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ME-662 CONVECTIVE HEAT AND MASS TRANSFER

A. W. Date

Mechanical Engineering Department Indian Institute of Technology, Bombay

Mumbai - 400076 India

LECTURE-27 TURBULENCE MODELS-2

() March 11, 2011 1 / 21

(2)

LECTURE-27 TURBULENCE MODELS-2

1 Low Ret Two-Eqn model

2 High Ret Stress-Eqn model

3 Low Ret Stress-Eqn model

4 Algebraic Stress-Eqn model

5 Scalar Transport model

1 Eddy Diffusivity model

2 Turbulent Flux Model

6 Modeling Combustion and Turbulence Interaction

() March 11, 2011 2 / 21

(3)

Low Re

t

e- model L27(

191

)

For low Rett/ν ρ De

t = ∂

xi

(µ+ µt

σe) ∂e

xi

t

ui

xj

+ ∂uj

xi

ui

xj

−ρ ρ D

t = ∂

xi

(µ+µt σ)∂

xi

e

C1µt

ui

xj

+∂uj

xi

ui

xj

C2ρ

+ 2ν µt ( ∂2ui

xkxl

)2 µt = CDe2

), CD =CD exp

−3.4 (1+Ret/50)2

C1 = C1, C2 =C2

1−0.3 exp

Re2t = −2ν(∂e0.5

xi

)2

() March 11, 2011 3 / 21

(4)

Comments - L27(

192

)

1 Model constants1 are sensitised to low Ret region near the wall. They tend to high Ret values beyond sub-layers

2 The correction to CD is chosen to give values ofνt in agreement with the Van-Driest mixing length formula

3 The correction to C2 is selected from exptl. data on the decay of isotropic turbulence at low Ret ( at large times, etn where n'2.5 to 2.8).

4 The correction tois introduced to account for the non-isotropic contribution to the dissipation.

5 Wall-functions are no longer necessaryand e andEqns can be solved with ewall =wall =0. However, to capture the low Ret effects, very fine mesh (>60 grid nodes ) become necessary in the y+<100 region.

1Jones W P and Launder B L The Prediction of Laminarisation with a Two-Equation Model of Turbulence, Int. Jnl. of Heat and Mass Transfer, vol.

15, p 301, 1972

() March 11, 2011 4 / 21

(5)

Stress Eqn Model- L27(

193

)

Six transport equations for the one-point correlation ui0 u0j are derived from equation for Bij by setting separationξk =0 ( lecture 23 )

D ui0uj0

Dt = −

uj0uk0ui

xk

+u0i uk0uj

xk

{Pij}

− ∂

xk

"

u0i uj0 uk0 +p0 ρ

n

ui0 δjk +u0j δiko

#

{Dij} + p0

ρ

(∂ui0

xj

+ ∂uj0

xi

)

−2ν ∂ui0

xk

u0j

xk

{PSij} {ij}

() March 11, 2011 5 / 21

(6)

Modeling u

i0

u

j0

Eqn - L27(

194

)

1 Invoking the idea of local isotropy at high Ret the destruction rate is equally distributed among all its components. Henceij = (2/3) δij whereis obtained from its eqn.

2 Pressure-Strain Correlation PSij acts in two ways: Firstly, it sustains the division of TKE ( e ) into its three components u02i and secondly, it destructs the absolute magnitude of the shear stresses. Hence, without further elaboration

PSij = Cp1

e (ui0 vj0 −2

3 eδij) +Cp2(PijPii

3 ) + Cp3(Pij0 − 2

3P δij) +Cp4e(∂ui

xj

+∂uj

xi

) +PSw

PSw = e3/2 LB

Cp10

e (ui0 vj0 −2

3 eδij) +Cp20 (PijPij0)

Pij0 = −u0i uk0Uk

xj

u0j uk0Uk

xi

(see next slide)

() March 11, 2011 6 / 21

(7)

Contd . . . - L27(

195

)

This algebraic expression for PSij is derived from its exact Eqn2. The term containing Cp1 is calledreturn-to-isotropy. The PSw

term is called thewall-reflection termwhich accounts for the effects of pressure reflections from the wall. The recommended constants are: Cp1 =1.5, Cp10 =0.12, Cp2 =0.764, Cp20 = 0.01, Cp3 =0.109, Cp4=0.182, LB =wall distance. Finally the Triple Velocity correlation ui0 uj0 u0k in theDiffusion term Dij is modeled from its exact Eqn and(p0/ρ) n

ui0/∂xj+∂uj0/∂xi

o'0.

ui0uj0 uk0 =Cs

e

(

ui0ul0uj0uk0

xl

+u0j ul0uk0 u0i

xl

+u0kul0ui0 u0j

xl

)

where Cs '0.08 to o.11 ( from num expts )

2Hanjalic K. and Launder B. E. A Reynolds Stress Model of Turbulence and its Application to Thin Shear Flows, JFM.,52(4), p 609-638, 1972

() March 11, 2011 7 / 21

(8)

Algebraic Models ( ASMs ) - L27(

196

)

1 Implementation of Stress-Eqn model requires solution of 6 differential eqns for ui0 u0j, 2 Eqns for e andcoupled with the 3 RANS Eqns. This is a formidable problem.

2 The modeled forms presented above show that spatial gradients of ui0 uj0 occur only in thediffusion and convection - these terms make the Eqns differential ones.

3 Alg. Stress Models are developedusing the idea that ui0 uj0

e '

D ui0uj0

Dt −Diff(ui0uj0)

D e

D t −Diff(e) = −(2/3) (1−Cp1ij + (P/ )F (P/ )−1+Cp1

F = (1−Cp2) Pij

PCp3

Pij0

PCp4

e P (∂ui

xj

+∂uj

xi

) + 2

3 (Cp2+Cp3ij ( computational expense reduced)

() March 11, 2011 8 / 21

(9)

Low Re

t

ASM - L27(

197

)

u0i uj0 = −(2/3)eδij +e×F F = νt

e Sij +C1

νt

e (SikSjk − 1

3Skl Sklδij) + C2

νt

e (Ωik Sjk+ ΩjkSjk) +C3

νt

e (Ωikjk− 1

3 Ωklklδij) + C4

νt e

()2 (Skllj +Skjli)Skl

+ C5

νt e

()2 (ΩillmSmj+Sillmmj− 2

3 Slmmnnl δij) + νt e

()2 (C6Sij Skl Skl +C7Sijklkl) ( see next slide )

() March 11, 2011 9 / 21

(10)

Low Re

t

ASM Contd - L27(

198

)

ij = (∂ui/∂xj−∂uj/∂xi) Sij = (∂ui/∂xj+∂uj/∂xi) µt = fµCD e2/fµ=1−exp

−(Ret

90 )0.5−(Ret

90 )2

CD = 0.3×(1+0.35 n

max(S,Ω) o1.5

)−1

×

1−exp

− 0.36

exp(−0.75 max(S,Ω)

S = (e/) q

0.5 Sij Sij Ω = (e/)p

0.5Ωijij

Constants are: C1 = -0.1, C2= 0.1, C3= 0.26, C4 = - 10 (CD)2, C5= 0, C6= - 5 (CD)2 and C7 = 5 (CD)2. The model is tested for very complex strain fields - swirling flows, curved channels and jet-impingement on a wall ( Craft T. J., Launder B. L. and Suga K, IJHFF, 17(12), p 108, 1996 )

() March 11, 2011 10 / 21

(11)

Scalar Transport - L27(

199

)

From Lecture 21,

ρmcpm

"

Tˆ

t +∂uˆjTˆ

xj

#

= − ∂qˆj

xj

+µΦˆv (Instantaneous) ρmcpm

T

t +∂ujT

xj

= − ∂

xj

(−km

T

xj

mcpmu0j T0) + µeff Φvm (Time averaged) ρmcpmuj0 T0 must be obtained from

1 Eddy Diffusivity model, or

2 Transport Eqn for uj0 T0

() March 11, 2011 11 / 21

(12)

Eddy Diffusivity model - L27(

1019

)

1 Analogous toµt, we defineTurbulent thermal conductivity kt

so that

ui0 T0 = ( kt

ρcp

)∂T

xi

tT

xi

= νt PrT

T

xi

where PrT = Turbulent Prandtl number simeq 0.9 when Ret

is high.

2 Hence, energy Eqn will read as D T

D t = ∂

xk

( ν

Pr + νt σt

) ∂T

xk

+ Qgen

ρcp

where Qgeneff Φvm. Usually,ρm << µeff Φv.

() March 11, 2011 12 / 21

(13)

Comments on EDM - L27(

1119

)

1 The model is very convenient becauseνt is obtained from mixing length, or one- or two-eqn models and PrT is an absolute constant

2 The disadvantage is thatαt =0 whereνt =0. In several flows, significant temperature gradients and hence heat transfer exist in regions whereνt =0.

3 Likeνtt is also isotropic. But, measurement of decay of non-axi-symmetric temperature profiles in a fully developed turbulent flow in a pipe suggests that the ratio of tangential to radial diffusivities (αtt,r )>>1 near the wall.

4 Therefore, in general, ui0 T0 must be obtained directly from its differential transport equation.

() March 11, 2011 13 / 21

(14)

u

i0

T

0

Eqn - L27(

1219

)

Eqn for ui0T0 is derived by multiplying Eqn forT by uˆ i0 and Eqn foruˆi by T0 - addition and time-averaging gives.

ui0 T0

t +uk

ui0 T0

xk

= −

ui0 uk0T

xk

+uk0 T0ui

xk

{PT}

− ∂

xk

"

ui0 u0kT0 +p0T0

ρ δik −α ∂ui0T0

xk

#

{DT} + p0

ρ

T0

xi

− (ν+α) ∂u0i

xk

T0

xk

{RDT} {DisT}

() March 11, 2011 14 / 21

(15)

Modeling u

i0

T

0

Eqn - L27(

1319

)

1 Like PSij,Redistribution term RDT is modeled as RDT = −CT 1

e ui0 T0 +CT 2uk0 T0ui

xk

= −0.5

e un0 T0 e3/2 LB

( for Pr >1)

= −

CT 1+0.5(Pr +1 Pr )

e ui0 T0 ( for Pr << 1)

2 At high Ret or ( Peclet ),the task of Destruction is performed by RDT . Hence,DisT =0.

3 In thediffusion term, effect of p0 is either neglected or taken to be 0.2×ui0 uk0 T0 where

ui0 uk0 T0 =CT

e

"

uj0 uk0u0i T0

xj

+ui0uk0uj0 T0

xj

#

() March 11, 2011 15 / 21

(16)

Solving u

i0

T

0

Eqn - L27(

1419

)

1 The model constants are: CT 1= 3.6, CT 2= 0.266 and CT = 0.11.

2 Required correlations are taken as

ui0 T0 = νt PrT

T

xi

and − u0i uj0t Sij

3 νt is determined from e andEqns

4 For complete range of Prandtl numbers, PrT is modeled as PrT =0.85+0.0309

Pr +1 Pr

() March 11, 2011 16 / 21

(17)

Algebraic Flux Model - L27(

1519

)

1 Eqn forscalar fluctuationsis derived as D T02/2

Dt = − ∂

xi

"

ui0T02

2 −α ∂

xi

(T02 2

)#

ui0 T0T

xi

− α(∂T0

xi

)2 whereα(Tx0

i)2 =Te T02

2 The AFM is derived from D ui0 T0

D t −Diff(ui0 T0) =

"

(P−)e+ (P−)

T02

2

# ui0 T0 ep

T02 T02 = CT0 e

ui0 T0T

xk

prod = diss assumed where CT0 '1.6 for Pr ≥1.

() March 11, 2011 17 / 21

(18)

Evidence from DNS - Pipe flow - L27(

1619

)

1.5 3.0 4.5

10 Y+ 100

T 2

Pr = 2

Pr = 0.1 ( q w / ρCp Uτ)

Pr = 0.71

1 Mean T profiles for pipe flow agreed with DNS

2 Location of peak T02 shows that production shifts

towards larger y+ as Pr decreases.

0.2

−0.3

−0.2

− 0.1 0.1 0.3

LossGain

Production

Diffusion

Redistribution Dissipation

50 150

0.02 0.04

− 0.04

− 0.02

GainLoss

Redistribution

Diffusion

Production Dissipation

Budget v T Budget

50 150

( a ) u T ( b )

1 u0T0 budget is similar to e-budget

2 v0T0 budget resembles u0v0 budget justifying Eddy Diff model for this case.

() March 11, 2011 18 / 21

(19)

Combustion and Turbulence - 1 - L27(

1719

)

1 InCombustionit is necessary to solve differential eqns for all participating species k.

∂(ρmωk)

t + ∂(ρmujωk)

xj

= ∂

xj

ρmDeff

∂ωk

xj

+Rk

whereRk = rate of species generation/consumption.

Deff =ν/Sct/SCt and SCt '0.9.

2 The simplest postulate is called the Simple Chemical Reaction ( SCR ) that is written as

1 kg of Fuel+Rst kg of Oxidant= (1+Rst) kg of Product There are only three species Fuel, Oxidant air and Products and Rst =(A/F)stoich

3 Rox =Rst ×Rfu and Rpr =−(1+RstRfu. In laminar flow Rfu =−A exp(−E

RuTmfuωoxn (A and E are fuel-specific)

() March 11, 2011 19 / 21

(20)

Combustion and Turbulence - 2 - L27(

1819

)

1 Inturbulent combustion, however, it is observed thatouter edges of flames are very intermittent and jagged.

2 Experimentally it is observed thateven if time-averaged ωfu andωox are high, Rfu rates are not as high as would be expected from the Arrhenius formula

3 This is because,the fuel and oxidant at a given point are present at different times. Clearly, therefore, time scales of chemical reaction and turbulence are important. These are characterised bySL/urms0 where SL is the laminar flame speed of the fuel.

4 These ideas are captured3in Rfu =−Cebuρm

q

0fu)2

e ' −Cebuρmωfu e

3Spalding D. B. Development of Eddy-Breakup Model of Turbulent Combustion, 16th Symposium on Combustion, p 1657, 1976

() March 11, 2011 20 / 21

(21)

Combustion and Turbulence - 3 - L27(

1919

)

1 In practical computing, the applicability of the EBU has been enhanced by the following variant

Rfu =−ρm e Min

Aωfu, A Rst

ωox, A0 1+Rst

ωprod

where A = 4 and A0 '2.

2 In the next lecture, we shall discuss tow important aspects of turbulent flows: ( a ) Laminar-to-Turbulent Transition and ( b ) Effect of Wall Roughness

() March 11, 2011 21 / 21

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