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Inner approximations for pseudospectra of block triangular matrices

2.2 The general case

Example 2.1.7. Consider the matrices Aâ=

−2 0 0 1 +i

, A=

−2 9 + 8i 0 1 +i

with ε = 1.7, the value of ε˜= f(ε)ε from Theorem 2.1.4 is calculated to be 3.5720.

This is shown in Figure 2.1.2(right).

-1.5 -1 -0.5 0 0.5 1 1.5

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1

Figure 2.1.2: Λε(A),â Λε˜(A)â and Λε(A) along with the spectrum • for Exam- ple 2.1.6(left) and Example 2.1.7(right).

28 2.2. The general case

Aâ =

a11 c11

0 b11

a22 c22

0 b22

a33 c33

0 b33

andP =

1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1

.

Consequently,

σmin(AzI) =σmin(AâzI) = min

1j3σmin(TjzI), where Tj =

ajj cjj

0 bjj

; j ∈ {1,2,3} so that Λε(A) = Λε(A) =â

Û3 j=1

Λε(Tj). Let ε > 0 be arbitrary. For each j = 1,2,3, let εj > ε be the optimal value from Theorem 2.1.4 such that Dεj(ajj)∪Dεj(bjj) ⊆Λε(Tj). If ε0 := min{ε˜1˜2˜3}, then

Û3 j=1

(Dε0(ajj)∪Dε0(bjj)) ⊆ Λε(A) is an optimal inner approximation of Λε(A) via pseudospectra levels corresponding to its diagonal entries.

However, there are cases where it can be proved that Λε(A)â is the optimal inner approximation of Λε(A). One such situation is identified in the next theorem.

Theorem 2.2.1. Suppose L ∈ Cm,m, M ∈ Cm,m such that Aâ =

L 0 0 M

is a normal matrix. If one of the eigenvectors ofLbelongs to the left null space ofC or one of the eigenvectors ofM belongs to the right null space of C, then forA =

L C 0 M

and any given ε > 0, Λε(A)â ⊆ Λε(A) is such that Λε(A)â has a common boundary point with Λε(A).

Proof. Suppose that L has an eigenvector v corresponding to an eigenvalue λ such thatvC = 0.AsAâis a normal matrix, so areLandM.Therefore, there exist unitary matrices V1 and V2 and diagonal matrices DL and DM such that L = V1DLV1 and M = V2DMV2. Also we may assume without loss of generality that v is the first column of V1. Therefore, setting S =

V1 0 0 V2

, and Câ = V1CV2, it is easy to see that the first row and first column of SAS are given by è λ 0 · · · 0 é and

è λ 0 · · · 0 éT respectively. This implies that the disc with centre atλand radius ε is common to bothΛε(A)and Λε(A).â The proof for the case that an eigenvector of M, belongs to the right nullspace of C follows with similar arguments. Hence, the proof.

If A satisfies the hypothesis of Theorem 2.2.1, then Λε(A)â is a good inner ap- proximation of Λε(A) as it consists of discs of radius ε centered at the eigenvalues of A that reach upto the boundary of Λε(A). Thus without loss of generality, we consider an Athat does not satisfy the properties of Theorem 2.2.1. Theorem 2.2.2, Lemma 2.2.3 and Corollary 2.2.4 provide a means of finding the desired inner ap- proximations for the case when the diagonal blocks L, M are square matrices of the same size. Throughout we assume C to be non-singular.

Theorem 2.2.2. Suppose Aâand Aare as given in (2.0.1) withü=m andC ∈Cm,m is non-singular. Then

..

.(AzI)1...

2...(MzI)1...

2

ñ

1 +ëC1(LzI22, (2.2.1) and ...(AzI)1...

2...(LzI)1...

2

ñ

1 +ëC1(MzI22. (2.2.2) Proof. For z ∈ C\(Λ(L)∪Λ(M)), let vmin(z), umin(z) ∈ Cm denote right and left singular vectors of MzI corresponding to σmin(MzI)respectively. Then

..

.(AzI)1...

2 =

.. .. ..

(LzI)1 −(LzI)1C(MzI)1

0 (MzI)1

.. .. ..

2

.. .. ..

(LzI)1 −(LzI)1C(MzI)1

0 (MzI)1

0

umin(z)

.. .. ..2

=

.. .. ..

− ë(MzI)1ë2(LzI)1Cvmin(z) ë(MzI)1ë2vmin(z)

.. .. ..

2

=...(MzI)1...

2

ñ

ëvmin(z22+ë(LzI)1Cvmin(z22

=...(MzI)1...

2

ñ

1 +ë(LzI)1Cvmin(z22

...(MzI)1...

2

ñ1 +σmin2 ((LzI)1C)

...(MzI)1...

2

ñ

1 + ëC1(LzI22. In a similar way, one can derive the second inequality.

For z ∈ Λε(A), ëC1(LzI2 ≤ ëC1ë2Aë2Lë2 +ε). Since our aim is to approximate the ε-pseudospectra of A by ε(> ε)˜ level pseudospectra of both L and M. So for the matrix M, if γ(z) := ñ1 +ëC1(LzI22 then the aim is to obtain a lower bound γ > 1 of γ(z) such that ë(MzI)1ë2γε1 implies that ë(AzI)1ë21ε. With this aim in view, we have the following result.

Lemma 2.2.3. Suppose L, M and C are as described in Theorem 2.2.2. Let σmin(C)>0 and z0 ∈C. For α >1, if

r(α) :=σmin(C)

A 1

α2 −1 −...C1(Lz0I)...

2

B

, (2.2.3)

30 2.2. The general case then for any ε >0,

D(z0, r(α))∩Λαε(M)⊆Λε

L C 0 M

. Proof. Let zD(z0, r(α)). Then,

..

.C1(LzI)...

2 ≤ |zz0|...C1...

2 +...C1(Lz0I)...

2r(α)

σmin(C)+...C1(Lz0I)...

2

= 1

α2−1 :=R.

Therefore, α =ñ1 + R12 and using Theorem 2.2.2, we obtain for zD(z0, r(α)),

.. .. .. .

LzI C 0 MzI

1.......

2

...(MzI)1...

2

öõ

õô1 + 1

ëC1(LzI22

...(MzI)1...

2

ó

1 + 1 R2

= α...(MzI)1...

2. Therefore, zD(z0, r(α))∩Λαε(M) =⇒

.. .. .. .

LzI C 0 MzI

1.......

2

1ε.

Corollary 2.2.4. Suppose Aâ and A are as given in Theorem 2.2.2. Let ε > 0 and z0, zˆ0 ∈C. Choose RL(α)>0 and RM(α)>0 such that

Λαε(L)⊆D(z0, RL(α)) and Λαε(M)⊆Dz0, RM(α)).

Choose α1 such that RL(α1) = σmin(C)

31

α211 − ëC1(Mz0I2

4

and α2 such that RM(α2) = σmin(C)

31

α221 − ëC1(Lzˆ0I2

4

. Then α0 := min{α1, α2} > 1 and Λα0ε(A)â ⊆Λε(A).

Proof. AsRM(α)>0is such thatΛαε(M)⊆Dz0, RM(α)),by Lemma 2.2.3 for this particular choice of α2 we have Λα2ε(M) ⊆ Λε(A). Similarly, by interchanging the roles of L and M, we get α1 such that Λα1ε(L) ⊆Λε(A). From simple calculations, it is clear that

α1 =

öõ õô1 +

A σmin(C)

RL(α1) +σmin(CC1(Mz0I2

B2

and

α2 =

öõ õô1 +

A σmin(C)

RM(α2) +σmin(CC1(Lzˆ0I2

B2

. Therefore, Λα0ε(A)â ⊆Λε(A) for α0 = min{α1, α2}>1.

We seek a suitable centrez0 and radiiRL(α1), RM(α)for the discs containing the αε-pseudospectra of the diagonal blocks. From the definition ofr(α), it can be seen that α is inversely proportional to r(α). So in order to increase α, we choose the pointzˆ0 and RM(α)suitably so thatDz0, RM(α))is a tight outer approximation for Λαε(M).

The αε-pseudospectrum of M is contained in the disc centered at zˆ0 of radius ëMzˆ0Ië2 +αε. This follows since for z ∈ Λαε(M) we have z ∈ Λ(M +E) for some E ∈ Cn,n with ëEë2ε. This gives zzˆ0 ∈ Λ(M +Ezˆ0I) which implies

|zzˆ0| ≤ ëMzˆ0Ië2+αε. Thus,

Λαε(M) = Λαε(M)∩Dz0,ëMzˆ0Ië2+αε)⊆Λε

L C 0 M

, (2.2.4) and also replacing αε by a larger quantity 1

α2−1 + 12ε, Λαε(M) = Λαε(M)∩Dz0,ëMzˆ0Ië2 +ε(√

α2−1 + 1))⊆Λε

L C 0 M

. (2.2.5) For finding a suitable α, we first take RM(α) = ëMzˆ0Ië2 +αε and equate it with r(α). Then any solution of RM(α) =r(α)is the largest positive solution of the quartic equation

x4+ 2p3x3+p2x2+ 2p1x+p0 = 0 (2.2.6) where

p3 = σmin(CC1(Lzˆ0I2Mzˆ0Ië2

ε ,

p2 = (σmin(CC1(Lzˆ0I2Mzˆ0Ië2)2ε2

ε2 ,

p1 = −σmin(CC1(Lzˆ0I2Mzˆ0Ië2

ε ,

and p0 = −(σmin(CC1(Lzˆ0I2Mzˆ0Ië2)2+σ2min(C)

ε2 .

Since p3 > 0 and p0 < 0, there exists α0 >0 such that RM(α0) = r(α0). Similarly, taking RM(α) =ëMzˆ0Ië2 +ε(√

α2−1 + 1), we have RM(α0) =r(α0) for

α0 =ñβ2+ 1, (2.2.7)

where β =−F2 +12ñF2+ 4σminε(C) for F := σmin(C)ëC−1(Lzˆ0I)ë2+ëMzˆ0Ië2+ε

ε .

A suitable α > 1 such that Λαε(L) ⊆ Λε(A) is computed by using an identi- cal strategy. One can also obtain α by replacing the discs Dz0,ëMzˆ0Ië2 +αε) and Dz0,ëMzˆ0Ië2+ε(√

α2−1 + 1)) in (2.2.4) and (2.2.5) by discs arising from

32 2.2. The general case Bauer-Fike and Gersgorin inclusion regions. However, the quality of the inner ap- proximations using the inclusions from (2.2.4) and (2.2.5) appear to be better than the ones from these strategies. Clearly, the value of α also depends on the choice of the point zˆ0. One strategy is to choose zˆ0 as the center of the smallest disc containing the eigenvalues of the matrix M. We obtain this by using the CVX tool- box [23] in Matlab. Notice that in (2.2.7), α is a monotonically increasing function of σmin(CC1(Lzˆ0I2Mzˆ0Ië2.So another strategy is to choose zˆ0 to be the point which minimizes the convex functionσmin(CC1(LzI2MzIë2. The following examples illustrate the outcome of both strategies.

Example 2.2.5. Let A and Aâ be as in (2.0.1) where

L=

77.29063 0.6551 0.9597 0.7513 0.7547 77.8374 0.3404 0.2551 0.2760 0.1190 77.4147 0.5060 0.6797 0.4984 0.2238 77.3009

, M =

55.1091 0.1493 0.8143 0.1966 0.9593 55.7425 0.2435 0.2511 0.5472 0.8407 55.0707 0.6160 0.1386 0.2543 0.3500 55.5267

,

and C =

88.6483 0.9172 0.3804 0.5308 0.8308 88.7142 0.5678 0.7792 0.5853 0.7572 88.9241 0.9340 0.5497 0.7537 0.0540 88.8701

and ε = 1.5. We choose z0 and zˆ0 to be the center of the smallest disc containing the eigenvalues of L and M respectively. The value of ε˜= α0ε where α0 is a root of (2.2.6) is 4.6936. If ε˜= α0ε where α0 is given by (2.2.7) then ε˜= 4.5421. The corresponding pseudospectra levels are shown in Figure 2.2.1 and Figure 2.2.2.

Next, we selectz0 to be the point minimizing the functionσmin(CC1(MzI2

LzIë2andzˆ0to be the one that minimizesσmin(CC1(LzI2MzIë2. Then ε˜=α0ε= 4.7131when α0 is a root of equation (2.2.6), while ε˜=α0ε= 4.5603 whenα0 satisfies (2.2.7). This is illustrated in Figure 2.2.3 and Figure 2.2.4, respec- tively.

-80 -75 -70 -65 -60 -55 -50

-8 -6 -4 -2 0 2 4 6 8

Figure 2.2.1: Λε(A),â Λε(A) and Λα0ε(A),â for ε = 1.5 and α0ε = 4.6936. The eigenvalues of A are marked by •.

-80 -75 -70 -65 -60 -55 -50 -8

-6 -4 -2 0 2 4 6 8

Figure 2.2.2: Λε(A),â Λε(A) and Λα0ε(A),â where ε = 1.5 and α0ε= 4.5421. The eigenvalues of A are marked by •.

-80 -75 -70 -65 -60 -55 -50

-8 -6 -4 -2 0 2 4 6 8

Figure 2.2.3: Λε(A),â Λε(A) and Λα0ε(A),â where ε = 1.5 and α0ε = 4.7131 for Example 2.2.5. The eigenvalues of A are marked by •.

-80 -75 -70 -65 -60 -55 -50

-8 -6 -4 -2 0 2 4 6 8

Figure 2.2.4: Λε(A),â Λε(A) and Λα0ε(A),â where ε = 1.5 and α0ε = 4.5603 for Example 2.2.5. The eigenvalues of A are marked by •.

34 2.2. The general case If M is a normal matrix and zˆ0 is chosen to be the center of the smallest disc containing the eigenvalues of M, then Dz0,ëMzˆ0Ië2 +αε) is also the smallest disc containing Λαε(M). This ensures that the radius r(α) cannot be made smaller than ëMzˆ0Ië2+αε for normal matrices.

Proposition 2.2.6. Let M ∈ Cm,m be a normal matrix and suppose z0 ∈ C is the center of the smallest disc containing the eigenvalues ofM.ThenD(z0,ëMz0Ië2+ αε) is the smallest disc containing Λαε(M).

α λ1 ˆ

λ1 z0

Figure 2.2.5: Spectrum and pseudospectrum for a normal matrix.

Proof. Since Λαε(M)⊆D(z0,ëMz0Ië2 +αε), it suffices to show there are points on the boundary of the disc D(z0,ëMz0Ië2 +αε) belonging to Λαε(M). Let λ1

be any eigenvalue of M on the boundary of the smallest disc centered at z0 that contains all the eigenvalues of M as shown in Figure 2.2.5. The existence of at least one such eigenvalue of M is ensured by the choice of z0. Sinceλ1z0 ∈Λ(Mz0I) and Mz0I is normal, so |λ1z0| = ëMz0Ië2. Consider the point λˆ1 on the boundary of the discD(z0,ëMz0Ië2+αε)obtained by extending the straight line joiningλ1 andz0. Clearly,λ1 is the closest eigenvalue ofM toλˆ1 and---λˆ1λ1

--

-=α0ε.

Let E :=−σmin(Mλˆ1I)uv, where u and v are the left and right singular vectors corresponding to the minimum singular value of M−ˆλ1I, thenλˆ1 ∈Λ(M+E)with

ëEë2 =σmin(M −ˆλ1I) = min

λΛ(M)|λ−ˆλ1|=|λ1−ˆλ1|=αε.

So ˆλ1 ∈Λαε(M) and hence the proof.

We have the following example as an illustration of Proposition 2.2.6.

Example 2.2.7. Let A and Aâ be as in (2.0.1) where L and M are normal matrices given by

L=

4.5976 0.7910 0.0366 0.2508 0.0065 0.7910 4.8848 0.4335 0.1206 0.5339 0.0366 0.4335 4.6619 0.0631 0.2296

0.2508 0.1206 0.0631 4.3691 0.8024 0.0065 0.5339 0.2296 0.8024 4.7638

,

M =

6.0069 0.3399 0.1542 0.2773 0.1958

0.3399 7.3751 0.7132 0.6721 0.8094 0.1542 0.7132 6.2306 1.0102 0.5780

0.2773 0.6721 1.0102 7.2276 0.5225 0.1958 0.8094 0.5780 0.5225 5.7072

,

and

C =

120.9716 0.0396 0.9554 0.0050 0.7673 0.3609 120.4694 0.7242 0.7825 0.9971 0.6442 0.1501 120.5809 0.9269 0.2277 0.0679 0.9913 0.5403 120.0083 0.9195 0.20791 0.4271 0.7054 0.8246 120.6420

.

Let ε = 0.1, and z0 and zˆ0 be the centers of optimal discs containing eigenvalues of L and M respectively. Then using (2.2.6) and (2.2.7) gives the values of ε˜as 0.7638 and 0.7595 respectively such that Λε˜(A)â ⊆Λε(A).

If z0 is a minimizer of the convex functionσmin(CC1(MzI2LzIë2

while zˆ0 minimizes σmin(CC1(LzI2MzIë2, using equations (2.2.6) and (2.2.7) also give ε˜to be 0.7638 and 0.7595 respectively such thatΛ˜ε(A)â ⊆Λε(A).

The corresponding pseudospectra levels for Aâ and A are shown in Figures 2.2.6 and 2.2.7.

-10 -8 -6 -4 -2 0 2 4 6

-1.5 -1 -0.5 0 0.5 1 1.5

Figure 2.2.6: Λε(A),â Λε(A) and Λα0ε(A),â for ε = 0.1 and α0ε = 0.7638. The eigenvalues of A are marked by •.

36 2.2. The general case

-10 -5 0 5

-1.5 -1 -0.5 0 0.5 1 1.5

Figure 2.2.7: Λε(A),â Λε(A) and Λα0ε(A),â where ε = 0.1 and α0ε= 0.7595. The eigenvalues of A are marked by •.

Now we come to the case when the diagonal blocksLandM ofAas in (2.0.1) differ in size and C is of full rank i.e., rankC = min{ü, m}. The following theorem allows us to obtain an inner approximation of Λε(A) via some higher level ε-pseudospectra of the smaller of the two diagonal blocks.

Theorem 2.2.8. Suppose Aâ and A are as given in (2.0.1) withü < m and C ∈Cü,m such that rankC=ü. Then

..

.(AzI)1...

2...(LzI)1...

2

ñ

1 + (σmin(C)/ëMzIë2)2. (2.2.8) Proof. Forz ∈C\(Λ(L)∪Λ(M)), and right, left singular vectors vmin(z), umin(z) in Cm of LzI corresponding to σmin(LzI), we have

..

.(AzI)1...

2 =

.. .. ..

(LzI)1 −(LzI)1C(MzI)1

0 (MzI)1

.. .. ..2

.. .. ..

è vmin(z) 0 é

(LzI)1 −(LzI)1C(MzI)1

0 (MzI)1

.. .. ..

2

= ...è ë(LzI)1ë2umin(z) − ë(LzI)1ë2umin(z)C(MzI)1 é...2

= ...(LzI)1...

2

ñ

1 +ëumin(z)C(MzI)1ë22

...(LzI)1...

2

ñ

1 + (σmin(C)/ëMzIë2)2.

Lemma 2.2.9. Let Aâ and A be as described in the statement of Theorem 2.2.8 and suppose σmin(C)>0. Choose any z0 ∈C. For α >1, let

r(α) = 1σmin(C)/

α2−12− ëMz0Ië2. (2.2.9) Then for any ε >0, we have D(z0, r(α))∩Λαε(L)⊆Λε(A).

Proof. The proof is identical to that of Lemma 2.2.3.

Corollary 2.2.10. Let Aâ and A be as in (2.0.1) with ü < m and C ∈ Cü,m such that rankC = ü. Also let r(α) be as in Lemma 2.2.9. Suppose ε > 0, z0 ∈ C and RL(α) > 0 is chosen so that Λαε(L) ⊆ D(z0, RL(α)) for all α > 1. Let α0 be the solution of r(α) =RL(α). Then α0 >1 and we have Λα0ε(L)⊆Λε(A).

Proof. The proof is similar to that of Corollary 2.2.4.

To be able to use the idea of the proof of Theorem 2.2.8, to find ε > ε˜ such that Λε˜(M)⊆Λε(A)whenL,M and C are as assumed in its statement, it is necessary to ensure thatCvmin(z)Ó= 0for any right singular vectorvmin(z)ofMzIcorresponding toσmin(MzI)forz /∈Λ(M). However, this need not hold in general. To see this, let U andV be unitary matrices such that UCV =è Σü×ü 0ü×(mü)

éis an SVD of C.

Since Λε(A)with respect to the norm ë·ë2 is invariant with respect to multiplication of A by unitary matrices, we assume without loss of generality that

A=

L è Σü×ü 0ü×(mü) é

0 M

.

Suppose M =

M1,1 · · · M1,m1 0

0 . .. ... 0

... . .. ... ... Mm1,m1 ...

0 · · · 0 Mm,m

. If the point z is chosen close

to Mm,m, the right singular vector corresponding to σmin(MzI) is vmin(z) = em, therefore Cvmin(z) = 0.

However, it appears that only special values ofzsatisfyCvmin(z) = 0. To see this, assume that the unitary matrix V in the Singular Value Decomposition of C ∈Cü,m is partitioned as V =è V1 V2

é with V1 ∈Cm,ü and V2 ∈Cm,mü where rankC =ü.

If vmin(z), umin(z) ∈ Cm are right, left singular vectors of MzI corresponding to σmin(MzI) respectively, then Cvmin(z) = 0 if and only ifvmin(z)V1 = 0. In cases when none of the z ∈ Λε(A) satisfy this condition, it may be possible to have an inner approximation of Λε(A)via Λαε(M)for some α >1.

Theorem 2.2.11. Let L, M and C be as described in Theorem 2.2.8, and α0 > 1 be as obtained from Corollary 2.2.10. Suppose DM is a disc centered at some zˆ∈C that is large enough, so that Λε(M) ⊆ Λα0ε(M) ⊂ DM. For zDM, let vmin(z) be any right singular vector of MzI corresponding to σmin(MzI) and define

38 2.2. The general case ζ = inf

zDMëCvmin(z2. If ζ >0, then for zDM, we have

..

.(AzI)1...

2...(MzI)1...

2

ñ

1 + (ζ/ëLzIë2)2.

Proof. Let umin(z)∈Cm denote the left singular vector of MzI corresponding to σmin(MzI).Then for z ∈C\(Λ(L)∪Λ(M)), we have

..

.(AzI)1...

2 =

.. .. ..

(LzI)1 −(LzI)1C(MzI)1

0 (MzI)1

.. .. ..

2

.. .. ..

(LzI)1 −(LzI)1C(MzI)1

0 (MzI)1

0

umin(z)

.. .. ..2

=

.. .. ..

− ë(MzI)1ë2(LzI)1Cvmin(z) ë(MzI)1ë2vmin(z)

.. .. ..2

= ...(MzI)1...

2

ñ

1 +ë(LzI)1Cvmin(z22

...(MzI)1...

2

ñ

1 + (ëCvmin(z2/ëLzIë2)2.

which remains valid for all zDM. Since ëCvmin(z2ζ for all zDM, the desired inequality follows.

Lemma 2.2.12. Let L, M and C be as in the statement of Theorem 2.2.8 and suppose σmin(C)>0. For β >1 and z1 ∈C, let

ˆ

r(β) = ζ

β2−1 − ëLz1Ië2.

Also let DM be as in Theorem 2.2.11. Then for any ε >0, we have D(z1,r(β))ˆ ∩(Λβε(M)∩DM)⊆Λε(A).

Proof. LetzD(z1,r(β)). Then,ˆ ëLzIë2r(β) +ˆ ëLz1Ië2 = √ζ

β21.Defining R = √ζ

β21, we have β =

ò

1 +1Rζ22. Therefore, using Theorem 2.2.11, we obtain for zD(z1,r(β))ˆ ∩DM,

.. .. .. .

LzI C 0 MzI

1.......2...(MzI)1...

2

ñ

1 + (ζ/ëLzIë2)2.

...(MzI)1...

2

öõ õô1 +

Aζ R

B2

= β...(MzI)1...

2. Thus z ∈(D(z1,r(β))ˆ ∩DM)∩Λβε(M) =⇒

.. .. .. .

LzI C 0 MzI

1.......

2

1ε.

Now we use the preceding analysis to formulate a strategy for finding aβ >1such that Λβε(M) ⊆ Λε(A). Let α0 be as in Corollary 2.2.10 so that Λα0ε(L) ⊆ Λε(A). Then choosing DM =Dz,ëMzIˆ ë2+α0ε), we have Λα0ε(M) ⊆DM. If we select RM(β) = ëMz1Ië2+βε, thenΛβε(M)∩DMD(z1, RM(β)).Letβ1 be the largest positive solution of the equation RM(β) = ˆr(β) where ˆr(β) is as in Lemma 2.2.12.

In view of this lemma, Λβ1ε(M)∩DM ⊆Λε(A). Alternatively,

DM =Dz,ëMzIˆ ë2+α0ε)⊆D(z1,ëMzIˆ ë2+|zˆ−z1|+α0ε).

Let β2 >1 be such that r(βˆ 2) =ëMzIˆ ë2+|zˆ−z1|+α0ε, so that Lemma 2.2.12 implies Λβ2ε(M)∩DM ⊆ Λε(A). Let β0 := max{β1, β2}, since Λα0ε(M) ⊆ DM, we have Λα0ε(M)⊆Λε(A) if α0β0 and Λβ0ε(M)⊆Λε(A) otherwise.

In numerical experiments, computing the values of α0 and β1 is similar to the ones obtained for the case when ü =m. For finding the value of α0 for L, if we take RL(α) =ëLz0Ië2+αε and equate ther(α)in (2.2.9) withRL(α),so thatα is the largest positive solution of the equation

x4+ 2p3x3+p2x2+ 2p1x+p0 = 0 (2.2.10) where

p3 = (ëLz0Ië2Mz0Ië2)/ε,

p2 = èLz0Ië2Mz0Ië2)2ε2é2, p1 = −(ëLz0Ië2Mz0Ië2)/ε,

and p0 = −èLz0Ië2Mz0Ië2)2+σmin2 (C)é2,

with z0 being chosen as the point minimizing the convex function ëLzIë2 + ëMzIë2. Similarly, β1 is the largest positive solution of the quartic equation

x4+ 2p3x3+p2x2+ 2p1x+ãp0 = 0 (2.2.11) where

ã

p0 =−èLz0Ië2Mz0Ië2)2+ζ2é2. Moreover, it is easy to see that

β2 =

öõ õô

A ζ

ëLz1Ië2MzIˆ ë2+|z1zˆ|+α0ε

B2

+ 1 (2.2.12)

is the solution of r(β) =ˆ ëMzIˆ ë2 +|zˆ−z1|+α0ε, where z1 can be chosen to be the point minimizing the function ëLz1Ië2 +|z1zˆ|. This is illustrated in the following example.

40 2.2. The general case Example 2.2.13. Let A and Aâ be as in Theorem (2.2.8), where

L=

24.9500 0.1411 0.7321 0.5208 0.1582 24.5121 0.7498 0.2191 0.2864 0.7213 24.4073 0.8424 0.6871 0.9288 0.2395 24.6629

, C =

23.8312 0.5386 0.0763 0.2681 0.7039 0.3808 0.9223 23.4633 0.7087 0.8325 0.9323 0.6346 0.32702 0.8208 23.2349 0.9954 0.6876 0.3632 0.8041 0.9519 0.3989 23.6497 0.56835 0.4076

,

M =

20.8162 0.7699 0.8651 0.10704 0.5767 0.8288 0.7938 20.8295 0.06802 0.7242 0.94402 0.3225 0.4691 0.70608 20.9685 0.61369 0.8714 0.97615 0.3095 0.5953 0.0987 20.7829 0.5076 0.2782 0.6875 0.7528 0.5469 0.5666 20.7888 0.07283 0.9868 0.4967 0.4029 0.8113 0.4730 20.7512

,

and ε = 0.9. Let z0 be the point minimizing the function ëLzIë2MzIë2. Solving equation (2.2.10), we obtain α0ε = 2.4110 such that Λα0ε(L) ⊆ Λε(A). For the inner approximation via a suitable ε-pseudospectra level of M, first we choose DM = D(21.5,ëM−21.5Ië2+ 2.411) and z1 as a minimizer of the convex function ëLzIë2MzIë2. Then solving the equation (2.2.11), gives β1ε = 2.1512 so that Λβ1ε(M) ⊆ Λε(A). Next choosing z1 to be the point minimizing the function ëLz1Ië2+|z1zˆ|,equation (2.2.12) gives β2ε= 2.0196 so that Λβ2ε(M)⊆Λε(A).

Thus if β0ε= max{β1ε, β2ε}= 2.1512, and ε˜= min{α0ε, β0ε}=β0ε= 2.1512, then Λε˜(A)â ⊆Λε(A). The corresponding pseudospectra levels are shown in Figure 2.2.8.

16 18 20 22 24 26 28 30

-6 -4 -2 0 2 4 6

Figure 2.2.8: Λε(A),â Λε(A) and Λε˜(A),â where ε = 0.9 and ε˜ = 2.1512 for Example 2.2.13. •denotes the eigenvalues.

3

Localization sets for eigenvalues of homogeneous