (π π+ (1βπ)) (1β π) π(πΌ =π»|π’, π¦= π΅) = π(π’|π» , π¦ = π΅)π(π»|π¦=π΅)
π(π’|π» , π¦ =π΅)π(π»|π¦= π΅) +π(π’|πΏ , π¦ =π΅)π(πΏ|π¦ =π΅) =
= π(π’β1) (1βπΌ)π
π(π’β1) (1βπΌ) (π+ (1βπ)π(1βπ)) + π(π’)πΌ(1βπ) (1βπ) (1β π) The incumbent is reelected iff
π(πΌ =π»|π’, π¦ = π΄) > π =β π’ >
1βπβπΌ+π πΌ+π πβπ πΌπ 1βπ+π πβπΌπ
β‘ π’β
π΄
π(πΌ =π»|π’, π¦ =π΅) > π =β π’ >
πΌβπ πΌβπΌπ+π πΌπ 1βπ+π πβπΌπ
β‘π’β
π΅
Proposition 4
When the voter observes her own utility, we have two possible equilibria:
1) Ifπ > πΛtruth equilibrium.
2) Ifπ < πΛ, the low-type politician panders after observingπ =π΅with probability
Λ
π = (β(πβπΌ)1+π) +
q(π πΌ2β
2π2πΌ2+π3πΌ2β2π πΌ3+4π2πΌ3β2π3πΌ3+π πΌ4β2π2πΌ4+π3πΌ4) ( (πβπΌ)2(π2+π3β2π πΌβπ2πΌβπ3πΌ+πΌ2+π πΌ2βπ2πΌ2+π3πΌ2)) ,
where:
Λ
π= 0.5(β1+2πΌ2βπΌ3) 1βπΌ+πΌ2
+0.5 s
1.+4πΌβ8πΌ2+6πΌ3+4πΌ4β4πΌ5+πΌ6 (1βπΌ+πΌ2)2 . In both types of equilibrium, the voterβs strategy is to re-elect the incumbent i.f.f.
(π¦= π΄andπ’ > π’β
π΄) or (π¦ =π΅andπ’ > π’β
π΅).
Proof The voterβs strategy in equilibrium to reelect the incumbent follows directly from Lemma 7. We have already established that H-type incumbent and L-type incumbent who sees popular private signalπ = π΄, always follow their signal. Now we show that L-type incumbent who sees unpopular signal π = π΅ does not have profitable deviations in two cases considered above.
1) π > πΛ. Λπ is the value for whichπΈ ππ΅
π΅ β πΈ ππ΄
π΅ is positive even forπ =0 (and πΈ ππ΅
π΅ βπΈ ππ΄
π΅ is increasing inπ). Therefore, for the given reelection strategy of the voter, the low-type politician who sees the unpopular signal does not have incentive to deviate and pander.
1) π < πΛ. In this case voterβs strategy is to reelect incumbent iif (π¦ = π΄ and π’ > π’β
π΄(πΛ)) or (π¦ = π΅ and π’ > π’β
π΅(πΛ)). Given this strategy of the voter, the low-type incumbent with π = π΅ signal gets utility πΈ ππ΅
π΅(π’β
π΅(πΛ)) if he is truthful and πΈ ππ΄
π΅(π’β
π΄(πΛ)) if he panders. Since Λπ is chosen to equate these two expected utilities, the incumbent has no incentive to deviate.
Proposition 5
When the incumbent anticipates the external shock π, we can have the following equilibrium:
1) Ifπ > πΒ―the politician is always truthful, the voter reelects the incumbent i.f.f.
(π¦= π΄andπ’ > π’π΄ =1βπΌ) or (π¦ =π΅andπ’ > π’π΅ =πΌ).
2) Ifπ < πΒ―:
The Incumbent: β’ A low-type incumbent who receives private signalπ =π΅and antic- ipates a positive external shock panders with probabilityπ+β(π) > 0 whenπ’ < π < π’π΅;
β’ A low-type incumbent who receives private signalπ = π΅and antici- pates a negative external shock panders with probabilityπββ(π) > 0 whenπ’π΄β1< π <π’Β―β1.
Otherwise the incumbent is truthful.
The Voter: After popular policy choiceπ¦ = π΄:
- The voter elects the challenger for low enough utility: πβ
π΄ = 0 if π’π£ < π’π΄;
- The voter mixes between the incumbent and the challenger with probabilityπβ
π΄ β (0,1)for intermediate levels of utilityπ’π΄ < π’π£ <
Β― π’;
- The voter reelects the incumbent for high enough utility: πβ
π΄ =1 if π’π£ >π’Β―.
After unpopular policy choiceπ¦= π΅:
- The voter elects the challenger for low enough utility: πβ
π΅ = 0 if π’π£ < π’;
- The voter mixes between the incumbent and the challenger with probabilityπβ
π΅ β (0,1) for intermediate levels of utilityπ’ < π’π£ <
π’π΅;
- The voter reelects the incumbent for high enough utility: πβ
π΅ =1 if π’π£ > π’π΅.
Where:
π’= βπ+2π πΌβπΌ2
βπβπΌ+2π πΌ π’Β― = βπΌ+πΌ2
βπβπΌ+2π πΌ πβ
π΄ =


ο£²

ο£³
πβπΌ
π πΌβπ2πΌ for π’ β (π’π΄, π’)
0.5π4(1βπΌ)2+π3(0.5β0.5πΌ)+π2(β0.5+0.5πΌ)πΌ
π3(β1+πΌ) (β0.5πβ0.5πΌ+π πΌ) for π’ β (π’,π’Β―)
πβ
π΅ =


ο£²

ο£³
πβπΌβπ πΌ+π2πΌ
βπ2βπ πΌ+2π2πΌ for π’ β (π’,π’Β―)
πβπΌβπ πΌ+π2πΌ
βπ πΌ+π2πΌ for π’ β (π’, π’Β― π΅)
Β―
π= 0.5(β1+πΌ) πΌ
+0.5
r1β2πΌ+5πΌ2 πΌ2 πββ(π) =


ο£²

ο£³
(πβπ2βπ π+π2πβπ πΌ+π2πΌ+π π πΌβπ2π πΌβπ(1+π)+π2(1+π)+π π(1+π)βπ2π(1+π))
(β1.βπ πΌ(1+π)+π2πΌ(1+π)+π π πΌ(1+π)βπ2π πΌ(1+π)) for π β (π’π΄β1, π’β1)
(πΌ+π πΌ+πΌ2β1.βπ πΌ2+π(1+π)βπ2(1+π)+πΌ(1+π)β3π πΌ(1+π)+2π2πΌ(1+π))
(βπ2(1+π)+2π2πΌ(1+π)+πΌ2(1+π)β2.π πΌ2(1+π)) for π β (π’β1,π’Β―β1)
π+β(π) =



ο£²



ο£³
πΌ3(0.25πΌβ0.25π)+π3(0.5βπΌ)2(β1+π)+π πΌ(πΌ(0.5ββπΌβ0.25πΌ2)+(β0.25+0.25πΌ+0.75βπΌ2)π) ( (0.5πΌ2βπ πΌ2+π2(β0.5+1πΌ)) (πΌ2(0.5β0.5π)+π(0.5β1πΌ+(β0.5+πΌ)π)))
+ π2(0.25β1πΌ+0.5πΌ2+πΌ3+(β0.25+1.25βπΌβ1.25πΌ2β0.5πΌ3)π)
( (0.5πΌ2βπ πΌ2+π2(β0.5+1πΌ)) (πΌ2(0.5β0.5π)+π(0.5β1πΌ+(β0.5+πΌ)π))) for π β (π’,π’Β―)
(π πΌβπ2πΌβπ π πΌ+π2π πΌβππ+π2π+π ππβπ2ππ)
(π πΌβπ2πΌβπ π πΌ+π2π πΌβπ πΌπ+π2πΌπ+π π πΌπβπ2π πΌπ) for π β (π’, π’Β― π΅)
Figure A.1: This graph shows equilibrium strategy of the low-type incumbent with unpopular signalπ = π΅, depending on realization of the external shockπ.
Proof Much of this proof is always done in the main text. In order to prove the given strategy profile is actually an equilibrium, we should show that neither player (the incumbent or the voter) has an incentive to deviate, given strategy of the other one.
The Incumbent
In the second period, absent reelection motives, the incumbent always follows his private signal since π > πΌ. We have also shown that the high-type incumbent as well as the low-type incumbent with popular signalπ = π΄are always truthful in the first-period and thus have no profitable deviation. We need to show the same for the low-type incumbent with the unpopular signalπ = π΅.
Region 1 As discussed in the main text, for such extreme realizations of the external shock, the incumbent is either always reelected or always dismissed, and his policy choice has no impact on his reelection probability. Since his private signal is informative, the low-type incumbent with the unpopular signal always follows it to match the state and get a better first-period utility. In this case, the low-type incumbent has no profitable deviation.
Region 2 For small external shocks, given the equilibrium strategy of the voter, the incumbent is reelected i.f.f. he matches the state. Since his private signal is informative, the low-type incumbent is truthful and has no profitable deviation.
Region 3A For medium-low positive shocks, the incumbent is always reelected after matching the state. If the state is mismatched, he is reelected with probability πβ
π΄afterπ¦ = π΄and dismissed afterπ¦ =π΅. In the main text, we already showed thatπ0
π΄
> πβ
π΄1whereπ0
π΄makes the low type indifferent between being truthful
1πβ
π΄is the equilibrium reelection probability for this region.
and pandering. Since less reelection probability after π¦ = π΄ encourages the incumbent to be truthful, he has no profitable deviation.
Region 3B For medium-low negative shocks, the incumbent is always dismissed after a mismatched state. If the state is matched, he is always reelected after the popular policy choiceπ¦ = π΄and sometimes reelected with probabilityπβ
π΅after the unpopular policy choice. We have shown in the text thatπβ
π΅ > π0
π΅2where π0
π΅ makes the incumbent indifferent between being truthful and pandering.
Since reelection probability afterπ΅encourages the incumbent to be truthful, he has no profitable deviation.
4A and 4B In these regions, equilibrium levels of reelection ππ΄ and ππ΅ are chosen to make the low-type incumbent with unpopular signal indifferent between ei- ther policy choice. Therefore, the low-type incumbent panders and has no profitable deviation.
In Region 4π΄, the matched state leads to reelection of the incumbent regardless the policy choice. If, instead, the state is mismatched, then the voter always reelects the incumbent after the popular policy choice but mixes after the unpopular policy choiceπ¦ = π΅(ππ
π΅
< 1). When the low-type incumbent sees signalπ =π΅if he follows it and choosesπ¦ =π΅he gets:
πΈ ππ΅
π΅ = π(π= π΅|π =π΅) (1+π) +π(π = π΄|π =π΅) (0+ππ
π΅π). If instead he panders and choosesπ¦ = π΄he gets:
πΈ ππ΄
π΅ =π(π = π΄|π =π΅) (1+π) +π(π= π΅|π =π΅) (0+π).
Since the low-type incumbent panders in this region, the equilibrium reelection probabilityπβ
π΅makes him indifferent between following the unpopular policy and pandering, meaning:
πβ
π΅ = π(π = π΄|π =π΅) (1+π) βπ(π= π΅|π =π΅) π(π = π΄|π =π΅)π
.
We have already shown that this reelection probability makes the low-type incumbent truthful in Region 3π΅.
In Region 4π΅, the voter never reelects the incumbent regardless of the policy choice after a mismatched state. If the state is matched then he voter sometimes
2πβ
π΅is the equilibrium reelection probability for this region.
reelects the incumbent after the popular policy choice π¦ = π΄(π1+π
π΄
< 1) but always elects the challenger after the unpopular policy choice π¦ = π΅. When the low-type incumbent sees the unpopular signalπ = π΅, if he follows it and choosesπ¦= π΅he gets:
πΈ ππ΅
π΅ =π(π =π΅|π = π΅) (1+0) +π(π = π΄|π =π΅) (0+0). If instead he panders and choosesπ¦ = π΄he gets:
πΈ ππ΄
π΅ =π(π = π΄|π =π΅) (1+π1+π
π΄ π) +π(π= π΅|π =π΅) (0+0).
Since the low-type incumbent with the unpopular signal panders in this re- gion, the equilibrium reelection probability is derived by equating the two expressions above:
πβ
π΄ = π(π =π΅|π =π΅) βπ(π = π΄|π = π΅) π(π = π΄|π =π΅)π
.
We have already shown that this reelection probability makes the low-type incumbent truthful in Region 3π΄.
5A and 5B Similar to the previous case, reelection mixing probabilities make the low- type incumbent with unpopular signal indifferent between either policy choice and he has no profitable deviation. Unlike the previous case, both reelection probabilities play a role in satisfying the indifferent conditions for the low-type incumbent with the unpopular signal in both of these regions. Consequently, the equilibrium values of the reelection probabilities (πβ
π΄
, πβ
π΅) for these regions are derived by solving the system of equations for double indifference as shown in the main text.
The Voter
As already discussed in the main text, voter who observes utility beyond(0,1)range has no profitable deviation since she learns about matched/mismatched state (given challenger and incumbent are from the same pool, this is enough information for them to elect a second-period representative). The rest of the proof falls directly from the observations in Section 5.3 and uses Bayes Rule for updated posterior beliefs of the voter.
As discussed in the main text, the voter knows the low-type incumbent was truthful when she observes the utility level from Regions 1 and 2. Since π’π΄ = 1βπΌ and π’π΅ =πΌ, it follows directly from the truthful equilibrium of the baseline model that she has no profitable deviation.
For utility levels from Region 3, the voter knows that one of the two cases is possible:
β’ The state was matched andπ =π’π£β1. In which case,π’π΄β1< π < π’β1 and from the previous part, the incumbent is pandering with probabilityπββ.
β’ The state was mismatched andπ = π’π£. In which case, π’π΄ < π < π’, and the L-type incumbent is truthful.
Based on this information the voterβs posterior beliefs after each policy choice are:
π(π»|π’, π¦ =π΄)= π(π’β1)π πΌ
π(π’β1)πΌ π+ π(π’β1)πΌ(1β π) (π+ (1βπ)πββ) + (1βπΌ)π(π’) (1β π) (1βπ); π(π»|π’, π¦ =π΅) = π(π’β1)π(1βπΌ)
π(π’β1) (1βπΌ)π+ π(π’β1) (1βπΌ) (1β π)π(1βπββ) +πΌ π(π’) (1βπ) (1β π). The equilibrium level of pandering πββ(π = π’π£ β 1) in this region is derived to
make the voter indifferent between choosing the incumbent or the challenger after observing the popular policy choice (π(π»|π’, π¦ = π΄) = π). We also make sure that, for this equilibrium level of pandering, the voter wants to elect the challenger after observing the unpopular policy choice π¦ = π΅and the utility from this region (π(π»|π’, π¦= π΅) < π). This derives the thresholdπ’in equilibrium.
In Region 4, the voter knows that one of the two cases is possible:
β’ The state was matched andπ =π’π£β1. In which case, Β―π’β1 < π < π’π΅β1 and from the previous part, the incumbent is truthful.
β’ The state was mismatched andπ = π’π£. In which case, Β―π’ < π < π’π΅, and the L-type incumbent is pandering with probabilityπ+β.
Based on these beliefs, the voterβs posterior beliefs after each policy choice are:
π(π»|π’, π¦ =π΄)= π(π’β1)π πΌ
π(π’β1)πΌ π+ π(π’β1)πΌ(1β π)π+ (1βπΌ)π(π’) (π+βπ+ (1βπ)) (1β π); π(π»|π’, π¦ =π΅) = π(π’β1)π(1βπΌ)
π(π’β1) (1βπΌ)π+ π(π’β1) (1βπΌ) (1β π)π+πΌ π(π’) (1βπ) (1βπ+β) (1β π). In equilibrium, the voter is indifferent between voting for the incumbent or the
challenger after observing the unpopular policy choice π¦ = π΅ and the utility level from this region. Therefore, the equilibrium level of panderingπ+β(π =π’π£)is chosen to satisfy this indifference conditionπ(π»|π’, π¦= π΅) = π. The voter has no profitable deviation if she does not want to vote for the challenger after observing the popular policy choice π¦ = π΄for this equilibrium level of panderingπ+β(π =π’π£). Therefore we must haveπ(π»|π’, π¦ = π΄) > π. This condition is always satisfied forπ’ > π’Β―. For Region 5 we have already shown in the main text how the indifference conditions for the voter after both policy choices define the equilibrium levels of pandering (πββ, π+β) for the corresponding values of the external shock. This completes our proof.
A p p e n d i x B