LAMPIRAN
Lampiran 1. Warna Sirup
Panelis Konsentrasi Tu u du
Sintetis 2.5% 5% 7.5% 10% 12.5%
1 4 4 2 2 2 1 15 2.5000 -0.6833
2 3 5 4 2 2 1 17 2.8333 -0.3500
3 5 4 3 3 3 3 21 3.5000 0.3167
4 4 5 4 3 2 1 19 3.1667 -0.0167
5 4 5 3 2 2 2 18 3.0000 -0.1833
6 4 5 3 3 2 2 19 3.1667 -0.0167
7 4 5 5 3 3 3 23 3.8333 0.6500
8 4 5 5 3 3 2 22 3.6667 0.4833
9 4 4 3 2 2 2 17 2.8333 -0.3500
10 5 4 4 4 3 3 23 3.8333 0.6500
11 4 5 4 4 3 3 23 3.8333 0.6500
12 4 5 4 2 2 2 19 3.1667 -0.0167
13 3 4 4 3 3 3 20 3.3333 0.1500
14 3 4 4 3 3 3 20 3.3333 0.1500
15 4 5 3 3 3 2 20 3.3333 0.1500
16 5 4 3 3 2 1 18 3.0000 -0.1833
17 3 4 4 2 2 2 17 2.8333 -0.3500
18 2 3 4 3 2 2 16 2.6667 -0.5167
19 2 3 3 4 4 3 19 3.1667 -0.0167
20 4 4 3 2 2 1 16 2.6667 -0.5167
Tp 75 87 72 56 50 42
p 3.75 4.35 3.6 2.8 2.5 2.1 (T...) 382
dp 0.5667 1.1667 0.4167 -0.3833 -0.6833 -1.0833 (X…) 3.1833
SD 0.8507 0.6708 0.7539 0.6959 0.6070 0.7881
SE 0.3885 0.3064 0.3443 0.3178 0.2772 0.3599
TP2 5625 7569 5184 3136 2500 1764 25778
W1 = [ 4(0,5667) + 4(1,1667) + 2(0,4167) + 2(-0,3833) + 2(-0,6833) + 1(-1,0833)] = 4,5500
W2 = [ 3(0,5667) + 5(1,1667) + 4(0,4167) + 2(-0,3833) + 2(-0,6833) + 1(-1,0833)] = 5,9833
W3 = [ 5(0,5667) + 4(1,1667) + 3(0,4167) + 3(-0,3833) + 3(-0,6833) + 3(-1,0833)] = 2,3000
W20= [ 4(0,5667) + 4(1,1667) + 3(0,4167) + 2(-0,3833) + 2(-0,6833) + 1(-1,0833)] = 4,9667
N = Wi x du
= [4,5500 (-0,6833) + 5,9833 (-0,3500) + … + 4,9667 (-0,5167)] = -3,4061
D = du2 x dp2
= [ (-0,6833)2 + (-0,3500)2 +… + (-0,5167)2 x (0,5667)2 + (1,1667)2 + (0,4167)2 + (-0,3833)2 + (-0,6833)2 + (-1,0833)2]
= 3,1056 x 2,4697 = 7,6699
Faktor Koreksi (FK)
6 x 20
) T..
( 2
=
120
(382)2
= 1216,033
Jumlah Kuadrat
Jumlah Kuadrat total (JK total) = p2 – FK
Jumlah Kuadrat Ulangan =
Perlakuan Jml
) Tu
( 2
FK
= 1216,033
6
) 16 ( ... ) 17 ( ) 15
( 2 2 2
= 18,6333
Jumlah Kuadrat Perlakuan = Ulangan Jml
) Tp
( 2
FK
= 1216,033
20
) 42 ( ... ) 87 ( ) 75
( 2 2 2
= 72,8667
Jumlah Kuadrat Galad Acak = JK Total – JK Ulangan – JK Perlakuan = 133,9667 – 18,6333 – 72,8667
= 42,4667
JK Non Additivitas =
D ) (N2
=
7,6699 ) (-3,4061 2
= 1,5126
Tabel Sidik Ragam Uji Additivitas
Sumber Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 19 18,6333
Perlakuan 5 72,8667
Galad acak 95 42,4667
Non aditivitas 1 1,5126 1,5126 3,4719 3,955 6,949
sisa 94 40,9540 0,4357
Tabel Sidik Ragam
Sumber Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 19 18,6333 0,9807 2,1939* 1,709 2,132
Perlakuan 5 72,8667 14,5733 32,6013** 2,323 3,312
Galad acak 95 42,4667 0,4470
Total 119
* Antar ulangan berbeda sangat nyata ** Antar perlakuan berbeda sangat nyata
KV = √
…, 100%
= √0,4470
3,1833 100%
= 21,00%
Uji Beda Nyata Jujur (BNJ) 5%
BNJ 5%: W = α(p, )Sx
Sx = 0,4470
20 = 0,14949 BNJ 5% = 3,945 x 0,14949
= 0,58974
Warna
sintetis 2.5% 5% 7.5% 10% 12.5%
Purata
SE
3,75 ± 0,39
4,35 ± 0,31
3,60 ± 0,34
2,80 ± 0,32
2,50 ± 0,28
2,10 ± 0,36
Lampiran 2. Aroma Sirup
Panelis Konsentrasi Tu u du
Sintetis 2.5% 5% 7.5% 10% 12.5%
1 2 4 2 2 1 1 12 2.0000 -0.9200
2 4 5 2 2 3 3 19 3.1667 0.2467
3 2 2 2 3 3 3 15 2.5000 -0.4200
4 5 4 3 2 2 1 17 2.8333 -0.0867
5 4 5 5 4 4 2 24 4.0000 1.0800
6 3 5 3 3 3 2 19 3.1667 0.2467
7 4 4 3 2 2 1 16 2.6667 -0.2533
8 5 4 4 3 3 2 21 3.5000 0.5800
9 5 4 3 2 2 1 17 2.8333 -0.0867
10 4 4 3 2 2 2 17 2.8333 -0.0867
11 4 4 3 3 2 2 18 3.0000 0.0800
12 5 4 3 2 2 1 17 2.8333 -0.0867
13 5 4 4 3 3 3 22 3.6667 0.7467
14 3 3 2 1 2 2 13 2.1667 -0.7533
15 3 4 3 3 2 2 17 2.8333 -0.0867
16 3 3 2 2 2 2 14 2.3333 -0.5867
17 3 3 3 3 2 2 16 2.6667 -0.2533
18 4 2 2 2 2 2 14 2.3333 -0.5867
19 4 4 4 4 4 4 24 4.0000 1.0800
20 4 4 4 3 3 3 21 3.5000 0.5800
21 3 4 3 3 2 2 17 2.8333 -0.0867
22 4 4 3 2 1 1 15 2.5000 -0.4200
23 4 5 3 2 1 2 17 2.8333 -0.0867
24 4 4 3 2 2 1 16 2.6667 -0.2533
25 4 4 3 3 3 3 20 3.3333 0.4133
Tp 95 97 75 63 58 50 (T..) 438
p 3.80 3.88 3.00 2.52 2.32 2.00 (X…) 2.9200
dp 0.8800 0.9600 0.0800 -0.4000 -0.6000 -0.9200
SD 0.8660 0.7810 0.7638 0.7141 0.8021 0.8165
SE 0.3575 0.3224 0.3153 0.2948 0.3311 0.3370
W1 = [ 2(0,8800) + 4(0,9600) + 2(0,0800) + 2(-0,4000) + 1(-0,6000) + 1(-0,9200)] = 3,4400
W2 = [ 4(0,8800) + 5(0,9600) + 2(0,0800) + 2(-0,4000) + 3(-0,6000) + 3(-0,9200)] = 3,1200
W3 = [ 2(0,8800) + 2(0,9600) + 2(0,0800) + 3(-0,4000) + 3(-0,6000) + 3(-0,9200)] = -1,9200
W25= [ 4(0,8800) + 4(0,9600) + 3(0,0800) + 3(-0,4000) + 3(-0,6000) + 3(-0,9200)] = 1,8400
N = Wi x du
= [3,4400 ( -0,9200) + 3,1200 (0,2467) + … + 1,8400 (0,4133)] = -2,8224
D = du2 x dp2
= [ (-0,9200)2 + (0,2467)2 +… + (0,4133)2 x (0,8800)2 + (0,9600)2 + (0,0800)2 + (-0,4000)2 + (-0,6000)2 + (-0,9200)2]
= 6,5622 x 2,2224 = 14,5839
Faktor Koreksi (FK)
6 x 25
) T..
( 2
=
150
(438)2
= 1278,96
Jumlah Kuadrat
Jumlah Kuadrat total (JK total) = p2 – FK
Jumlah Kuadrat Ulangan =
Perlakuan Jml
) Tu
( 2
FK
= 1278,96
6
) 20 ( ... ) 19 ( ) 12
( 2 2 2
= 39,3733
Jumlah Kuadrat Perlakuan = Ulangan Jml
) Tp
( 2
FK
= 1278,96
25
) 50 ( ... ) 97 ( ) 95
( 2 2 2
= 76,7200
Jumlah Kuadrat Galad Acak = JK Total – JK Ulangan – JK Perlakuan = 167,04 – 39,3733– 76,7200
= 50,9467
JK Non Additivitas =
D ) (N2
=
14,5839 ) (-2,8224 2
= 0,5462
Tabel Sidik Ragam Uji Additivitas
Sumber Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 24 39,3733
Perlakuan 5 76,7200
Galad acak 120 50,9467
Non aditivitas 1 0,5462 0,5462 1,2897 3,925 6,854
Sisa 119 50,4005 0,4235
Tabel Sidik Ragam
Sumber Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 24 39,3733 1,6406 3,8642* 1,610 1,950
Perlakuan 5 76,7200 15,3440 36,1413** 2,290 3,170
Galad acak 120 50,9467 0,4246
Total 149
* Antar ulangan berbeda sangat nyata ** Antar perlakuan berbeda sangat nyata
KV = √
…, 100%
= √ ,
, 100%
= 22,31%
Uji Beda Nyata Jujur (BNJ) 5%
BNJ 5%: W = α(p, )Sx
Sx = , = 0,1303
BNJ 5% = 3,92 x 0,1303 = 0,51077
Aroma
sintetis 2,5% 5% 7,5% 10% 12,5%
Purata
SE
3,80 ± 0,36
3,88 ± 0,32
3,00 ± 0,32
2,52 ± 0,29
2,32 ± 0,33
2,00 ± 0,34
Lampiran 3. Kekentalan Sirup
Panelis Konsentrasi Tu u du
Sintetis 2.5% 5% 7.5% 10% 12.5%
1 2 5 4 3 2 2 18 3.0000 -0.3600
2 3 3 4 3 3 3 19 3.1667 -0.1933
3 4 4 4 3 2 2 19 3.1667 -0.1933
4 4 5 4 3 3 2 21 3.5000 0.1400
5 3 3 3 3 3 4 19 3.1667 -0.1933
6 3 3 3 3 4 4 20 3.3333 -0.0267
7 3 3 3 3 3 3 18 3.0000 -0.3600
8 4 4 4 3 4 4 23 3.8333 0.4733
9 4 4 4 4 4 4 24 4.0000 0.6400
10 3 3 3 3 3 3 18 3.0000 -0.3600
11 3 3 3 3 3 3 18 3.0000 -0.3600
12 3 3 3 3 3 3 18 3.0000 -0.3600
13 3 5 4 4 4 3 23 3.8333 0.4733
14 4 4 4 4 4 4 24 4.0000 0.6400
15 3 4 4 4 3 3 21 3.5000 0.1400
16 4 2 4 3 3 3 19 3.1667 -0.1933
17 2 3 2 3 3 3 16 2.6667 -0.6933
18 2 3 4 4 3 3 19 3.1667 -0.1933
19 4 4 4 4 4 4 24 4.0000 0.6400
20 4 4 4 4 4 4 24 4.0000 0.6400
21 3 3 3 3 3 3 18 3.0000 -0.3600
22 3 3 3 3 3 3 18 3.0000 -0.3600
23 4 4 5 5 2 1 21 3.5000 0.1400
24 3 3 3 3 3 3 18 3.0000 -0.3600
25 4 5 4 4 4 3 24 4.0000 0.6400
Tp 82 90 90 85 80 77 (T..) 504
p 3.28 3.6 3.6 3.4 3.2 3.08 (X…) 3.3600
dp -0.0800 0.2400 0.2400 0.0400 -0.1600 -0.2800
SD 0.6782 0.8165 0.6455 0.5774 0.6455 0.7594
SE 0.2659 0.3201 0.2530 0.2263 0.2530 0.2977
W1 = [ 2(-0,0800) + 5(0,2400) + 4(0,2400) + 3(0,0400) + 2(-0,1600) + 2(0,2800)] = 1,2400
W2 = [ 3(-0,0800) + 3(0,2400) + 4(0,2400) + 3(0,0400) + 3(-0,1600) + 3(0,2800)] = 0,2400
W3 = [ 4(-0,0800) + 4(0,2400) + 4(0,2400) + 3(0,0400) + 2(-0,1600) + 2(0,2800)] = 0,8400
W25= [ 4(-0,0800) + 5(0,2400) + 4(0,2400) + 4(0,0400) + 4(-0,1600) + 3(0,2800)] = 0,5200
N = Wi x du
= [1,2400 (-0,3600) + 0,2400 (-0,1933) + … + 0,5200 (0,6400)] = 0,4685
D = du2 x dp2
= [ (-0,3600)2 + (-0,1933)2 +… + (0,6400)2 x (-0,0800)2 + (0,2400)2 + (0,2400)2 + (0,0400)2 + (-0,1600)2 + (-0,2800)2]
= 4,2600 x 0,1488 = 0,6339
Faktor Koreksi (FK)
6 x 25
) T..
( 2
=
150
(504)2
= 1693,44
Jumlah Kuadrat
Jumlah Kuadrat total (JK total) = p2 – FK
Lampiran 3. (lanjutan)
Jumlah Kuadrat Ulangan =
Perlakuan Jml
) Tu
( 2
FK
= 1693,44
6
) 24 ( ... ) 19 ( ) 18
( 2 2 2
= 25,5600
Jumlah Kuadrat Perlakuan = Ulangan Jml
) Tp
( 2
FK
= 1693,44
25
) 77 ( ... ) 90 ( ) 82
( 2 2 2
= 5,6800
Jumlah Kuadrat Galad Acak = JK Total – JK Ulangan – JK Perlakuan = 74,5600 – 25,5600 – 5,6800
= 43,3200
JK Non Additivitas =
D ) (N2
=
0,6339 ) (0,4685 2
= 0,3463
Tabel Sidik Ragam Uji Additivitas
Sumber Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 24 25,5600
Perlakuan 5 5,6800
Galad acak 120 43,3200
Non aditivitas 1 0,3463 0,3463 0,9590 3,925 6,854
sisa 119 42,9737 0,3611
Tabel Sidik Ragam
Sumber Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 24 25,5600 1,0650 2,9501* 1,606 1,948
Perlakuan 5 5,6800 1,1360 3,1468** 2,292 3,176
Galad acak 120 43,3200 0,3610
Total 149
* Antar ulangan berbeda sangat nyata ** Antar perlakuan berbeda nyata
KV = √
…, 100%
= √0,3610
3,3600 100%
= 17,88%
Uji Beda Nyata Jujur (BNJ) 5%
BNJ 5%: W = α(p, )Sx
Sx = 0,3610
25 = 0,1202 BNJ 5% = 3,92 x 0,1202
= 0,47118
Kekentalan
sintetis 2.5% 5% 7.5% 10% 12.5%
Purata
SE
3,28 ± 0,27
3,60 ± 0,32
3,60 ± 0,25
3,40 ± 0,23
3,20 ± 0,25
3,08 ± 0,40
Lampiran 4. Rasa Sirup
Panelis Konsentrasi Tu u du
Sintetis 2.5% 5% 7.5% 10% 12.5%
1 4 5 4 3 2 1 19 3,1667 0,0933
2 4 2 2 2 3 3 16 2,6667 -0,4067
3 2 3 4 4 5 5 23 3,8333 0,7600
4 5 5 3 2 2 1 18 3,0000 -0,0733
5 4 4 4 3 3 3 21 3,5000 0,4267
6 4 4 4 3 3 2 20 3,0000 3,0000
7 4 4 3 3 2 2 18 3,0000 -0,0733
8 5 4 3 3 3 2 20 3,3333 0,2600
9 4 4 3 3 2 2 18 3,0000 -0,0733
10 4 4 3 2 2 1 16 2,6667 -0,4067
11 4 4 4 3 2 2 19 3,1667 0,0933
12 4 4 4 3 2 2 19 3,1667 0,0933
13 5 4 4 3 2 1 19 3,1667 0,0933
14 4 2 2 3 2 1 14 2,3333 -0,7400
15 3 4 4 3 3 3 20 3,3333 0,2600
16 4 4 3 4 4 2 21 3,5000 0,4267
17 2 3 2 2 2 2 13 2,1667 -0,9067
18 4 2 2 3 3 2 16 2,6667 -0,4067
19 5 4 4 3 3 3 22 3,6667 0,5933
20 3 4 4 4 4 4 23 3,8333 0,7600
21 4 4 3 3 3 2 19 3,1667 0,0933
22 4 3 2 2 1 1 13 2,1667 -0,9067
23 5 5 3 2 2 1 18 3,0000 -0,0733
24 4 4 3 2 2 2 17 2,8333 -0,2400
25 5 4 4 3 3 2 21 3,5000 0,4267
Tp 100 94 81 71 65 52 (T..) 463
p 4 3,76 3,24 2,84 2,6 2,08 (X..) 3,0733
dp 0,9267 0,6867 0,1667 -0,2333 -0,4733 -0,9933
SD 0,8165 0,8307 0,7789 0,6245 0,8660 0,9967
SE 0,3370 0,3429 0,3215 0,2578 0,3575 0,4114
W1 = [ 4(0,9267) + 5(0,6867) + 4(0,1667) + 3(-0,2333) + 2(-0,4733) + 1(-0,9933)] = 5,1667
W2 = [ 4(0,9267) +2 (0,6867) + 2(0,1667) + 2(-0,2333) + 3(-0,4733) + 3(-0,9933)] = 0,5467
W3 = [ 2(0,9267) + 3(0,6867) + 4(0,1667) + 4(-0,2333) + 5(-0,4733) + 5(-0,9933)] = -3,6867
W25= [ 5(0,9267) + 4(0,6867) + 4(0,1667) + 3(-0,2333) + 3(-0,4733) + 2(-0,9933)] = 3,9400
N = Wi x du
= [ 5,1667(0,0933) + 0,5467 (-0,4067) + … + 3,9400 (0,4267)] = 2,7066
D = du2 x dp2
= [ (0,0933)2 + (-0,4067)2 +… + (0,4267)2 x (0,9267)2 + (0,6867)2 + (0,1667)2 + (-0,2333)2 + (-0,4733)2 + (-0,9933)2]
= 13,9991 x 1,6365 = 22,9093
Faktor Koreksi (FK)
6 x 25
) T..
( 2
=
150
(463)2
Lampiran 4. (lanjutan)
Jumlah Kuadrat
Jumlah Kuadrat total (JK total) = p2 – FK
= [(4)2 (5)2 (4)2 ...(2)2]1429,127 = 163,8733
Jumlah Kuadrat Ulangan =
Perlakuan Jml
) Tu
( 2
FK
= 1429,127
6
) 21 ( ... ) 16 ( ) 19
( 2 2 2
= 30,3733
Jumlah Kuadrat Perlakuan = Ulangan Jml
) Tp
( 2
FK
= 1429,127
25
) 52 ( ... ) 94 ( ) 100
( 2 2 2
= 65,5533
Jumlah Kuadrat Galad Acak = JK Total – JK Ulangan – JK Perlakuan = 163,8733 – 30,3733 – 65,5533
= 67,9467
JK Non Additivitas =
D ) (N2
=
22,9093 ) (2,7066 2
Tabel Sidik Ragam Uji Additivitas Sumber
Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 24 30,3733
Perlakuan 5 65,5533
Galad acak 120 67,9467
Non aditivitas 1 0,3198 0,3198 0,5627 3,925 6,854
Sisa 119 67,6269 0,5683
F Hit < F Tabel 5% < F Tabel 1% Data aditif
Tabel Sidik Ragam Sumber
Ragam Db JK KT FHitung
Ftabel
5% 1%
Ulangan 24 30,3733 1,2656 2,2351* 1,610 1,950
Perlakuan 5 65,5533 13,1107 23,1546** 2,290 3,170
Galad acak 120 67,9467 0,5662
Total 149
Lampiran 4. (lanjutan)
KV = √
.. 100%
= √ ,
, 100%
= 24,48%
Uji Beda Nyata Jujur (BNJ) 5%
BNJ 5%: W = α(p, )Sx
Sx = , = 0,1505
BNJ 5% = 3,92 x 0,1505 = 0,58996
Rasa
sintetis 2,5% 5% 7,5% 10% 12,5%
Purata
SE
4,00 ± 0,34
3,76 ± 0,34
3,24 ± 0,32
2,84 ± 0,26
2,60 ± 0,36
2,08 ± 0,41
Kadar Air Daging Umbi Bit Merah Ulangan 1
I II III
Massa cawan (g) 43,6140 31,6745 46,1983
Massa cawan + sampel (g) 44,6133 32,6773 47,2162
Massa sampel (g) 0,9993 1,0028 1,0179
Penimbangan 1 43,7172 31,7808 46,3060
Penimbangan 2 43,7182 31,7797 46,3020
Penimbangan 3 43,7181 31,7796 46,3020
Penimbangan 4 43,7166 31,7810 46,3029
Penimbangan 5 43,7166 31,7808 46,3027
Massa air (g) 0,8967 0,8965 0,9135
Kadar air (%) 89,7328 89,3997 89,7436
Purata kadar air (%) b/b 89,6254
SD 0,1955
Lampiran 5. (lanjutan) Ulangan 2
I II III
Massa cawan (g) 43,0668 38,7708 48,0234
Massa cawan + sampel (g) 44,0524 39,7768 49,0296
Massa sampel (g) 0,9856 1,0060 1,0062
Penimbangan 1 43,1514 38,8680 48,1167
Penimbangan 2 43,1503 38,8678 48,1150
Penimbangan 3 43,1509 38,8677 48,1159
Penimbangan 4 43,1509 38,8677 48,1152
Penimbangan 5 43,1509 38,8677 48,1152
Massa air (g) 0,9015 0,9091 0,9144
Kadar air (%) 91,4671 90,3678 90,8766
Purata kadar air (%) b/b 90,9038
SD 0,5502
Ulangan 3
I II III
Massa cawan (g) 48,4787 43,7765 43,4758
Massa cawan + sampel (g) 49,4945 44,7811 44,4777
Massa sampel (g) 1,0158 1,0046 1,0019
Penimbangan 1 48,5895 43,8746 43,5824
Penimbangan 2 48,5888 43,8738 43,5814
Penimbangan 3 48,5885 43,8737 43,5810
Penimbangan 4 48,5888 43,8743 43,5820
Penimbangan 5 48,5888 43,8743 43,5818
Massa air (g) 0,9057 0,9068 0,8959
Kadar air (%) 89,1613 90,2648 89,5771
Purata kadar air (%) b/b 89,6154
SD 0,5771
Lampiran 5. (lanjutan)
Contoh Perhitungan Kadar Air (b/b)
Cawan Petri 1 (data diambil dari tabel kadar air daging umbi bit merah pada ulangan 3)
Massa Sampel = (massa cawan + sampel) – massa cawan = 49,4945 g – 48,4787 g
= 1,0158 g
Massa air = (massa cawan + sampel) - (massa cawan + sampel) setelah pengovenan
Kadar air = x 100%
= ,
, x 100% = 89,1613 %
Ulangan Purata Kadar Air ± SE
1 89,6254 ± 0,4857
2 90,9038 ±1,3668
3 89,6154 ±1,4337
Purata ± SE 90,0482 ± 1,0954
Data dan Contoh Perhitungan Kadar Betalain Data Kadar Betalain Daging Bit
Ulangan Absorbansi Betanin
(mg/100g)
Vulgaxantin I (mg/100g)
Betalain (b.b) (mg/100g) A538 A476 A600
1 0,399 0,269 0,054 89,457 41,966 126,291
2 0,421 0,277 0,055 83,839 42,493 131,950
3 0,401 0,270 0,058 84,325 40,800 126,291
X 0,407 0,272 0,056 85,874 41,753 127,627
SD 0,012 0,004 0,002 3,113 0,866 3,834
SE 0,030 0,010 0,005 2,232 0,621 11,666
Data Kadar Betalain Sari Daging Bit
Ulangan Absorbansi Betanin
(mg/100g)
Vulgaxantin I (mg/100g)
Betalain (b.b) (mg/100g) A538 A476 A600
1 0,438 0,249 0,057 46,552 15,562 62,123
2 0,455 0,269 0,056 55,728 20,946 76,674
3 0,474 0,312 0,060 67,46 32,242 99,702
X 0,456 0,277 0,058 56,580 22,917 79,500
SD 0,018 0,032 0,002 10,480 8,513 18,948
Lampiran 6. (Lanjutan)
Kadar Betalain Daging Umbi Bit merah
Ulangan Kadar Betalain (mg/100 g) dalam (b.b)
1 126,291
2 131,950
3 124,639
Purata ± SE 127,627 ± 11,666
Purata Kandungan betalain (mg/100 g) = , , , = 127,627
Standar Deviasi = 3,834 n = Jumlah ulangan (3) SE = t 2
√
= 4,303 , √ = 11,666
Ulangan Kadar Betalain (mg/100 g) dalam (b.k)
1 1269,027
2 1325,891
3 1252,427
Purata ± SE 1282,448 ± 95,714
Purata Kandungan betalain (mg/100 g) = , , ,
= 1282,448 Standar Deviasi = 38,527
n = Jumlah ulangan (3) SE = t 2
√ = 4,303 ,
Contoh Perhitungan Kadar Betalain
= 1,095( − )
= − −
3,1
= − Kadar Betalain dalam (b.b)
= 1,095( 0,421− 0,277) = 0,4007 = 0,277− − ,
, = 0,1275 = 0,421− 0,4007 = 0,0202
- Betanin = , x faktor pengenceran = , x 2,5
= 0,89457 mg/100 ml (dalam 1 g /100 ml sampel) = 89,457 mg/100 g sampel
- Vulgaxanthin = , x faktor pengenceran = , x 2,5
= 0,42493 mg/100 ml (dalam 1 g/ 100 ml sampel) = 42,493 mg/100 g sampel
Kadar betalain = 89,457 mg/100 g + 42,493 mg/100 g = 131,950 mg/100 g
Kadar Betalain dalam (b.k)
- Kadar Air = 90,0482 % (b/b)
- Berat Kering = 100% - 90,0482% = 9,9518% - Dalam 1 g sampel = , = 0,099518
Kadar betalain (b. k) = , / ,
Lampiran 7.
Viskositas Sirup Sari Umbi Bit Merah Konsentrasi 5%
Ulangan Viskositas sirup sari umbi bit merah konsentrasi
5%
1 14,0206 cP
2 14,0258 cP
3 14,0600 cP
Purata ± SE 14,0355 cP ± 0,0531
Purata viskositas sirup sari umbi bit merah konsentrasi 5%
= , , , = 14,0355
Standar Deviasi = ∑( )
= ( , , ) ( , , ) ( , , )
= ( , ) ( , ) ( , )
= ( , ) ( , ) ( , )
= , = 4,58175 = 0,0214
n = Jumlah ulangan (3) SE = t 2
√
Contoh perhitungan viskositas sirup sari umbi bit merah
(1) t = 1938,85 detik = . −
1,2928 = 5,595. 10 . 1938,85−
5,1754 1938,85
1,2928 = 10,8478− 2,2669.10
Lampiran 8
Data Hasil Penyinaran terhadap Degradasi Warna Sirup Sari Umbi Bit Merah 5% Intensitas 803,208 lux
y = -0,005x + 0,405 R² = 0,889
y = -0,013x - 0,9 R² = 0,886 y = 0,036x + 2,457
R² = 0,876
-2 -1 0 1 2 3 4
0 5 10 15
A b s .5 5 4 n m
W aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,005x + 0,517 R² = 0,920
y = -0,010x - 0,658 R² = 0,922 y = 0,020x + 1,931
R² = 0,919
-1 -0,5 0 0,5 1 1,5 2 2,5
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,005x + 0,509 R² = 0,871
y = -0,010x - 0,673 R² = 0,862 y = 0,022x + 1,960
R² = 0,851
-1 -0,5 0 0,5 1 1,5 2 2,5
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
Intensitas 803,21 lux
Intensitas 1.718,72 lux
y = -0,003x + 0,453 R² = 0,885
y = -0,009x - 0,790 R² = 0,879 y = 0,021x + 2,201
R² = 0,869
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5 3
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,002x + 0,219 R² = 0,858
y = -0,013x - 1,513 R² = 0,848 y = 0,065x + 4,533
R² = 0,832
-3 -2 -1 0 1 2 3 4 5 6
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,005x + 0,394 R² = 0,978
y = -0,016x - 0,909 R² = 0,993 y = 0,037x + 2,529
R² = 0,969
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5 3 3,5
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
Intensitas 1.718,72 lux
y = -0,005x + 0,522 R² = 0,976
y = -0,011x - 0,648 R² = 0,978 y = 0,024x + 1,911
R² = 0,977
-1 -0,5 0 0,5 1 1,5 2 2,5
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,007x + 0,506 R² = 0,953
y = -0,015x - 0,679 R² = 0,957 y = 0,031x + 1,971
R² = 0,961
-1 -0,5 0 0,5 1 1,5 2 2,5
0 5 10 15
A b s . 5 5 4 n m
W aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,007x + 0,459 R² = 0,926
y = -0,018x - 0,776 R² = 0,938 y = 0,042x + 2,171
R² = 0,945
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5 3
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
Intensitas 2.465,68 lux
y = -0,003x + 0,218 R² = 0,827
y = -0,016x - 1,521 R² = 0,849 y = 0,079x + 4,582
R² = 0,865
-3 -2 -1 0 1 2 3 4 5 6
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,006x + 0,409 R² = 0,958
y = -0,017x - 0,890 R² = 0,949 y = 0,047x + 2,429
R² = 0,938
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5 3 3,5
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,006x + 0,503 R² = 0,881
y = -0,013x - 0,684 R² = 0,871 y = 0,029x + 1,978
R² = 0,863
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5
0 5 10 15
A b s . 5 5 4 n m
W aktu (jam)
A.554
ln A.554
Intensitas 2.465,68 lux
y = -0,008x + 0,527 R² = 0,952
y = -0,017x - 0,639 R² = 0,960 y = 0,035x + 1,891
R² = 0,966
-1 -0,5 0 0,5 1 1,5 2 2,5
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,008x + 0,476 R² = 0,924
y = -0,020x - 0,737 R² = 0,912 y = 0,047x + 2,084
R² = 0,895
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5 3
0 5 10 15
A b s . 5 5 4 n m
W aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,004x + 0,223 R² = 0,935
y = -0,019x - 1,493 R² = 0,929 y = 0,097x + 4,436
R² = 0,92
-3 -2 -1 0 1 2 3 4 5 6
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
Intensitas 6.352,85 lux
y = -0,007x + 0,387 R² = 0,989
y = -0,02x - 0,945 R² = 0,986 y = 0,057x + 2,567
R² = 0,982
-2 -1 0 1 2 3 4
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,008x + 0,507 R² = 0,989
y = -0,018x - 0,676 R² = 0,983 y = 0,040x + 1,960
R² = 0,976
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5 3
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,011x + 0,486 R² = 0,785
y = -0,025x - 0,721 R² = 0,812 y = 0,056x + 2,059
R² = 0,839
-1,5 -1 -0,5 0 0,5 1 1,5 2 2,5 3
0 5 10 15
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
Intensitas 6.352,85 lux
Intensitas 54.203,77 lux
y = -0,012x + 0,456 R² = 0,950
y = -0,030x - 0,781 R² = 0,96 y = 0,077x + 2,171
R² = 0,965
-2 -1 0 1 2 3 4
0 2 4 6 8 10 12
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,005x + 0,218 R² = 0,898
y = -0,025x - 1,519 R² = 0,912 y = 0,13x + 4,565
R² = 0,923
-3 -2 -1 0 1 2 3 4 5 6 7
0 2 4 6 8 10 12
A b s .5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,024x + 0,571 R² = 0,940
y = -0,048x - 0,556 R² = 0,948 y = 0,095x + 1,739
R² = 0,950
-1 -0,5 0 0,5 1 1,5 2 2,5
0 1 2 3 4 5 6
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
y = -0,022x + 0,557 R² = 0,928
y = -0,044x - 0,583 R² = 0,940 y = 0,088x + 1,789
R² = 0,950
-1 0 1 2 3
0 1 2 3 4 5 6
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,028x + 0,561 R² = 0,945
y = -0,044x - 0,583 R² = 0,940 y = 0,115x + 1,767
R² = 0,958
-1 -0,5 0 0,5 1 1,5 2 2,5 3
0 1 2 3 4 5 6
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,026x + 0,567 R² = 0,964
y = -0,053x - 0,562 R² = 0,965 y = 0,108x + 1,746
R² = 0,962
-2 -1 0 1 2 3
0 1 2 3 4 5 6
A b s . 5 5 4 n m
w aktu (jam)
A.554
ln A.554
1/ A.554
y = -0,028x + 0,550 R² = 0,919
y = -0,052x - 0,569 R² = 0,954 y = 0,118x + 1,809
R² = 0,953
-2 -1 0 1 2 3
0 1 2 3 4 5 6
A b s . 5 5 4 n m w aktu(jam) A.554 ln A.554
Lampiran 8. (lanjutan) Intensitas 803,21 lux
Ulangan Waktu (jam)
0 2 4 6 8 10
Intensitas 1.718,72 lux
Ulangan Waktu (jam)
0 2 4 6 8 10
Lampiran 8. (lanjutan) Intensitas 2.465,68 lux
Ulangan Waktu (jam)
0 2 4 6 8 10
Intensitas 6.352,85 lux
Ulangan Waktu (jam)
0 2 4 6 8 10
Lampiran 8. (lanjutan) Intensitas 54.203,77 lux
Ulangan Waktu (jam)
0 1 2 3 4 5
Konstanta Degradasi Warna Sirup Umbi Bit Merah 5%
Ulangan Intensitas Cahaya (lux) Tu u du
803,21 1.718,72 2.465,68 6,352,85 54.203,77
1 0,013 0,016 0,017 0,020 0,048 0,114 0,0228 -0,00024
2 0,010 0,011 0,013 0,018 0,044 0,096 0,0192 -0,00384
3 0,010 0,015 0,017 0,025 0,044 0,111 0,0222 -0,00084
4 0,009 0,018 0,020 0,030 0,053 0,13 0,026 0,00296
5 0,013 0,016 0,019 0,025 0,052 0,125 0,025 0,00196
Tp 0,055 0,076 0,086 0,118 0,241 0,576
p 0,011 0,0152 0,0172 0,0236 0,0482
Dp -0,01204 -0,00784 -0,00584 0,00056 0,02516
SD 0,0019 0,0026 0,0027 0,0047 0,0043
SE 0,0023 0,0032 0,0033 0,0059 0,0053
TP2 0,0030 0,0058 0,0074 0,0139 0,0581
W1= (0,013)(-0,01204) + (0,016)(-0,00784) + (0,017)(-0,00584) + (0,020)(0,00056) + (0,048)(0,02516)
= 0,000838
W2= (0,010)(-0,01204) + (0,011)(-0,00784) + (0,013)(-0,00584) + (0,018)(0,00056) + (0,044)(0,02516)
= 0,000835
W3= (0,010)(-0,01204) + (0,015)(-0,00784) + (0,017)(-0,00584) + (0,025)(0,00056) + (0,044)(0,02516)
= 0,000784
W4 = (0,009)(-0,01204) + (0,018)(-0,00784) + (0,020)(-0,00584) + (0,030)(0,00056) + (0,053)(0,02516)
= 0,000984
W5 = (0,013)(-0,01204) + (0,016)(-0,00784) + (0,019)(-0,00584) + (0,025)(0,00056) + (0,052)(0,02516)
N = ∑ (W.du)
=(W1)(du1) + (W2)(du2) + ...(W5)(du5)
= (0,000838)(-0,00024) + (0,000835)(-0,00384) + (0,000784)(0,00084) + (0,000984)(0,00296) + (0,000929)(0,00196)
= 6,70162 x 10-7
D = du2 x dp2
= [ (-0,00024)2 + (-0,00384)2 +… + (0,00196)2 x (-0,01204)2 + (-0,00784)2 + (-0,00584)2 + (0,00056)2 + (-0,02516)2]
= 0,0000281120 x 0,000873872 = 2,45663x 10 -8
Faktor Koreksi (FK)
5 x 5
) T..
( 2
=
25
(0,576)2
= 0,0132710
Jumlah Kuadrat
Jumlah Kuadrat total (JK total) = p2 – FK =
0,0132710 ]
) 0,052 ( ... ) 017 , 0 ( ) 016 , 0 ( ) 0,013
[( 2 2 2 2
= 0,0046010
Jumlah Kuadrat Ulangan =
Perlakuan Jml
) Tu
( 2
FK
= 0,0132710
5
) 125 , 0 ( ... ) 096 , 0 ( ) 144 , 0
( 2 2 2
Jumlah Kuadrat Perlakuan = Ulangan Jml
) Tp
( 2
FK
= 0,0132710
5
) 0,241 ( ... ) 076 , 0 ( ) 055 , 0
( 2 2 2
= 0,0043694
Jumlah Kuadrat Galad Acak = JK Total – JK Ulangan – JK Perlakuan = 0,0046010 – 0,0001406 – 0,0043694 = 0,0000910
JK Non Additivitas =
D ) (N2
=
8 10 2,45663x
) 7 10 x (6,70162
-2
[image:42.595.98.521.119.593.2]-= 1,82818 x 10 -5
Tabel Sidik Ragam Uji Additivitas
Sumber Ragam Db JK KT FHitung Ftabel
5% 1%
Ulangan 4 0,0001406
Perlakuan 4 0,0043694
Galad acak 16 0,0000910
Non aditivitas 1 0,0000183 0,0000183 3,7690 4,540 8,680
Sisa 15 0,0000728 0,0000049
Tabel Sidik Ragam
Sumber Ragam Db JK KT FHitung
Ftabel
5% 1%
Ulangan 4 0,0001406 0,0000351 6,1757* 3,010 4,770
Perlakuan 4 0,0043694 0,0010923 191,9754** 3,010 4,770
Galad acak 16 0,0000910 0,0000057
Total 24
* Antar ulangan berbeda nyata
** Antar perlakuan berbeda sangat nyata
KV = √
…. 100%
= √ ,
, 100%
= 10,36%
Uji Beda Nyata Jujur (BNJ) 5%
BNJ 5%: W = α(p, )Sx
Sx = , = 1,0677 x 10-3 BNJ 5% = 4,05 x 1,0677 x 10-3
= 4,3 x 10-3
k
803,21 lux 1.718,72 lux 2.465,68 lux 6.352,85 lux 54.203,77 lux
Purata 0,0110 0,0152 0,0172 0,0236 0,0482
SE 0,0023 0,0032 0,0033 0,0059 0,0053