Information system application - databases - L1 - HK1

(1)

Nguiri hien swum de (K9 ve ghi re hp ten)

Lf TN Huyen Chin

Tnr&ng Khoa/B0 mon duyet (Kt vi ghi re he ten)

Thum Ngic Duy TRUONG DAI HOC VAN LANG

KHOA CONG NGHE THONG TIN

Made: 01 (Lan 1) Mon thi: INFORMATION SYSTEM APPLICATION - DATABASES

Khoa/Lop: I(24PM - 1-19C ICSI: 1 - Nam hoc: 2019-2020 Tiled gian thi: 45 phin0; 60 phnt 0; 75 philt 0; 90 phtita; 120 phut LI Hinh thfrc thi: Tiy Wan a Trac nghiem 0 Tyr luan + Trac nghiem

- Duqc sfr clang tai lieu 0 - Ithong su dung tii lieu 121

cuOi Kt

Sinh vien tra 16bi tit cá ctic cau hal sau vao glib, Mtn Mi thi ding, sau khi hoan thanh sinh vien nap iqi de' va gay lam bal thi cho Glom thj. Gicim thi kh6ng huong dein gi them.

CIL 1: [1.5 diem] Lf thuyet

1.1 Hay hoan thanh bang thuat ngir sau (trong giay lam bai): [0.5 diem]

STT Thu .@ ngfr Tieng Viet Thuat ngfk Tieng Anh Viet tit (neu co) I Urge do Ca se(

da filo

Database Schema

2 Sieu

du Ho

Metadata

3 Mei lien ket xac dinh Iden4bling relationship

4 Hut thuOc ham Functional Dependency FD

5 He quan tri ea se (la lieu Database Management

System DBMS

1.2 Hay neu dinh nghia Dung chat) 1 dm via& chuan h6a du lieu. Cho vi du. [1.0 diem]

Dinh neda (0.5 diem): Luoe de quan he R a dang chuan 1 (1NF - First Normal Form) nett moi thuOc tinh elm R deu chfra cac gia tri nguyen

tó

(atomic value), gia tri nay khong la mOt danh sach ck gia tri hose the gia tri phire hop (composite value).

Vi du (0.5 diem):

Urge de quan he R kh6ng a clang than 1 vi thuOc tinh Diem thi la thuOc tinh phfre hop.

(2)

Tong so san

Phai

hal gian trandau CAU LAC

139 (5)

LU'A TUCI (3) 091

(4) II

.(VraTranDaii

Dia chi

ti rign il ^MT01 ^M1 ⁹

S1 Tien L1 MT01 M2 7

52 Tree L1 MT01 M1 9

52 Trim L1 MT01 M2 8

S3 Hien L2 MT02 M1 5

Eugc d6 quan he R 6 INF vi cac thu6c tinh cüa R khong la thuOc tinh da tri, kh6ng la thu6c tinh phirc hgp.

Mew H9/fin Me lop Tenlop Moniwc Diem

Si Tien L1 MT01 M1 9

Si Tien L1 MT01 M2 7

S2 Tit L1 MT01 M1 9

S2 Trim L1 MT01 M2 8

S3 Hien L2 MT02 M1 5

flu 2: [1.5 diem] Luo:c do Co ser dit

Cho Mo hinh quan h (ERD) sau, ban hay thiet k Elroy d6 ca s6 dir lieu cho rno hinh nay (Wu sinh vien phai có so tin? hi các quan h trong luve do):

(3)

Li:yr ta Ca sit dii• lieu:

PHONG (MA ph6ng, Dia chi, T6ng

s6

sari)

1RANDAU (MA trail Mu, Ngly thi du, Gia bAt Mu, LUATUOI (TuOi, Thai gian tan Mu)

DOT (MA d'Oi, Phái, Ttniii,

ma

CLB)

CAULACBO

(via

CLB, so, Duang, QuAnDCA, Tinh/TP)

VANDONGVIEN (MA VDV, Ten, Dia chi, Phai,

ma

CLB, Tuth) CHITIETDANGKY (MA &A, MA VDV)

CHITIETGAPGO (MA trait du. MA doi, MA CLB, Ti s6) TRONGTAI (MA trait Mu, Ho ten, Loai trong tni

SODIENTHOAI (MA VDV, SO then thoai) CAU 3:

[4 Sim] Chan hoa de 1[0

Cho mOt lucc

d6

quan h R(A,B,C,D,E,F,G,H,I,J,K,L) va tAp pitii thueic ham F={K—>G,G—>K,K—>EF,BC—>D,BH—>ALGL—>J,D—>A}.

3.1 Tim

tat

ea khoa cüa ltrqc d6 quan h R tren. [1.5 diem]

K —> EF, BC —> D, BH —> AI, GL —> J, D—>A}

(4)

Left(f) = { BCGICELDH } Right(f) = { DKGEFAIJ }

= U — URigho ={ ABCDEFGHIJKL } —{DKGEFALI } = { BCHL } N+F = { BCHL }F= { BCHLDA} * U

D = Umghtm — thso = { DKGEFAIJ } { BCGKELDH } = FAH }

£ =U — .71±F 72) = { ABCDEFGHIJICL } — { BCHLDAFIJ } = { EGK}

= 2' — 1 = EG, EIC, GK EGK

Voi {ACC; }+F BCHLE }+F ={BCHLEDAI } * U c> Vay { BCHLE } Thong la mOt kh6a cfm R

Voi {Nati }÷F ={BCHLG }+F ={BCHLGDICAEFIJ } = U fz:> Kay { BCHLG } la mOt khoa R

c> Loai be tap cha cita G: { EG },{GK }, { EGK }

V6i {N.C; }+F

=

BCHLK }+F ={ BCHLICDAEFIGJ } = U c> Voy BCHLK } la m'Ot kh6a cüa R

Lti> Loai bo t..3p cha K: { EK }

Ket Juan: R co 2 khoa BCHLG } va BCHLK } 3.2 Phan ra lucre d quan h R tren. [2.5 diem]

F = { K —> G,

(5)

12.2 (BCDEFGHIJICL) G K

= IGICEFI CA)

R8 (BCGHIL) BH -> I

= {BHIA}

R7 (J) R (ABCDEFGHIJKL)

Ri (G ICEF) R4 (BCDGHIJL) BC D

• /11CIFF = {BCDM

R5 (BCD) R6 (BCGHIJL) GL-›.1 LrF = {GL

R9 (BHI) RI (BCGHL) Ire ={B }

C6 =-{C}

G±F GKEF 114F =MI

L+F = { L Kt luiin: p = ( DA ),

1( 3 (c

KEF), R5 R7 (a.1), R9 (Bill) Rio (BCGH1)

CAU 4: [3 diem] Di sti quan he

(6)

KQ

C. 7Ccre(r)

4.1 Tinh Neu that Dui

A

quan he: [1.5 diem]

Cho r va s la hai quan he rilux sau:

r ABCDE

a b b a b h

b b b d d h

0 OD cct 0 C4

b a h e g f

c b a g d g

sDEFG abc f gda c bbgb

Tinh cac bi6u thdc dal s6 quan he' sau day:

a. RABc(r) TCDEF(ar4‘rr(S))

KQ A BC

b b c a d a b d c h h f

b. rcBc(aBn,(r)) fl icEF(s)

LKQ

a

7EDE(aDtE(s))

d. ituon(r) TcEpo(s)

KQBDEF G

(7)

b b c bb

b b g b b

a d a a b

b d cbb

h h f null null

4.2 Ng6n nee Doi s6 quan h (NNDSQH): [1.5 diim]

Cho the quan h sau:

Xicong (Miliarcknz Tenguemg, ThanhPho)

ScinPhim (Aft7SetnPhlim TenScinPhcim, MauSeic, TrmigLigyng) NhetCungCcip (MaNhezCunRCap, TenNhaCungCcip, SoDienThogi)

PhilnPhoi (MitidnPhiim, MaXwang, MaNhaCunzap, SaLuvng, DarzGia)

wet

the truy van sau bang NNDSQH:

Hay cho Het Ma san pham, Ten san pham, Dun gia sau khi da firth them 10% time VAT cho nhang san pham c6 mau DO da dugc phan phei.

ThMaSanPham, TenSanPham, DonGias 1. I CfMauSae = 'DO'

(SanPham NPhanPhoi)

Hay cho biet Ma nha cung cap, Ten cung cAp cila cac nha cung cap phan phoi cho cac xtremg san xuat a thanh phe HCM hodc duce phan phei vei se lugng tit 1000 trO. len.

11MaNhaCungCap, TenNhaCungCap aThanhPho = 'HCM' V SoLuong >=1000

(NhaCungCap D4 PhanPhoi)

Hay cho biet Ma san pham, Ten san pham cUa nhitng san pham chwa dugc phan phoi.

WMaSanPham, TenSanPham

SanPham

ThMaSanPham, TenSanPham

(SanPham IXIPhanPhoi)

Hay cho biet Ten nha cung cap cimg vai tong s6 Krung san pham duce phan ph& cfm team Nha cung cap.

TenNhaCungCapTSUM(SoLuong)

(NhaCungCap N PhanF'hoi)

Hay cho biet Ma nha cung cAp da phan ph& tat ca san pham cüa Gong ty.

ThMaNhaCungCap, MaSanPham

PhanPhoi : 71

^MaSanPham

SanPham

000