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Engineering Mathematics 2

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Engineering Mathematics 2

Lecture 6 Yong Sung Park

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13.1 Complex numbers

Complex number is an ordered pair 𝑧 = 𝑥, 𝑦 , where 𝑅𝑒 𝑍 = 𝑥, 𝐼𝑚 𝑍 = 𝑦.

Imaginary unit: 𝑖 = (0, 1), 𝑖2 = −1

In practice, 𝑧 = 𝑥 + 𝑖𝑦.

Verify the following:

𝑧1 ± 𝑧2 = 𝑥1 ± 𝑥2 + 𝑖 𝑦1 + 𝑦2

𝑧1𝑧2 = 𝑥1𝑥2 − 𝑦1𝑦2 + 𝑖 𝑥1𝑦2 − 𝑥2𝑦1 𝑧1

𝑧2 = 𝑥1𝑥2 + 𝑦1𝑦2 + 𝑖 𝑥2𝑦1 − 𝑥1𝑦2 𝑥22 + 𝑦22

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• Complex plane

• The complex conjugate number of 𝑧 = 𝑥 + 𝑖𝑦: 𝑧 = 𝑥 − 𝑖𝑦ҧ 𝑧 ҧ𝑧 = 𝑥2 + 𝑦2

𝑅𝑒 𝑍 = 𝑥 = 𝑧 + ҧ𝑧

2 , 𝐼𝑚 𝑍 = 𝑦 = 𝑧 + ҧ𝑧 2

x

y z = x + iy

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13.2 Polar form of complex numbers.

• With 𝑥 = 𝑟 cos 𝜃, 𝑦 = 𝑟 sin 𝜃, the polar form of a complex number is 𝑧 = 𝑟 cos 𝜃 + 𝑖 sin 𝜃

in which

𝑟 = 𝑧 = 𝑥2 + 𝑦2 = 𝑧 ҧ𝑧 is the absolute value or modulus, and

𝜃 = arg 𝑧 = tan−1 𝑦

𝑥 is the argument, which is multivalued. The principal value of the argument is −𝜋 < Arg 𝑧 ≤ 𝜋 .

x

y z = x + iy

r 𝜃

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• Question:

Which is greater? 2𝑖 vs. 5𝑖

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• Triangle inequality

𝑧1 + 𝑧2 ≤ 𝑧1 + 𝑧2

𝑧1 + 𝑧2 + ⋯ + 𝑧𝑛 ≤ 𝑧1 + 𝑧2 + ⋯ + 𝑧𝑛

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• Example 2:

Verify the triangle inequality with

𝑧1 = 1 + 𝑖 and 𝑧2 = −2 + 3𝑖

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• 𝑧1𝑧2 = 𝑟1𝑟2 cos 𝜃1 + 𝜃2 + 𝑖 sin 𝜃1 + 𝜃2 , therefore 𝑧1𝑧2 = 𝑧1 𝑧2 and arg 𝑧1𝑧2 = arg 𝑧1 + arg 𝑧2

𝑧1

𝑧2 = 𝑟1

𝑟2 cos 𝜃1 − 𝜃2 + 𝑖 sin 𝜃1 − 𝜃2 , therefore

𝑧1

𝑧2 = 𝑧1

𝑧2 and arg 𝑧1

𝑧2 = arg 𝑧1 − arg 𝑧2

• By induction, 𝑧𝑛 = 𝑟𝑛 cos 𝑛𝜃 + 𝑖 sin 𝑛𝜃 , 𝑛 = ⋯ , −2, −1, 0, 1, ⋯

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• De Moivre’s formula,

cos 𝜃 + 𝑖 sin 𝜃 𝑛 = cos 𝑛𝜃 + 𝑖 sin 𝑛𝜃

• Example:

Express cos 3𝜃 and sin 3𝜃 in terms of cos 𝜃, sin 𝜃 and their powers.

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• Roots:

Consider 𝑧 = 𝑤𝑛, there are 𝑛 values for 𝑤 = 𝑛 𝑧. Find them.

(hint: use 𝑧 = 𝑟 cos 𝜃 + 𝑖 sin 𝜃 and 𝑤 = 𝑅 cos 𝜙 + 𝑖 sin 𝜙 )

• Example:

Find 𝑛 1 for 𝑛 = 2 and 3.

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13.3 Derivative. Analytic function.

• A circle of radius 𝜌 and centre 𝑎: 𝑧 − 𝑎 = 𝜌

𝑧 − 𝑎 < 𝜌: open circular disk → 𝜌 -neighbourhood of 𝑎 𝑧 − 𝑎 ≤ 𝜌: closed circular disk

𝑧 − 𝑎 > 𝜌: exterior of circular disk 𝜌1 < 𝑧 − 𝑎 < 𝜌2: open annulus

𝜌1 ≤ 𝑧 − 𝑎 ≤ 𝜌2: closed annulus

𝑎 𝜌

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• 𝑦 > 0: upper half plane 𝑦 < 0: lower half plane 𝑥 > 0: right half plane 𝑥 < 0: left half plane

• Domain is an open connected set.

• A boundary point of a set 𝑆 is a point with its every nbhd contains points in 𝑆 and 𝑆𝑐.

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• Complex function

𝑤 = 𝑓 𝑧 = 𝑢 𝑥, 𝑦 + 𝑖𝑣 𝑥, 𝑦

• Example:

For 𝑤 = 1

𝑧 𝑧 ≠ 0 , find 𝑢 and 𝑣.

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• 𝑓(𝑧) has a limit 𝑙 as 𝑧 → 𝑧0 from any direction, that is,

𝑧→𝑧lim0 𝑓(𝑧) = 𝑙

if for any 𝜖 > 0, there exists 𝛿 > 0 such that 𝑓 𝑧 − 𝑙 < 𝜖 for all 𝑧 ≠ 𝑧0 and 𝑧 − 𝑧0 < 𝛿.

• 𝑓(𝑧) is continuous at 𝑧 = 𝑧0 if lim

𝑧→𝑧0 𝑓(𝑧) = 𝑓(𝑧0).

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A complex function is differentiable at 𝑧 = 𝑧0 if 𝑓 𝑧0 = lim

𝑧→𝑧0

𝑓 𝑧 −𝑓(𝑧0) 𝑧−𝑧0

exists. Note the limit is taken from any direction.

𝑓′ 𝑧 is called the derivative of 𝑓 𝑧

𝑓 𝑧 is called analytic (or holomorphic) in some domain if it is differentiable in the domain.

The differentiation rules are the same as those for the real functions.

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• Example 4: Show that 𝑓 𝑧 = ҧ𝑧 is not analytic.

• Example: Show that

𝑓 𝑧 = 𝑧𝑛 is analytic in complex plane.

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13.4 Cauchy-Riemann equations. Laplace equation

• Consider necessary conditions for 𝑓 𝑧 = 𝑢 𝑥, 𝑦 + 𝑖𝑣 𝑥, 𝑦 to be analytic in nbhd of 𝑧0 𝑥0, 𝑦0 , by taking the limit

(1) along the horizontal direction; and (2) along the vertical direction.

• 𝑓 is analytic in domain D iff 𝑢 and 𝑣 satisfy Cauchy-Riemann equations:

𝜕𝑢

𝜕𝑥 = 𝜕𝑣

𝜕𝑦 and 𝜕𝑣

𝜕𝑥 = − 𝜕𝑢

𝜕𝑦

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• Example 1: Show that

𝑓 𝑧 = ҧ𝑧 does not satisfy C-R equations

• Example 2: Is 𝑓 𝑧 = 𝑒𝑥 cos 𝑦 + 𝑖 sin 𝑦 analytic?

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• Show that, if 𝑓 𝑧 is analytic in a domain D, then both 𝑢 and 𝑣 satisfy 2D Laplace’s equation, respectively.

• 𝑣 is called a harmonic conjugate function of 𝑢 in D and vice versa.

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• Example:

Find a harmonic conjugate function for 𝑢 = 𝑥2 − 𝑦2.

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