Engineering Mathematics 2
Lecture 6 Yong Sung Park
13.1 Complex numbers
• Complex number is an ordered pair 𝑧 = 𝑥, 𝑦 , where 𝑅𝑒 𝑍 = 𝑥, 𝐼𝑚 𝑍 = 𝑦.
• Imaginary unit: 𝑖 = (0, 1), 𝑖2 = −1
• In practice, 𝑧 = 𝑥 + 𝑖𝑦.
• Verify the following:
𝑧1 ± 𝑧2 = 𝑥1 ± 𝑥2 + 𝑖 𝑦1 + 𝑦2
𝑧1𝑧2 = 𝑥1𝑥2 − 𝑦1𝑦2 + 𝑖 𝑥1𝑦2 − 𝑥2𝑦1 𝑧1
𝑧2 = 𝑥1𝑥2 + 𝑦1𝑦2 + 𝑖 𝑥2𝑦1 − 𝑥1𝑦2 𝑥22 + 𝑦22
• Complex plane
• The complex conjugate number of 𝑧 = 𝑥 + 𝑖𝑦: 𝑧 = 𝑥 − 𝑖𝑦ҧ 𝑧 ҧ𝑧 = 𝑥2 + 𝑦2
𝑅𝑒 𝑍 = 𝑥 = 𝑧 + ҧ𝑧
2 , 𝐼𝑚 𝑍 = 𝑦 = 𝑧 + ҧ𝑧 2
x
y z = x + iy
13.2 Polar form of complex numbers.
• With 𝑥 = 𝑟 cos 𝜃, 𝑦 = 𝑟 sin 𝜃, the polar form of a complex number is 𝑧 = 𝑟 cos 𝜃 + 𝑖 sin 𝜃
in which
𝑟 = 𝑧 = 𝑥2 + 𝑦2 = 𝑧 ҧ𝑧 is the absolute value or modulus, and
𝜃 = arg 𝑧 = tan−1 𝑦
𝑥 is the argument, which is multivalued. The principal value of the argument is −𝜋 < Arg 𝑧 ≤ 𝜋 .
x
y z = x + iy
r 𝜃
• Question:
Which is greater? 2𝑖 vs. 5𝑖
• Triangle inequality
𝑧1 + 𝑧2 ≤ 𝑧1 + 𝑧2
𝑧1 + 𝑧2 + ⋯ + 𝑧𝑛 ≤ 𝑧1 + 𝑧2 + ⋯ + 𝑧𝑛
• Example 2:
Verify the triangle inequality with
𝑧1 = 1 + 𝑖 and 𝑧2 = −2 + 3𝑖
• 𝑧1𝑧2 = 𝑟1𝑟2 cos 𝜃1 + 𝜃2 + 𝑖 sin 𝜃1 + 𝜃2 , therefore 𝑧1𝑧2 = 𝑧1 𝑧2 and arg 𝑧1𝑧2 = arg 𝑧1 + arg 𝑧2
• 𝑧1
𝑧2 = 𝑟1
𝑟2 cos 𝜃1 − 𝜃2 + 𝑖 sin 𝜃1 − 𝜃2 , therefore
𝑧1
𝑧2 = 𝑧1
𝑧2 and arg 𝑧1
𝑧2 = arg 𝑧1 − arg 𝑧2
• By induction, 𝑧𝑛 = 𝑟𝑛 cos 𝑛𝜃 + 𝑖 sin 𝑛𝜃 , 𝑛 = ⋯ , −2, −1, 0, 1, ⋯
• De Moivre’s formula,
cos 𝜃 + 𝑖 sin 𝜃 𝑛 = cos 𝑛𝜃 + 𝑖 sin 𝑛𝜃
• Example:
Express cos 3𝜃 and sin 3𝜃 in terms of cos 𝜃, sin 𝜃 and their powers.
• Roots:
Consider 𝑧 = 𝑤𝑛, there are 𝑛 values for 𝑤 = 𝑛 𝑧. Find them.
(hint: use 𝑧 = 𝑟 cos 𝜃 + 𝑖 sin 𝜃 and 𝑤 = 𝑅 cos 𝜙 + 𝑖 sin 𝜙 )
• Example:
Find 𝑛 1 for 𝑛 = 2 and 3.
13.3 Derivative. Analytic function.
• A circle of radius 𝜌 and centre 𝑎: 𝑧 − 𝑎 = 𝜌
•
𝑧 − 𝑎 < 𝜌: open circular disk → 𝜌 -neighbourhood of 𝑎 𝑧 − 𝑎 ≤ 𝜌: closed circular disk
𝑧 − 𝑎 > 𝜌: exterior of circular disk 𝜌1 < 𝑧 − 𝑎 < 𝜌2: open annulus
𝜌1 ≤ 𝑧 − 𝑎 ≤ 𝜌2: closed annulus
𝑎 𝜌
• 𝑦 > 0: upper half plane 𝑦 < 0: lower half plane 𝑥 > 0: right half plane 𝑥 < 0: left half plane
• Domain is an open connected set.
• A boundary point of a set 𝑆 is a point with its every nbhd contains points in 𝑆 and 𝑆𝑐.
• Complex function
𝑤 = 𝑓 𝑧 = 𝑢 𝑥, 𝑦 + 𝑖𝑣 𝑥, 𝑦
• Example:
For 𝑤 = 1
𝑧 𝑧 ≠ 0 , find 𝑢 and 𝑣.
• 𝑓(𝑧) has a limit 𝑙 as 𝑧 → 𝑧0 from any direction, that is,
𝑧→𝑧lim0 𝑓(𝑧) = 𝑙
if for any 𝜖 > 0, there exists 𝛿 > 0 such that 𝑓 𝑧 − 𝑙 < 𝜖 for all 𝑧 ≠ 𝑧0 and 𝑧 − 𝑧0 < 𝛿.
• 𝑓(𝑧) is continuous at 𝑧 = 𝑧0 if lim
𝑧→𝑧0 𝑓(𝑧) = 𝑓(𝑧0).
• A complex function is differentiable at 𝑧 = 𝑧0 if 𝑓′ 𝑧0 = lim
𝑧→𝑧0
𝑓 𝑧 −𝑓(𝑧0) 𝑧−𝑧0
exists. Note the limit is taken from any direction.
• 𝑓′ 𝑧 is called the derivative of 𝑓 𝑧
• 𝑓 𝑧 is called analytic (or holomorphic) in some domain if it is differentiable in the domain.
• The differentiation rules are the same as those for the real functions.
• Example 4: Show that 𝑓 𝑧 = ҧ𝑧 is not analytic.
• Example: Show that
𝑓 𝑧 = 𝑧𝑛 is analytic in complex plane.
13.4 Cauchy-Riemann equations. Laplace equation
• Consider necessary conditions for 𝑓 𝑧 = 𝑢 𝑥, 𝑦 + 𝑖𝑣 𝑥, 𝑦 to be analytic in nbhd of 𝑧0 𝑥0, 𝑦0 , by taking the limit
(1) along the horizontal direction; and (2) along the vertical direction.
• 𝑓 is analytic in domain D iff 𝑢 and 𝑣 satisfy Cauchy-Riemann equations:
𝜕𝑢
𝜕𝑥 = 𝜕𝑣
𝜕𝑦 and 𝜕𝑣
𝜕𝑥 = − 𝜕𝑢
𝜕𝑦
• Example 1: Show that
𝑓 𝑧 = ҧ𝑧 does not satisfy C-R equations
• Example 2: Is 𝑓 𝑧 = 𝑒𝑥 cos 𝑦 + 𝑖 sin 𝑦 analytic?
• Show that, if 𝑓 𝑧 is analytic in a domain D, then both 𝑢 and 𝑣 satisfy 2D Laplace’s equation, respectively.
• 𝑣 is called a harmonic conjugate function of 𝑢 in D and vice versa.
• Example:
Find a harmonic conjugate function for 𝑢 = 𝑥2 − 𝑦2.