Chapter III: Large-color π -matrix
3.3 Proof of Theorem 3.2.2
Figure 3.11: The820knot.
knot is fibered, the knot complement Lagrangian can be completely shifted off of the zero sectionπ3, just like the knot conormal Lagrangian. Since the geometry is completely analogous, we expect that the coefficients ofπΉπΎ for a fibered knotπΎ are polynomials, just like (colored) HOMFLY-PT polynomials are polynomials.
Remark 3.2.15. Based on the principles of topological field theory, it is natural to expect thatπΉπΎ(π₯ , π)for a fibered knot is a (graded) trace of the monodromy action on the Hilbert space HΞ£π,
1 associated to the fiber surface. It is a very interesting problem to figure out the exact formula for the monodromy representation onHΞ£π,
1
and compare it withπΉπΎ(π₯ , π).
1. πΉπΏ is an invariant of πΏ. That is, it is independent of the choice of the homogeneous braid representative.
2. Setting π = πβ, its β-expansion agrees with the Melin-Morton-Rozansky expansion of the colored Jones polynomials.
3. πΉπΏ is annihilated by the quantumπ΄-polynomial (or quantumπ΄-ideal in case it has multiple components).
In other words,πΉπΏ is the invariant whose existence was conjectured in [GM21].
Proof. For simplicity, letβs focus on the caseπΏis a knot. The argument we are about to present can be easily generalized to the case of links. In this case,π π(π· , πΌ) is an element ofZ[π, πβ1] [[π₯β1]]. Our goal is to show that theβ-expansion of this series agrees with the Melvin-Morton-Rozansky expansion of the colored Jones polynomials ofπΏ expanded nearπ₯ =β, which is part (2) of the Theorem. Before doing that, letβs first see how part (1) and (3) immediately follow from part (2). Part (1) follows from part (2) because the Melvin-Morton-Rozansky expansion is an invariant of a knot, and part (2) shows that it can be re-summed into a series inπ₯β1 with coefficients inZ[π, πβ1]. Since theβ-series uniquely determines the Laurent polynomial inπ =πβ,πΉπΏ itself is an invariant ofπΏ, and that proves part (1). Proof of part (3) from (2) is similar. Since the Melvin-Morton-Rozansky expansion is annihilated by the quantumπ΄-polynomial, Λπ΄πΏπ(π· , πΌ)should vanish when expanded into a series inβ. Since Λπ΄πΏπ(π· , πΌ) βZ[π, πβ1] [[π₯β1]], it follows that each coefficient should vanish, meaning that Λπ΄πΏπ(π· , πΌ) =0.
Now letβs prove part (2). For this, we combine ideas from [LW01] and [Roz98].
Following [Roz98], we define theparametrizedπ -matricesto be R(πΌ, π½, πΎ)πβ², πβ²
π, π =πΏπ+π ,πβ²+πβ²
π πβ²
πΌππ½π
β²
πΎπβπ
β²
, (3.10)
Rβ1(πΌ, π½, πΎ)πβ², πβ²
π, π =πΏπ+π ,πβ²+πβ²
π πβ²
πΌππ½π
β²
πΎπβπ
β²
,
where π, π , πβ², πβ² β₯ 0. Given an oriented knot diagram with one strand open, we can consider the state sum by replacing each positive crossing withRand negative crossing withRβ1. We will use different parameters for each crossing, so there will be 3πindependent parameters in total, whereπis the number of crossings of the knot diagram. It should be noted that the parametrizedπ -matrices donotsatisfy either Yang-Baxter relation or unitarity. In particular,Risnotthe inverse matrix ofRβ1;
we are abusing the notation for convenience. The significance of the parametrized π -matrix comes from the fact that they induce an algebra morphism in the following way. Denoting the vectorπ£πβπ£π by a monomialπ§π
1π§
π
2, we see that R(π§π
1π§
π
2) =(πΎ π§
1+π½ π§
2)π(πΌ π§
1)π =R(π§
1)πR(π§
2)π, Rβ1(π§π
1π§
π
2) =(πΌ π§
2)π(π½ π§
1+πΎ π§
2)π =Rβ1(π§
1)πRβ1(π§
2)π.
Put in a slightly different language, this means that the parametrized π -matrices induce a model of random walk of free bosons on the knot diagram. It follows from the theorem of Foata and Zeilberger [FZ99] (see also [LW01] for an exposition of Foata-Zeilberger formula) that the result of this state sum is
Z({πΌ},{π½},{πΎ})= 1
det(πΌβ B), (3.11)
whereBis the transition matrix of this model of random walk. That is,Bis theπΓπ matrix whereπis the number of internal arcs of the knot diagram, and it records the probability (or the weight) of a boson to jump from one arc to another. The weight is determined by the corresponding entry of the matrixRorRβ1, with (π, π) = (0,1) or (1,0)and(πβ², πβ²) = (0,1)or(1,0). From the definition of the transition matrix, it is easy to see that the denominator, det(πΌ β B), can be expressed in the following way.
det(πΌβ B) =βοΈ
π
(β1)|π|π(π), (3.12) where the sum ranges over all simple multi-cyclesπ,|π|is the number of components of the multi-cycleπ, andπ(π)denotes the weight ofπ. Let us clarify some of the terminologies. Acycle is a cyclic path (without a starting point or an end point) on the knot diagram as an oriented graph. Amulti-cycleis an unordered tuple of cycles. We call a multi-cyclesimpleif it uses each arc at most once. Since it counts simple multi-cycles (with weights), det(πΌβ B) can be obtained as a result of a state sum where the space of spin states is spanned by 0 and 1, instead of all non-negative integers, as long as we keep track of the sign(β1)|π|. In this sense, det(πΌβ B) can be obtained as a state sum in a system of random walk of free fermions.
The argument we are about to present applies to all nice diagrams, but for simplicity of exposition, letβs assume that our oriented knot diagram is given by a homogeneous braid diagram. With the canonical inversion datum for this homogeneous braid diagram, each crossing will look like one of the four types in Figure 3.12. The
β-signed arcs are the ones whose orientations get inverted in the inversion datum.
The signπ is given by
Figure 3.12: Four possible types of crossings
π =(β1)(# of columns with negative crossings)+(# of(π Λβ1)β,ββ,βcrossings)
.
Now letβs βinvertβ this model of random walk. That is, we consider the inverted state sum, but usingRandRβ1instead Λπ and Λπ β1. Explicitly, the four types of crossings are given by
R++,+,+ :πΏπ+π ,πβ²+πβ²
π πβ²
πΌππ½π
β²
πΎπβπ
β²
, (3.13)
Rβ,+β,+ :πΏπ+π ,πβ²+πβ²πΎβ1
πβ²+ (βπβ1) πβ²
πΌπ(βπ½)πβ²πΎβ(βπβ1)βπ
β²
, (Rβ1)++,β,β :πΏπ+π ,πβ²+πβ²πΎβ1
πβ²+ (βπ β1) πβ²
πΌπ(βπ½)πβ²πΎβπ
β²β(βπβ1)
, (Rβ1)ββ,β,β :πΏπ+π ,πβ²+πβ²πΌβ1π½β1
βπβ²β1
βπ β1
πΌβ(βπβ1)π½β(βπ
β²β1)(βπΎ)(βπβ²β1)β(βπβ1).
Extracting out the factorsπΎβ1andπΌβ1π½β1to normalize these βinvertedβ parametrized π -matrices, we see that this again gives a model of random walk of free bosons. This can be best described with what we call βhighway diagrams." Before inversion, the highway diagrams for the positive and the negative crossing look like Figure3.13.
Note the arcs connecting the over-strand with the under-strand. They denote the
Figure 3.13: Highway diagrams for the positive and the negative crossing.
way the bosons can move; they can move from the over-strand to the under-strand, but not the other way around. After inverting some of the indices according to the four types of crossings as in Figure3.12, we can make a change of variables to the inverted indices and useπ
inv :=βπ β1 βZβ₯0instead of π βZ<0for each inverted index π (π, π,πβ², or πβ²). The effect of this change of variables to the diagram is to
invert the orientation of the inverted arcs. As a result, the inverted highway diagrams for the four types of crossings look like Figure 3.14. The inverted parametrized
Figure 3.14: Inverted highway diagrams for the four types of crossings.
π -matrices can now be thought of as the maps from the incoming strands to the outgoing strands. After extracting out the pre-factor (πΎβ1forRββ,+,+ and(Rβ1)+,β+,β, and πΌβ1π½β1for(Rβ1)β,ββ,β), each of these maps induce an algebra morphism in the sense we discussed above. For instance, in case ofπΎRββ.+,+, denoting the vectorπ€πβ²
inv
βπ£π by a monomialπ§
πβ²
inv
1 π§
π
2, we see that πΎR(π§
πβ²
inv
1
π§π
2) = (πΎβ1π§
1βπ½πΎβ1π§
2)πβ²inv(πΌπΎβ1π§
1βπΌ π½πΎβ1π§
2)π = (πΎR(π§
1))πβ²inv(πΎR(π§
2))π. It follows that the result of the state sum of this new model of random walk of free bosons is
Zinv({πΌ},{π½},{πΎ}) = Γ
π2
πΎβ1Γ
π3
πΎβ1Γ
π4
πΌβ1π½β1
det(πΌ β Binv) , (3.14) whereBinv is the transition matrix of this new model of random walk (determined by R++,+,+, πΎRβ
,+
β,+, πΎR+
,β
+,β, πΌ π½Rββ,β
,β), and the term in the numerator denotes the product of πΎβ1for each crossing of the second and the third type multiplied by the product of πΌβ1π½β1for each crossing of the fourth type, basically pulling out the pre-factor.
We will prove the following lemma.
Lemma 3.3.2.
Z({πΌ},{π½},{πΎ})=πZinv({πΌ},{π½},{πΎ}). (3.15) To prove the lemma, letβs compare the denominators, det(πΌβ B) and det(πΌβ Binv). Recall from (3.12) that each of these determinants can be understood as the weighted sum over all simple multi-cycles. So our strategy is to find a one-to-one correspon- dence between the set of all simple multi-cycles in the first model of random walk of free fermions and that of the second model. A crucial observation is the following correspondence.
Proposition 3.3.3. Forπ, πβ², π , πβ² β {0,1}, there is a correspondence between the parametrizedπ -matrix and its inverted version , as in Figure3.15.
Figure 3.15: The correspondence between the parametrized π -matrix and its inversion.
This can be proved by checking all the cases. There are two cases we need to be a little careful of. Those are when π, π , πβ², πβ² are all 1 in the crossing of the type eitherRβ,+β,+ orR+,β+,β. In those cases, the right-hand side of the equations in Figure 3.15are zero, but naively the inverted parametrizedπ -matrices (3.13) themselves are non-zero. This is okay, and in fact when we consider the fermionic model that computes det(πΌβ Binv)(instead of the bosonic model that computes its inverse), it is more natural to set the value of the matricesRββ,+,+ andR++,β,βto be 0 whenπ, π , πβ², πβ²are all 1. This is because in those types of crossing, whenπ, π , πβ², πβ²are all 1, then there are two different ways to make it into a simple multi-cycle. That is, there are two different simple multi-cycles realizing that configuration. For instance, in the case of Rβ,+β,+, we can either connectπβ²to πβ²and π toπ, or we can connectπβ²toπand π to πβ². Moreover, one of the two simple multi-cycles have one more component than the other. Since we are counting simple multi-cycles with weight and sign as in3.12, the contribution of that configuration is 0. Therefore in this fermionic modelRβ,+β,+ and R++,β,βare zero whenπ, π , πβ², πβ²are all 1, and this proves the proposition.
We are now ready to compare det(πΌβ B) with det(πΌβ Binv). Letπ· andπ·
invbe the highway diagrams for the original knot diagram and its inversion. Any multi-cycles in eitherπ·orπ·
invcan be thought of as a configuration of 0βs and 1βs on the diagram.
Moreover, any such configuration that has a non-zero weight uniquely determines the simple multi-cycle. Following the rule as in Figure3.15, for each simple multi-cycle πinπ·, there is a corresponding multi-cycleπ
inv inπ·
inv and vice versa. Even their weights agree, up to a simple factor as given in Figure3.15. We need to carefully study these extra factors. The factors πΎβ1 and πΌβ1π½β1 give an overall factor of
Γ
π2
πΎβ1Γ
π3
πΎβ1Γ
π4
πΌβ1π½β1, which gets cancelled out with the numerator of (3.14).
Letβs take a careful look at the sign factors. We claim that the overall sign factor agrees with (β1)|π|β|πinv|π. The basic idea is the following. Suppose we have π number of disjoint intervals on a circle, and suppose that the ends of the intervals are connected in a certain way so that they form a collection of cycles. If we change the set of intervals on the circle to their complement, then the resulting number of cycles and the original number of cycles have the same parity ifπis odd, and they have the opposite parity ifπis even. See Figure3.16as an illustration. This is exactly what
Figure 3.16: The change of parity of the number of components as we invert the circle.
happens when we invert a column of a knot diagram. Under the correspondence in Figure3.15, 0βs and 1βs in a column labeled withβsigns change place. So, for instance, if we have a column labeled withβsigns and if the adjacent columns are labeled with+signs, then a typical picture would be something like Figure3.17. In the figure, the column we are inverting is highlighted with a green stripe, and this is the one that plays the role of the circle in Figure3.16. A part of a typical multi-cycle is drawn with red lines. As pointed out above, the change of parity of the number of components of the multi-cycle is determined by the parity of the red intervals in the green stripe. The number of such intervals equals the number of red outgoing strands from the green stripe, which is the sum ofπβ²βs for the crossings on the left edge of the stripe plus the sum of πβ²βs for the crossings on the right edge of the stripe.
More generally, there can be some number of columns labeled withβsigns that are adjacent to each other. In that case, the number of circles is not just the number of columns that we invert, because some of the circles are connected through crossings of type(Rβ1)β,ββ,βwith either (π, π , πβ², πβ²)= (1,0,0,1), (0,1,1,0)or(1,1,1,1). As a result, the parity of the number of circles that we invert has the same parity with the number of columns withβ sign plus the number of such crossings. Note that the number of crossings of type(Rβ1)β,ββ,βwith either(π, π , πβ², πβ²) =(1,0,0,1), (0,1,1,0)
Figure 3.17: Inverting a column labeled withβsign.
or(1,1,1,1)equals the number of all crossings of type(Rβ1)β,ββ,β minus the number of such crossings with (π, π , πβ², πβ²) = (0,1,0,1)(or (1,0,1,0)after inversion). All in all, we have
(β1)change of parity in the # of components = (β1)Γπ2
πβ²+Γ
π3
πβ²+Γ
π4(πβ²βπ)
π , whereΓ
π2
πβ²+Γ
π3
πβ²+Γ
π4(πβ²β π)denotes the sum of πβ²βs for all the crossings of the second type plus the sum ofπβ²βs for all the crossings of the third type plus the sum of(πβ²β π)βs for all the crossings of the fourth type. Comparing with Figure3.15, we see that the overall change of sign in the weight of any multi-cycle is justπ. This concludes the proof of Lemma3.3.2.
In the classical limit, theπ -matrices Λπ (π₯)and Λπ β1(π₯)can be obtained by specializing the parameters of the parametrized π -matrix. More precisely,
Λ π (π₯)πβ², πβ²
π, π
π=1
=R(πΌ, π½, πΎ)πβ², πβ²
π, π
πΌ=π₯β
1 2, π½=π₯β
1
2,πΎ=1βπ₯β1
, (3.16)
Λ
π β1(π₯)πβ², πβ²
π, π
π=1
=Rβ1(πΌ, π½, πΎ)πβ², πβ²
π, π
πΌ=π₯
1 2, π½=π₯
1 2,πΎ=1βπ₯
.
This fact, combined with Lemma3.3.2, immediately proves that the classical limit of π π(π· , πΌ) agrees with ΞπΏ1(π₯), whereΞπΏ(π₯) denotes the Alexander polynomial of πΏ. The rest of the proof follows easily from what Rozansky proved in [Roz98]; there exists a differential operator π·πin the parameters {πΌ},{π½},{πΎ} with polynomial
coefficients such that the coefficient ofβπin the Melvin-Morton-Rozansky expansion is
π·πZ({πΌ},{π½},{πΎ})
specialize{πΌ},{π½},{πΎ}according to (3.16)
. (3.17)
The way it is proved is by observing that theβ-expansion of Λπ (π₯)can be obtained by acting a certain differential operator inπΌ, π½, πΎ toR(πΌ, π½, πΎ) and then specializing these parameters. It is easy to see that the differential operator for the π -matrix remains the same even when we invert some of the indices, and it follows that the operator π·π itself remains the same under inversion. So the corresponding βπ-coefficient for the inverted state sum is given by
(β1)π π·πZinv({πΌ},{π½},{πΎ})
specialize{πΌ},{π½},{πΎ}according to (3.16)
. (3.18)
By Lemma3.3.2, (3.17) and (3.18) are the same as rational functions. This finishes
the proof of Theorem3.3.1. β‘
Remark 3.3.4. It is important to note that (3.17) is a power series in (1βπ₯)while (3.18) is a power series in π₯β1. In other words, a state sum and its inversion are typically defined in a different domain; one nearπ₯ =1 and the other nearπ₯ =β(or π₯ =0 if we had started with the lowest weight Verma module). For this reason, they canβt be compared directly. This is why even though a lot is known about the integral form of the Melvin-Morton-Rozansky expansion cyclotomically (see e.g., [Hab02;
Hab07;Wil22]), it has been a challenge to find its integral form nearπ₯ =0 orπ₯ =β as [GM21] conjectured.
In the above proof, we circumvented the issue of having different domains of convergence by making use of the fact that they can both be expressed as rational functions and showed that the two rational functions are the same.
Remark 3.3.5. The effect of the sign factor on the positive and negative stabilization moves can be summarized as in Figure3.18.
Remark 3.3.6. When specialized according to (3.16), the equation (3.12) becomes Murakamiβs state sum expression for the (multi-variable) Alexander polynomial [Mar05]. In Murakamiβs state sum model, the space of spin states is a 2-dimensional super-vector spaceπ =span{π£
0, π£
1}whereπ£
0has even degree andπ£
1has odd degree.
The trace is replaced by the super-trace, and one of the π -matrix element has an extraβsign. The set ofπ£
1-colored arcs form a simple multi-cycle, and the number of components is counted by the signs coming from the super-trace and theπ -matrix element.
Figure 3.18: Sign factors under stabilizations.
C h a p t e r 4
DEHN SURGERY
In the previous chapter we have studied how to define and compute Λπ for various link complements. In this chapter, we turn our attention to Dehn surgery, in order to glue in solid tori along the boundaries of those link complements.
The most basic form of the surgery formula is (2.5) [GM21, Conjecture 1.7], which we expect to be true for all knots, wheneverβπ
π is big enough (where
π
π is the Dehn surgery coefficient). There is a natural generalization for links.
Conjecture 4.0.1. Let π3
π1,Β·Β·Β·, ππ(πΏ) be the 3-manifold obtained by performing the (π
1,Β· Β· Β· , ππ)-surgery onπΏ β π3, and letπ΅be theπΓπ linking matrix defined by π΅π π =


ο£²

ο£³
ππ ifπ = π π π(π, π) otherwise
. (4.1)
LetLπ
π΅ be the βLaplace transformβ defined by Lππ΅ :π₯π’β¦β


ο£²

ο£³ πβ(π’, π΅
β1π’) ifπ’ βπ+π΅Zπ
0 otherwise
. (4.2)
Then1 Λ π
π3π
1,Β·Β·Β·, π
π(πΏ),π(π) Lπ
π΅
(π₯
1 2
1 βπ₯
β1
2
1 ) Β· Β· Β· (π₯
1 2
π βπ₯
β1
2
π )πΉπΏ(π₯
1,Β· Β· Β· , π₯π, π)
, (4.3) whenever the smallest eigenvalue ofβπ΅β1is big enough so that the right-hand side converges.
Remark 4.0.2. The range of surgery coefficients for which this Dehn surgery formula is applicable is closely related to the rate of quadratic growth of the order ofπ(i.e., the minimalπ-degree) of the coefficients ofπΉπΎ(π₯ , π). More precisely, for any knot πΎ, if we define
ππΎ :=lim inf
πββ
ordπππ(π) π2
,
1Here,denotes equality up to a sign and a shift in overallπ-degree. That is, π πiff π =π πππ for some signπβ {Β±1}andπ βQ.
where ππ(π) is the coefficient of π₯π+12 in πΉπΎ(π₯ , π), then the right-hand side of the surgery formula converges whenever whenever βπ/π1 +ππΎ > 0. It would be very interesting to understand how the invariantππΎ is related to some other known invariants of knots, such as the boundary slopes of theπ΄-polynomial Newton polygon.
Assuming Conjecture4.0.1and its consistency, one can deduce formulas for partial Dehn surgery (i.e., performing Dehn surgery only on some strands of a link). In particular, the following partial small surgery formula is often useful:
Conjecture 4.0.3. Let πΏ be a link with componentsπΏ
0, πΏ
1,Β· Β· Β· , πΏπ, withπΏ
0being an unknot. LetπΏβ²be the link obtained by performing theβ1
π-surgery onπΏ
0. Then πΉπΏβ²(π₯
1,Β· Β· Β· , π₯π, π) L
(π₯
1 2π
0 βπ₯
β1
2π
0 )πΉπΏ(π₯
0,Β· Β· Β· , π₯π, π)
(4.4) wheneverπ is big enough so that the right-hand side converges, where
L :π₯π’
0 β¦β ππ π’
2 Γ
1β€πβ€π
π₯
π π(πΏπ, πΏ
0)π π’
π . (4.5)
This partial Dehn surgery formula was used in [Par20b] to reverse-engineerπΉπΏ for the Whitehead link and the Borromean rings, from the double twist knots, and the result is consistent with Examples3.2.7and3.2.8.
While the Dehn surgery formulas we have just reviewed are nice, they are limited to the surgeries for which the minus of the inverse of the surgery coefficient is big enough. In the rest of this chapter, we present some hints and ideas toward overcoming this issue. The main observation is that the two-variable seriesπΉπΎ(π₯ , π) can be expanded in a form that we call theinverted Habiro series, and that in this form there are some niceπ-series identities that allow us to go beyond the range of surgery coefficients that we were limited to.
4.1 Inverted Habiro series
It is a well-known theorem of Habiro [Hab02] that for any knotπΎ, there is a sequence of Laurent polynomialsππ(πΎ) βZ[π, πβ1]such that the colored Jones polynomials π½πΎ(ππ), colored by theπ-dimensional irreducible representationππofπ°π©2, can be decomposed as
π½πΎ(ππ)=
β
βοΈ
π=0
ππ(πΎ)
π
Γ
π=1
(π₯+π₯β1βππβπβπ) π₯=ππ
.
The purpose of this section is to make a curious observation that for some simple knots and links, the sequence {ππ(πΎ)}πβ₯0 can be naturally extended to negative values ofπ. The simplest example is the figure-eight knot. In this case we have ππ(41) =1 for anyπ β₯0, so it is very natural to setππ(41) =1 for anyπ βZ. Once we have such an extension of the sequence {ππ(πΎ)}, we can βinvert" the Habiro series in the following way:
β
βοΈ
π=0
ππ(πΎ)
π
Γ
π=1
(π₯+π₯β1βππ βπβπ) { β
β
βοΈ
π=1
πβπ(πΎ) Γπβ1
π=0(π₯+π₯β1βππ βπβπ) . The series on the right-hand side is what we will call aninverted Habiro series. As we will see through examples, ππ(πΎ) withπ < 0 are in general not necessarily Laurent polynomials, but rather Laurent power series inπwith integer coefficients.
A priori the βinverted Habiro series" is a very different object compared to the original Habiro series. For one thing, the specializationπ₯=ππdoesnβt make sense any more for the inverted Habiro series, as it has poles atπZ. For another thing, the inverted Habiro series can be expanded into a power series inπ₯orπ₯β1, which is not possible for the usual Habiro series. The distinction is clearer in the classical limitπ β 1 where the usual Habiro series take values inZ[[π₯+π₯β1β2]] (a completion at a finite placeπ₯+π₯β1 = 2) whereas the inverted Habiro series take values inQ[[π₯+π₯1β
1β2]]
(a completion at an infinite placeπ₯+π₯β1 =β). Morally, this is the same as what we did in the previous section; whether it is a state sum or a Habiro series, we are inverting it to make it convergent nearπ₯+π₯β1=β.
We conjecture thatπΉπΎ can be thought of as the inverted Habiro series.
Conjecture 4.1.1. For any knotπΎ withΞπΎ(π₯) β 1, it has an inverted Habiro series, and it agrees with theπΉπΎ in the sense that
πΉπΎ(π₯ , π) =β(π₯
1 2 βπ₯β
1 2)
β
βοΈ
π=1
πβπ(πΎ) Γπβ1
π=0(π₯+π₯β1βππ βπβπ) when the right-hand side is expanded into a power series inπ₯.
Remark 4.1.2. In this conjecture, we have imposed the condition that degΞπΎ(π₯) > 0 to make sure that ΞπΎ1(π₯) =π(π₯) as a power series inπ₯.
The following identity allows us to transform a power series inπ₯ into an inverted Habiro series and vice versa.