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Asymptotic stability of traveling waves for viscous scalar conservation laws

Hyun Ki Kim

Department of Mathematical Sciences

Graduate School of UNIST

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Asymptotic stability of traveling waves for viscous scalar conservation laws

A dissertation

submitted to the Graduate School of UNIST in partial fulfillment of the

requirements for the degree of Master of Science

Hyun Ki Kim

17.12.2016 Approved by

Advisor

Bongsuk Kwon

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Asymptotic stability of traveling waves for viscous scalar conservation laws

Hyun Ki Kim

This certifies that the dissertation of Hyun Ki Kim is approved.

17.12.2016

Advisor: Bongsuk Kwon

Hantaek Bae: Thesis Committee Member #1

Kyudong Choi : Thesis Committee Member #2

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I dedicate this dissertation to my parents

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Abstract

There are many research about Viscous scalar conservation law ut+f(u)x =µuxx. In this paper, we study stability and asymptotic stability of travelling solutions for viscous scalar conservation law. The major result shows that if Rankine Hugoniot condition, the generalized shock condition and some assumptions hold, there exist a solution approaches to the travelling solution, satisfy stability and asymptotic stability problems at corresponding rate. The important feature of this paper is to employ an appropriate weight function to show the stability and asymptotic behavior of the viscous shock waves.

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Contents

1 Introduction 1

2 Existence of travelling wave solution 4

3 Reformulation of the Problem 7

4 Stability of travelling wave for convex flux case 9 5 Stability of travelling wave for non convex flux case 14 6 Asymptotic stability of travelling wave for non convex flux case 20

7 Conclusion 28

8 Appendix 30

References 31

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1

Introduction

We consider the Cauchy problem for viscous scalar conservation laws:

ut+f(u)x=µuxx, (x, t)∈R×R+, (1.0.1)

u(x,0) =u0(x), x∈R, (1.0.2)

whereµ >0 is called the coefficient of viscosity, f ∈C2 and the initial data u0(x) satisfies

u0(x)→u± as x→ ±∞. (1.0.3)

Let this scalar viscous conservation law admits smooth travelling wave solutions with shock profile

u(x, t) =U(ξ) , ξ =x−st, (1.0.4)

U(ξ)→u± as ξ → ±∞. (1.0.5)

ssatisfies the Rankine Hugoniot condition

s(u+−u) =f(u+)−f(u), (1.0.6) and the generalized shock condition

h(u) =−s(u−u±) +f(u)−f(u±)

<0 (u+< u < u),

>0 (u< u < u+). (1.0.7) The generalized shock condition means

f0(u+)≤s≤f0(u). (1.0.8)

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About travelling waves for viscous scalar conservation law, Il’in and Oleinik [1], Nishihara [2], Kawashima and Matsumura[3] investigated the asymptotic stability of travelling wave for viscous scalar conservation law with convex function f. However, we need to generalize the condition about f, because the convex function f is limited case. So, there were many re- searches about the non convex function with some assumptions. Matsumura and Kawashima [4], investigated stability of travelling waves with convex and concave function that has a one inflection point. Jones, Gardner and Kapitula[7] investigated stability of travelling wave and decay rate withC2 function.

Using these results, Nishihara and Matsumura [6] generalized the asymptotic stability of travel- ling wave with non convex functionf. So, our purpose is to survey on their results on stability and decay rate for any C2 function.

In section 2, we consider the existence of travelling wave using Lipschitz condition. In section 3, we reformulate the viscous scalar conservation law using section 2 results. In section 4, we check the stability of travelling wave for convex flux case using local existence and a priori estimate.

In section 5, we check stability of travelling wave for non convex flux case using local existence and a priori estimate. In section 6 and 7, we show asymptotic decay rate of the viscous shock waves for C2 functionf.

To find the a priori estimates for each case, we use the section 3 and combine them with local existence. Then, we show that stability and asymptotic decay rate for each section. In these progresses, we use an Energy method with appropriate weight function.

Notation 1.

1.0.1 We denote the constant Ca,b,.. depending ona, b, .. by Ca,b,.. or only by C.

1.0.2 We denote f(x)∼g(x) as x→awhen C−1g < f < Cg in a neighbourhood ofa.

1.0.3 We denote byL2 space with the norm

||f||2 =R

R|f(x)|2dx.

1.0.4 Hl is the sobolev space ofl th order with the norm

||f||2l = Σlj=0||(∂x )jf(x)||2.

1.0.5 L2w is the weighted L2 space. f ∈L2w meansw1/2f ∈L2 with the norm

|f|2w =R

Rw(x)|f(x)|2dx.

1.0.6 Ifw(x) =hxia= (1 +x2)α/2, we writeL2w=L2α and | · |w=| · |α.

1.0.7 If a weighted function ishxiαw, we denote byf ∈L2α,w with the norm

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|f|α,w = (R

R< x >αw(x)|f(x)|2dx)1/2.

For example, ifC−1 ≤w(x)≤C, we know thatL2=H0=L20=L2w with|| · ||=|| · ||0 =| · |0

| · |w and thatL2α,w=L2α with| · |α,w ∼| · |α.

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2

Existence of travelling wave solution

The first thing we need to check is the existence of travelling wave solutions of viscous scalar conservation law. If f is convex, we get the 2 Lemma.

Lemma 2.0.1. If (1.0.1) admits a travelling wave U(x−st), satisfies U(±∞) = u± and f is convex, then u± and s must satisfy the Rankine Hugoniot condition and the generalized shock condition.

Proof. Since we admitu(x, t) =U(x−st) =U(ξ), (1.0.1) satisfy −sU0+f(U)0=µU00. Integrating over (±∞, ξ), we get

µU0 =−sU+f(U)−c=h(U). (2.0.1)

Since U(±∞) =u± ,U0(±∞) = 0 and using ξ→ ±∞ in (2.0.1) we know

h(u±) = 0 and c=−su±+f(u±). (2.0.2) It equals to the Rankine Hugoniot condition.

The equation (2.0.1) withh(u±) = 0 admits a smooth solution U(ξ) satisfyingU(±∞) =u± if and only if

h(u)<0, if u+< u, h(u)>0, if u+> u.

(2.0.3) is done. So, we know that the condition ofh(U) must be satisfied becausef is convex. Since the generalized shock condition is proved that it’s equivalent to the condition of h(U), we proved that the Rankine Hugoniot condition and the generalized shock condition are necessary for the existence of a travelling waveU(x−st) satisfying U(±∞) =u±.

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Lemma 2.0.2. (Existence of travelling solutions with convex function f) Suppose the Rankine Hugoniot condition and the generalized shock condition hold. Then, there exist a travelling wave U(x−st), satisfyingU(±∞) =u±. The U(ξ) is a monotone function of ξ.

Proof. We have

Differential equation: Uξ=h(U, ξ) , U(±∞) =u±

Initial condition: U(ξ) =U

To prove Lemma 2.0.2, we use Lipschitz condition.

Since h(Uk(ξ)) uniformly converge to h(U·(ξ)) = U·(ξ) by the Pichard iteration, the global solution U(ξ) exist, ifh(U) is global lipschitz ofU.

So, we need to showh(U) is global lipschitz.

Since h is convex,U can’t beU ≥u and U ≤u+. It meansU ∈[u+, u].

So, we get ∀(ξ, U)∈(R,(u+, u))

|∂U∂h|=|h0(U)|=|f0(U)−s| ≤supU∈[u+,u]|f0(U)|+s≤max(|f0(u+)|,|f0(u)|) +s≤K.

It means h(U) is Lipschitz. So, the global solutionU(ξ) exist.

By Lemma 2.0.1 and Lemma 2.0.2, we know:

there exists a travelling waveU(x−st) and it satisfiesU(±∞) =u±if and only ifu±and shock speedssatisfy the Rankine-Hugoniot condition and the generalized shock condition.

However, we can’t use Lemma 2.0.2 for the non-convex function f. So, to prove existence of travelling wave with non convex function f, we need some condition ofh(U).

Lemma 2.0.3. (Existence of travelling wave withf ∈C2) Assume Rankine-Hugoniot condition, the generalized shock condition and

|h(U)|∼|U −u±|1+k± , asU →u±, (2.0.4)

with k± ≥ 0. Then there exists a travelling wave solution U(ξ) of viscous scalar conservation law with U(±∞) =u±. Also,

|U(ξ)−u±|∼e−c|ξ| , if f0(u+)< s < f0(u), (2.0.5)

|U(ξ)−u±|∼|ξ|−1/k+ , if s=f0(u+), (2.0.6)

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|U(ξ)−u±|∼|ξ|−1/k , if s=f0(u), (2.0.7) is done as ξ→ ±∞, where k± is denoted to h(n)(u±) = 0 if 1≤n≤k± and h(n+1)(u±)6= 0.

Proof. We have

Differential equation: Uξ=h(U, ξ) , U(±∞) =u±

Initial condition: U(ξ) =U

To prove Lemma 2.0.3, we use Lipschitz condition.

Since h(Uk(ξ)) uniformly converge to h(U·(ξ)) = U·(ξ) by the Pichard iteration, the global solutionU(ξ) exist, ifh(U) is global lipschitz ofU. So, we need to showh(U) is global lipschitz.

Since h < 0 is non convex, |h(U)| ∼ |U −u±|1+k± help U → u± as ξ → ∞. It means U is bounded.

So, we get ∀(ξ, U)∈(R,(u+, u))

|∂U∂h|=|h0(U)|=|f0(U)−s| ≤supU∈[u+,u]|f0(U)|+s≤max(|f0(u+)|,|f0(u)|) +s≤K.

It means h(U) is Lipschitz. So, the global solutionU(ξ) exist.

By the implicit formula, we get 1. f0(u+)< s < f0(u) case,

Since h0(u±) =f0(U)−s6= 0 , |h(U)|∼|U −u±|asU →u± . Therefore, we get RU(ξ)

u++u 2

1

|u−u±|du=ln(u−u±)|u=U(ξ)

u=u++2u =ξ+c.

So, we know|U(ξ)−u±|∼e−c|ξ| asξ→ ±∞ for some constantc.

2. s=f0(u+) orf0(u) case,

In these cases,|h(U)|∼|U−u±|1+k± as U →u±. Therefore, RU(ξ)

u++u 2

1

|u−u±|1+k±du= c

(u−u±)k±|u=U(ξ)

u=u++2u =ξ+c.

So, we know

|U(ξ)−u+|∼ |ξ|1/kc + as ξ→ ∞ for some constantcifs=f0(u+),

|U(ξ)−u|∼ |ξ|1/kc asξ → −∞for some constantc ifs=f0(u).

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3

Reformulation of the Problem

For the stability and asymptotic stability of travelling wave solution U, we need a condition about U and the initial data u0. So, we add the assumption u0 −U is integrable. Since U(±∞) =u±, we get

R

R(u0(x)−U(±∞))dx=R

R(u0(x)−u±)dxT0.

It means we determineU which satisfies Z

R

(u0(x)−U(x))dx= 0, (3.0.1)

and define

ψ0(x) :=Rx

−∞(u0(y)−U(y))dy.

Let U(ξ) be the travelling wave solution where satisfy Lemma 2.0.3 and (3.0.1) , then we get

u(x, t) =U(ξ) +ψξ(ξ, t) , whereξ =x−st. (3.0.2) It means (1.0.1) with the initial data is

ψt−sψξ+ (f(U +ψξ)−f(U)) =µψξξ. (3.0.3)

ψ(ξ,0) = Z ξ

−∞

(u0−U)(η)dη. (3.0.4)

(3.0.3) is equivalent to the following form

ψt+h0(U)ψξ−µψξξ=F, (3.0.5)

F =−(f(U +ψξ)−f(U)−f0(U)ψξ). (3.0.6)

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Now, let select the weight as

w=w(U) =|(U−u+)(U −u)

h(U) |. (3.0.7)

Since |h(U)|∼|U −u±|1+k± in Lemma 2.0.3, we get the following form

iff0(u+)< s < f0(u) , w(U)∼C asU →u± and L2α,w(U)=L2α, (3.0.8) iff0(u+) =s < f0(u) ,w(U)∼|U−u+|−k+ asU →u+, (3.0.9)

orw(U(ξ))∼hξi asξ → ∞and hence L2w(U)=L2hξi

+,

iff0(u+)< s=f0(u) ,w(U)∼|U−u|−k asU →u, (3.0.10) orw(U(ξ))∼hξi asξ→ −∞ and henceL2w(U) =L2hξi

,

iff0(u+) =s=f0(u) ,w(U)∼|U−u±|−k± asU →u±, (3.0.11) orw(U(ξ))∼hξi asξ→ ±∞ and henceL2w(U) =L2hξi

=L21.

Remark 3.0.1. The reason why the weight functionw(U) is introduced and has the value that form is the key point of this thesis. We consider theC2 functionf(u), it’s not always h00(U) = f00(u) > 0. It means there are problems just doing estimate without using other method.

However, with the weight function w(U), w(U)h(U) is convex function, we can estimate much easily. The details comes out later.

We define the solution space

X(0, T) ={ψ∈C0(0, T;H2∩L2w(U)), ψξ∈L2(0, T;H2∩L2w(U)}.

Then U be the solution globally in time about stability and asymptotic stability for (1.0.1).

To prove it, we suppose there is a local existence result.

Proposition 3.0.1. (local existence)For any0 >0, there exists a positive constant To depend- ing on 0 such that if ψ0∈H2∩L2w(U) and ||ψ0||20, then the problem has a unique solution ψ∈X(0, T) satisfying ||ψ(t)||2≤20 for 0≤t≤T0.

We check the case u+ < u, h(U) ≤0 for U ∈[u+, u] because the other case, u+ > u, h(U)≥0, is proved in the same method.

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4

Stability of travelling wave for convex flux case

In this chapter, we check A priori estimate and Stability of travelling waves for convex flux using continuation argument.

Theorem 4.0.1. (A priori estimate) Letψbe a solution of the(3.0.5) and satisfying inX(0, T) for a constant T >0. Then there exists a constant 3 >0 such that if sup0≤t≤T ||ψ(t)||2 < 3, thenψ(t) satisfies

||ψ(t)||22+Rt

0||ψξ(τ)||22dτ ≤C22(||ψ0||22), for any0≤t≤T.

The key point of this section is to use the standard energy method.

Lemma 4.0.1. Let ψ∈X(0, T) be a solution of (3.0.5). Then, it satisfies

||ψ(t)||+Rt

0 µ||ψξ(τ)||2dτ ≤C||ψ0||2. Proof. Multiplying 2ψon (3.0.5) we get

2ψψt+ 2ψψξh0(U)−2µψψξξ = 2ψF. (4.0.1) It means

2)t+ (ψ2h0(U))ξ−h00(U)Uξψ2−(2µψψξ)ξ+ 2µψξ2= 2ψF, (4.0.2) In (4.0.2), (·)ξ is the term which disappears after integration over R.

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||ψ(t)||2+Rt 0

R

R−(h(U))00Uξψ2+ 2µψ2ξdξdτ =||ψ0||+Rt 0

R

R2ψF dξdτ. Since Uξ <0 andh00(U) =f00(U)≥0 such that we get

||ψ(t)||2+Rt

0 2µ||ψξ||2dτ ≤ ||ψ0||2+Rt 0

R

R2ψF dξdτ. Let

N(t) = sup0≤τ≤t||ψ(τ)||2, and assumeN(t)≤0.

By the taylor extension, |F|=|f(U +ψξ)−f(U)−f0(U)ψξ|=O(ψ2ξ). It satisfies |F| →0 as ξ→ ±∞.

Then, for some 3 satisfying N(t)< 3< 0,

||ψ(t)||2+Rt

0 ||ψξ||2dτ ≤C22||ψ0||2.

Moreover, we need to check the similarly case when we apply ∂ξ and∂ξξ to rewritten form.

Then, we can get a new lemma.

Lemma 4.0.2. There is a positive constant 3 where is smaller than 0 such that if N(t) ≤ 3< 0,

||ψξ(t)||21+Rt

0||ψξξ(τ)||21dτ ≤C(||(ψ0)ξ||21).

Proof. For higher order estimate, we apply ∂ξ to the (3.0.5). Then, ψξt+{(h(U))0ψξ}ξ−µψξξξ=Fξ. Multiplying 2ψξ on (3.0.5) we get

ξ2)t+{(h(U))0ψ2ξ}ξ− {2µψξξξψξ}ξ+h00(U)Uξψξ2+ 2µψξξ2 = 2ψξFξ. (4.0.3) Integrating (4.0.3) over (0, t×R) we get

||ψξ(t)||2+Rt

0

R

Rh00(U)Uξψ2ξdξ+ 2µ||ψξξ(τ)||dτ =||ψξ(0)||2+Rt

0

R

R2Fξψξdξdτ. Then, for some3 satisfyingN(t)< 3 < 0, there exist C such that

||ψξ(t)||2+Rt 0

R

Rh00(U)Uξψξ2dξ+µ||ψξξ(τ)||dτ ≤C(||ψξ(0)||2).

By, −Rt 0

R

Rh00(U)Uξψ2ξdξ≥0, we have

||ψξ(t)||2+Rt

0µ||ψξξ(τ)||dτ ≤C(||ψξ(0)||2)−Rt 0

R

Rh00(U)Uξψξ2dξdτ,

≤C(||ψξ(0)||2) +cRt 0

R

Rψ2ξdξdτ,

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wherec= supξ∈R{|h00(U)Uξ|}<∞.

Applying ∂ξξ to (3.0.5) we get

ψξξt+{(h(U))0ψξ}ξξ−µψξξξξ=Fξξ, Multiplying 2ψξξ we get

ξξψξξt+{(h(U))0ψξ}ξξξξ−µ2ψξξψξξξξ=Fξξξξ (4.0.4) we changed the second term in (4.0.4) to the other form as follows

(h0(U)ψξ)ξξψξξ ={(h0(U)ψξ)ξψξξ}ξ−(h0(U)ψξ)ξψξξξ

={(h0(U))ξψξψξξ+h0(U)ψξξ2 }ξ−(h0(U))ξψξψξξξ−h0(U)ψξξψξξξ

={(h0(U))ξψξψξξ+h0(U)ψξξ2 }ξ− {12h0(U)ψξξ2 }ξ+ 12(h0(U))ξψξξ2

−{((h0(U))ξψξξξ}ξ+ ((h0(U))ξψξ)ξψξξ

= 12{h0(U)ψ2ξξ}ξ+ 32(h0(U))ξψξξ2 + (h0(U))ξξψξψξξ. It means

ξξ2 )t+{(h(U))0ψξξ2 }ξ−{2µψξξξψξξ}ξ+3h0(U)ξψ2ξξ+2h0(U)ξξψξψξξ+2µψξξξ2 = 2ψξξFξξ. (4.0.5) Integrating (4.0.5) over (0, t)×R we get

||ψξξ(t)||2+Rt 0

R

R+3h0(U)ξψξξ2 + 2h0(U)ξξψξψξξdξ+ 2µ||ψξξξ(τ)||dτ =

||ψξξ(0)||2+Rt 0

R

R2Fξξψξξdξdτ. Then, for some3 satisfyingN(t)< 3 < 0, there exist C such that

||ψξξ(t)||2+Rt 0

R

Rµψ2ξξξ(τ)dξdτ ≤C(||ψξξ(0)||2)−Rt 0

R

R3h0(U)ξψξξ2 + 2h0(U)ξξψξψξξdξdτ. Since −Rt

0

R

R3h0(U)ξψξξ2 + 2h0(U)ξξψξψξξdξdτ ≤cRt 0

R

Rψξ2ξξ2 dξdτ, wherec= 5 supξ∈R{|(h0(U))ξ+ (h0(U))ξξ|}<∞, we have

||ψξξ(t)||2+Rt 0

R

Rµψ2ξξξ(τ)dξdτ ≤C(||ψξξ(0)||2) +cRt

0||ψξξ(τ)||2+||ψξ(τ)||2dτ. Combining with these higher order cases, we get

||ψξ(t)||2+||ψξξ(t)||2+Rt

0 ||ψξξ(τ)||2+||ψξξξ(τ)||2dτ ≤C(||(ψ0)ξ||2+||(ψ0)ξξ||2) +cRt

0 ||ψξξ(τ)||2+||ψξ(τ)||2dτ.

Combining Lemma 4.0.1 and Lemma 4.0.2. we get

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||ψ(t)||22+Rt

0||ψξ(τ)||22dτ ≤C(||ψ0||22).

where constantC dependent ofN(t). So, the proof of A priori estimate is done.

Let check the Stability of travelling wave.

Theorem 4.0.2. (Stability) Supposeψ0∈H2. Then there exists a positive constant2 andC2

such that if ||ψ0||2< 2, the problem has a unique global solution ψ∈X(0,∞),

||ψ(t)||22+ Z t

0

||ψξ(τ)||22dτ ≤C22(||ψ0||22). (4.0.6)

for anyt≥0. Also, ψξ tends to 0 in the L norm ast→ ∞, supξ∈Rξ(ξ, t)| →0 , as t→ ∞.

Proof. To prove this theorem, we have to use Continuation argument.

Suppose2= min{3/2, 3/2C3} ,C2=C3.

By the local existence, we put||ψ0||222223/4. Because ofT0 is dependent of0 ,T0 has the valueT0(3) such that the solution exists on [0, T0(3)]. It means

||ψ(t)||22 ≤4(||ψ0||22)≤23, fort∈[0, T0].

By A priori estimate with T =T0(3), we know

||ψ(t)||22+Rt

0||ψξ(τ)||22dτ ≤C32(||ψ0||22), for 0≤t≤T. So we get

||ψ(t)||22≤C32(||ψ0||22)≤C3222423. It means

||ψ(T0)||22 ≤C3222423.

Using above results, we knowψ(ξ, T0)∈H2 and ||ψ(T0)||22 ≤ ||ψ(T0)||22423. So, we can apply Local existence again at the start timeT0. Then,

||ψ(t)||22 ≤4(||ψ0||22)≤23 fort∈[T0,2T0].

It means Local existence holds for t∈[0,2T0].

Also, by A priori estimate, we get

||ψ(t)||22+Rt

0||ψξ(τ)||22dτ ≤C32(||ψ0||22),

⇒ ||ψ(t)||22 ≤C32(||ψ0||22)≤C3222423.

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fort∈[0,2T0].

Using the same methods, Local existence and A priori estimate hold fort∈[0, nT0], n∈N. It means a global solution ψ∈X(0,∞) exist.

The remain thing is to showψξ tends to 0 in the L norm ast→ ∞,

supξ∈Rξ(ξ, t)| →0 , as t→ ∞. (4.0.7) Using the Gagliardo-Nirenburg interpolation inequality, we get

sup

ξ∈R

ξ(t)| ≤ ||ψξξ(t)||1/2||ψξ||1/2. (4.0.8)

Since

||ψ(t)||2+Rt

0 µ||ψξ(τ)||2dτ ≤C||ψ0||2

||ψξ(t)||2+Rt

0µ||ψξξ(τ)||2dτ ≤C||ψξ(0)||2+cRt

0||ψξ(τ)||2dτ ≤C||ψ0||21

||ψξξ(t)||2+Rt

0µ||ψξξξ(τ)||2dτ ≤C||ψξξ(0)||2+cRt

0||ψξ(τ)||2+||ψξξ(τ)||2dτ ≤C||ψ0||22 are done, we know ||ψξ(t)|| and||ψξξ(t)||are uniformly bounded for t≥0.

Also, since ||ψξ(t)||2 is integrable over tand dtd||ψξ(t)||2 is also integrable overtand satisfies Rt

0(dtd||ψξ(τ)||2)dτ =||ψξ(t)||2− ||ψξ(0)||2 ≤C||ψξ(0)||2,

we know||ψξ(t)||2is lipschitz continuous. Therefore||ψξ(t)||2 is uniformly continuous. It means

||ψξ(t)|| →0 , as t→ ∞. (4.0.9)

So we get,

sup

ξ∈R

ξ(t)| ≤ ||ψξξ(t)||1/2||ψξ||1/2 →0, ast→ ∞ (4.0.10) Therefore, Theorem 4.0.2 is done.

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5

Stability of travelling wave for non convex flux case

In this section, we check A priori estimate and Stability of travelling waves for non convex flux using continuation argument.

The key point of this section is to use the energy method with weighted functionw(U).

Theorem 5.0.1. (A priori estimate) Letψbe a solution of the(3.0.5) and satisfying inX(0, T) for a positive constant T. Then there exists a positive constant3 such that ifsup0≤t≤T||ψ(t)||2<

3, then ψ(t) satisfies

||ψ(t)||22+|ψ(t)|2w(U)+Rt

0||ψξ(τ)||22+|ψξ(τ)|2w(U)dτ ≤C22(||ψ0||22+|ψ0|2w(U)), for any0≤t≤T.

Lemma 5.0.1. Let ψ∈X(0, T) be a solution of the reformulation form. Then, it satisfies

1

2|ψ(t)|2w(U)+Rt 0 ||p

−Uξψ(τ)||2+µ|ψξ(τ)|2w(U)dτ ≤ 120|2w(U)+Rt 0

R

Rw(U)ψF dxdτ, Proof. Multiplying the (3.0.5) by 2w(U)ψ we get

2wψψt+ 2wψψξh0(U)−2wµψψξξ= 2wψF. (5.0.1) Using the product rule, we get

2wψψt+ 2wψψξh0(U) + 2w0ψψξh(U)−2w0ψψξh(U)−2wµψψξξ= 2wψF, (5.0.2)

⇒(wψ2)t+ 2(wh)0ψψξ−2w0ψψξh(U)−2wµψψξξ = 2wψF, (5.0.3)

⇒(wψ2)t+ ((wh)0ψ2)ξ−(wh)00Uξψ2−2w0ψψξh(U)−2wµψψξξ= 2wψF, (5.0.4)

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In the chapter 2, we knowh(U) =µUξ such that we get

(wψ2)t+ ((wh)0ψ2)ξ−(wh)00Uξψ2−2µw0Uξψψξ−2wµψψξξ= 2wψF. (5.0.5) Using the product rule, we get

(wψ2)t+ ((wh)0ψ2)ξ−(wh)00Uξψ2−2(µwψψξ)ξ+ 2µwψξ2 = 2wψF. (5.0.6) It means

(12w(U)ψ2)t+ (12(w(U)h(U))0ψ2−µw(U)ψψξ)ξ +µw(U)ψξ212(w(U)h(U))00Uξψ2 =w(U)ψF. Integrating the result over (0, t)×R we get

1

2|ψ(t)|2w(U)+Rt 0

R

Rµw(U)ψξ212(w(U)h(U))00Uξψ2dξdτ = 120|2w(U)+Rt 0

R

Rw(U)ψF dξdτ. Since we selected the weight w = w(U) = |(U−u+h(U))(U−u)|, we know w(U)h(U) is convex function of U such that 12(wh)00= 1.

1

2|ψ(t)|2w(U)+Rt

0µ|ψξ(τ)|2w(U)+|| −p

Uξψ(τ)||2dτ = 120|2w(U)+Rt 0

R

Rw(U)ψF dξdτ

Let

N(t) = sup0≤τ≤t||ψ(τ)||2 and assumeN(t)≤0.

By the taylor extension, |F|=|f(U +ψξ)−f(U)−f0(U)ψξ|=O(ψ2ξ). It satisfies |F| →0 as ξ→ ±∞.

Then, for some 3 satisfying N(t)< 3< 0,

|ψ(t)|2w(U)+Rt

0ξ(τ)|2w(U)dτ ≤C|ψ0|2w(U)

Moreover, we need to check the similarly case when we apply ∂ξ and ∂ξξ to (3.0.5). Then, we can get a new lemma

Lemma 5.0.2. There is a positive constant 3 where is smaller than 0 such that if N(t) ≤ 3< 0,

||ψξ(t)||21+Rt

0||ψξξ(τ)||21dτ ≤C(||(ψ0)ξ||21+|ψ0|2w(U))

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Proof. For the estimates ofψξ andψξξ, we apply∂ξ and∂ξξ to (3.0.5) and multiplyψand ψξξ. Applying ∂ξ to (3.0.5), and multiplying 2ψξ to the result, we get

ξψξt+ 2(h0(U)ψξ)ξψξ−2µψξξξψξ = 2Fξψξ. (5.0.7) Using the product rule, we get

2ξ)t+ 2h00(U)Uξψ2ξ+{(h)0ψ2ξ}ξ−(h)00Uξψ2ξ− {2µψξψξξ}ξ+ 2µψξξ2

= 2Fξψξ Integrating over (0, t)×R, we get

||ψξ(t)||2− ||ψξ(0)||2+ Z t

0

Z

R

h00Uξψξ2dξdτ+ Z t

0

2µ||ψξξ(τ)||2dτ = Z t

0

Z

R

2Fξψξdξdτ (5.0.8) Under the smallness assumption onN(T), we get

||ψξ(t)||2+ Z t

0

Z

R

h00Uξψξ2dξ+ 2µ||ψξξ(τ)||2dτ ≤ ||ψξ(0)||2 (5.0.9) Since U is a smooth function and bothUξ and Uξξ converge to 0 asξ → ±∞,|Uξ|and|Uξξ|are bounded, so is supξ∈R|h00(U)Uξ|<∞. It means

||ψξ(t)||2+ Z t

0

2µ||ψξξ(τ)||2dτ ≤ ||ψξ(0)||2− Z t

0

Z

R

2h00Uξψξ2dξdτ (5.0.10)

≤ ||ψξ(0)||2+cRt 0

R

Rψξ2dξdτ ≤ ||ψξ(0)||2+cRt 0

R

Rξ2dξdτ

≤ ||ψξ(0)||2+C|ψ(0)|2w(U) wherec= 2 supξ∈R|h00(U)Uξ|

So, the estimates ofψξ follows

||ψξ(t)||2+ Z t

0

µ|ψξξ(τ)|2w(U)dτ ≤C(||ψξ(0)||2+|ψ(0)|2w(U)) (5.0.11)

Applying ∂ξξ to (3.0.5), and multiplying 2ψξξ to the result, we get

ξξψξξt+ 2(h0(U)ψξ)ξξψξξ−2µψξξξξψξξ = 2Fξξψξξ. (5.0.12) Using the product rule, we get

ξξψξξt+ 2(h0(U)ψξ)ξξψξξ− {2µψξξξψξξ}ξ+ 2wµψ2ξξξ= 2wFξξψξξ.

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The second term, 2(h0(U)ψξ)ξξψξξ is calculated as follows

2(h0(U)ψξ)ξξψξξ={(2h0ψξ)ξψξξ}ξ−(2h0ψξ)ξψξξξ

={2h0ψ2ξξ+ 2h00Uξψξψξξ}ξ−2h00Uξψξψξξξ−2h0ψξξψξξξ

={2h0ψ2ξξ+ 2h00Uξψξψξξ}ξ+{−(2h00Uξψξψξξ)ξ+ (2h00Uξ)ξψξψξξ+ 2h00Uξψξξ} +{−(h0ψξξ2 )ξ+h00Uξψξξ2 }

={h0ψ2ξξ}ξ+ 3h00Uξψ2ξξ+ 2(h0)ξξψξψξξ So, we get

ξξψξξt+{h0ψξξ2 }ξ+ 3h00Uξψ2ξξ+ 2(h0)ξξψξψξξ

−{2µψξξξψξξ}ξ+ 2µψξξξ2 = 2Fξξψξξ. Integrating over (0, t)×R, we get

||ψξξ(t)||2− ||ψξξ(0)||2+Rt 0

R

R3(h)00Uξψ2ξξ+ 2(h0)ξξψξψξξdξdτ +Rt

02µ||ψξξξ(τ)||2dτ =Rt 0

R

R2Fξξψξξdξdτ. Under the smallness assumption onN(T), we get

||ψξξ(t)||2+Rt

02µ||ψξξξ(τ)||2dτ ≤ ||ψξξ(0)||2−Rt 0

R

R3(h)00Uξψ2ξξ+ 2(h0)ξξψξψξξdξdτ. Since U is a smooth function and bothUξ and Uξξ converge to 0 asξ → ±∞,|Uξ|and|Uξξ|are bounded, so is supξ∈R|(h0(U))ξ+ (h0(U))ξξ|<∞. It means

||ψξξ(t)||2+Rt

02µ||ψξξξ(τ)||2dτ ≤ ||ψξξ(0)||2−Rt 0

R

R3(h)00Uξψξξ2 + 2(h0)ξξψξψξξdξdτ

≤ ||ψξξ(0)||2+cRt

0||ψξξ(τ)||+||ψξ(τ)||dτ ≤ ||ψξξ(0)||2+C(||ψξ(0)||2+|ψ(0)|2w(U)) wherec= 5 supξ∈R|(h0(U))ξ+ (h0(U))ξξ|<∞.

So, the estimates ofψξξ follows

||ψξξ(t)||2+ Z t

0

2µ||ψξξξ(τ)||2dτ ≤C(||ψξξ(0)||2+||ψξ(0)||2+|ψ(0)|2w(U)) (5.0.13)

Combining (5.0.11) with (5.0.13) , we get

||ψξ(t)||21+Rt

0||ψξξ(τ)||21dτ ≤C(||ψξ(0)||21+|ψ0|2w(U)).

So, Combineing Lemma 5.0.1 with Lemma 5.0.2, we get

||ψ(t)||22+|ψ(t)|2w(U)+Rt

0||ψξ(τ)||22+|ψξ(τ)|2w(U)dτ ≤C(||ψ0||22+|ψ0|2w(U)).

where constantC dependent ofN(t). So, the proof of A priori estimate is done.

Let check the Stability of travelling wave.

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Theorem 5.0.2. (Stability) Suppose ψ0 ∈H2∩L2w(U). Then there exists a positive constant2 andC2 such that if||ψ0||2+|ψ0|w(U) < 2, the problem has a unique global solutionψ∈X(0,∞),

||ψ(t)||22+|ψ(t)|2w(U)+ Z t

0

||ψξ(τ)||22+|ψξ(τ)|2w(U)dτ ≤C22(||ψ0||22+|ψ0|2w(U)). (5.0.14)

for anyt≥0. Also, ψξ tends to 0 in the L norm ast→ ∞,

supξ∈Rξ(ξ, t)| →0 , as t→ ∞. (5.0.15) Proof. To prove this theorem, we have to use continuation argument, again. The proof is similar to Theorem 4.0.2. The difference point is the weightedL2w norm.

Suppose2= min{3/2, 3/2C3} ,C2=C3.

By the local existence, we put||ψ0||22+|ψ0|2w(U)2223/4. Because of T0 is dependent of0 , T0 has the value T0(3) such that the solution exists on [0, T0(3)]. It means

||ψ(t)||22+|ψ(t)|2w(U)≤4(||ψ0||22+|ψ0|2w(U))≤23 fort∈[0, T0].

By A priori estimate with T =T0(3), we know for 0≤t≤T

||ψ(t)||22+|ψ(t)|2w(U)+Rt

0||ψξ(τ)||22+|ψξ(τ)|2w(U)dτ ≤C32(||ψ0||22+|ψ0|2w(U)).

So, we get

||ψ(t)||22+|ψ(t)|2w(U)≤C32(||ψ0||22+|ψ0|2w(U))≤C3222423. It means

||ψ(T0)||22+|ψ(T0)|2w(U)≤C3222423.

Using above results, we know ψ(ξ, T0)∈H2∩L2w(U) and||ψ(T0)||22 ≤ ||ψ(T0)||22+|ψ(T0)|2w(U)

23

4. So, we can apply Local existence again at the start timeT0,

||ψ(t)||22+|ψ(t)|2w(U) ≤4(||ψ0||22+|ψ0|2w(U))≤23 fort∈[T0,2T0].

It means Local existence holds for t∈[0,2T0].

Also, by A priori estimate,

||ψ(t)||22+|ψ(t)|2w(U)+Rt

0 ||ψξ(τ)||22+|ψξ(τ)|2w(U)dτ ≤C32(||ψ0||22+|ψ0|2w(U))

⇒ ||ψ(t)||22+|ψ(t)|2w(U)≤C32(||ψ0||22+|ψ0|2w(U))≤C3222423, fort∈[0,2T0].

Using the same method, Local existence and A priori estimate hold fort∈[0, nT0], n∈N. It

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means a global solution ψ∈X(0,∞) exist.

The remain thing is to showψξ tends to 0 in the L norm ast→ ∞,

supξ∈Rξ(ξ, t)| →0 , as t→ ∞. (5.0.16) In fact, this is the same method that of Theorem 4.0.2. Using the Gagliardo-Nirenburg inter- polation inequality, we get

sup

ξ∈R

ξ(t)| ≤ ||ψξξ(t)||1/2||ψξ||1/2. (5.0.17)

Since

|ψ(t)|2w(U)+Rt

0µ|ψξ(τ)|2w(U)dτ ≤C|ψ0|2w(U)

||ψξ(t)||2+Rt

0µ||ψξξ(τ)||2dτ ≤C||ψξ(0)||2+cRt

0||ψξ(τ)||2dτ ≤C||ψ0||21

||ψξξ(t)||2+Rt

0µ||ψξξξ(τ)||2dτ ≤C||ψξξ(0)||2+cRt

0||ψξ(τ)||2+||ψξξ(τ)||2dτ ≤C||ψ0||22 are done, we know ||ψξξ(t)|| is uniformly bounded fort≥0.

Since ||ψξ(t)||2 is integrable overtand dtd||ψξ(t)||2 is also integrable overtand satisfies Rt

0(dtd||ψξ(τ)||2)dτ =||ψξ(t)||2− ||ψξ(0)||2 ≤C||ψξ(0)||2,

we know||ψξ(t)||2is lipschitz continuous. Therefore||ψξ(t)||2 is uniformly continuous. It means

||ψξ(t)|| →0 , as t→ ∞. (5.0.18)

So we get,

sup

ξ∈R

ξ(t)| ≤ ||ψξξ(t)||1/2||ψξ||1/2 →0, ast→ ∞ (5.0.19) Therefore, Theorem 5.0.2 is done.

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