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Lemma: For a block matrix of the formM = P Q 0 R , the determinant|M|=|P||R|

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Theorem: The geometric multiplicity of an eigenvalue can not exceed its algebraic multiplicity1. Lemma: For a block matrix of the formM =

P Q 0 R

, the determinant|M|=|P||R|. This can be proved by performing row transformations onM to convert it to an upper triangular formM0 =

P0 Q0 0 R0

(which leaves the determinant unchanged). The determinant of an upper triangular matrix is the product of the diagonal elements, which can be factored into the product of the diagonal elements of P0 and Q0, thus giving us |M|=|M0|=|P0||Q0|=|P||Q|. The last equality follows because row transformations would not have changed the determinants of P, Q. Note that it is important for 0 to have been in the lower left part of M. This way, the row transformations R → R0 involve only the rows of R0 (and not P), and hence leave the determinant of R unchanged.

Proof:

0. Setup: For an n×n matrix A, say that an eigenvalue λ has geometric multiplicity r i.e. there are r linearly independent eigenvectors, {vi}ri=1, corresponding to this eigenvalue (γA(λ) = r).

1. Supplement thesereigenvectors withs =n−radditional vectors,{wi}si=1 such that all thenvectors are all linearly independent. These nvectors are arranged as the columns of a matrixS = [v1. . . vrw1. . . ws].

2. Consider the action of A on S: AS = [λv1. . . λvrAw1. . . Aws]. Since wi need not be an eigenvector, there is no particular simplification in describing the action ofA on it. However, since S specifies a basis for the entire space, we can say that Awi can be expressed as a linear combination of the basis vectors {vi},{wi}. We write this as follows: Awi = Pr

j=1vjcji +Ps

j=1wjdji, which is easily generalized to:

A[w1. . . ws] = [v1. . . vrw1. . . ws] C

D

, where C ∈Cr×s and D∈Cs×s.

3. Now construct the matrix (A−tI)S, where t is some scalar from the underlying field. We see the following factorization:

(A−tI)S = [(λ−t)v1. . .(λ−t)vr(Aw1−tw1). . .(Aws−tws)]

= [v1. . . vrw1. . . ws]

(λ−t)Ir×r C 0s×r D−tIs×s

where the elements of C, D are indicated in the action of A on wi above (it is useful to have a column picture interpretation of the RHS).

4. We now use the earlier lemma, giving |(A−tI)S| = |A−tI||S| = |S|(λ−t)r|D−tI|. Since S is composed of linearly independent vectors, |S| 6= 0, and it follows that

|A−tI|= (λ−t)rps(t) where ps(t) =|D−tI| is a polynomial in t of degree s.

5. Interpreting the above equation, we note that apart from the (λ−t)r factor, it is possible that λ is a root of ps(t) (and this will depend on D). Thus the algebraic multiplicity of λ (i.e. the number of times it is repeated) is atleast r, but can be more, i.e. µA(λ)≥γA(λ). QED.

1Uday Khankhoje, Linear Algebra EE5120, July-Nov 2018, Electrical Engineering IIT Madras http://www.ee.iitm.ac.in/uday/

2018b-EE5120/

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