Pembahasan Mtk UN 2013 Paket 01

(1)

Alfa Kristanti

(2)

(3)

(4)

(5)

Alfa Kristanti

(6)

Pada gambar di samping:

ABC PQR maka

AB = PQ, BC = PR, AC = QR

Q P

R 65

o 80o

A B

C 65

o 80o

Q

28

16 8

P R _M

L

K

12 6

21

= 12 16=

3

4 , =

21 28=

3

4 , =

6 8=

3 4

KL = 4 × 27 + 2 × 12 4 + 2

= 108 + 24₆ = 132

6 = 22

L daerah tdk diarsir = LKLMN + LPQRS– 2 × L daerah diarsir = 16 × 12 + 82– 2 × 40

= 192 + 64 – 80 = 176

Banyak lampu = � �

� =

4 × 30

6 = 20

D E

(7)

Alfa Kristanti

7

(6x_{+ 4) + (5}x_{+ 9) = 90} 11x_{+ 13 = 90} 11x_{= 90}–₁₃ 11x_{= 77} x_{= 7}

Penyiku AOC = COB = 5x + 9 = 5(7) + 9 = 35 + 9 = 44

Sudut keliling menghdp busur yg sama maka

ABE = ACE = ADE

ABE = 96₃ = 32

AOE = 2 × ABE

= 2 × 32 = 64

= 676−100 = 576 = 24

luar ₌ 262₋ ₁₃₋₃ 2₌ ₆₇₆₋₁₀2

LORS =



 ×

= 75 105 × 21 = 15

Panjang rusuk balok = 4 (p + l + t) = 4 (30 + 12 + 18) = 4 (60) = 240 cm

Kawat untuk kerangka 2 balok = 2 × 240 = 480 cm

(8)

BC =

4 = 72

4 = 18 t

9 15

t = 152−₉2₌ ₂₂₅−₈₁

t = 144 = 12

Vlimas = 1

3La × t = 1 3 × 18

2

× 12 = 324 × 4 = 1.296

dbola = rusuk kubus dbola = 12, maka : r = 12₂ = 6

Vbola = 4 3π r

3

= 4₃π × 63 = 4₃π × 216 = 4 π × 72 = 288 π

Ldinding = 2 (pt + lt) = 2(6 × 5 + 10 × 5) = 2(30 + 50) = 2(80) = 160

Biaya = 160 × Rp 40.000,- = Rp 6.400.000,-

s2 + s2 = 42 2 s2 = 16 s2 = 8

s = 8 = 4 × 2 = 2 2 4 s

s

Lkubus = 6 s 2

= 6 × 2 2 2 = 6 × 8 = 48

d = 14  r = 7

Ltabung= 2πr (r + t) = 2 × 22

7 × 7 (7 + 34) = 44 (41) = 1.804

Siswa dgn nilai 72 = 40 – 28 = 12 anak

Jml nilai siswa = 28 × 80 + 12 × 72 = 2.240 + 864 = 3.104

Rata-rata nilai = = 3.104

(9)

Alfa Kristanti

9

Data 5 6 7

8

₉

frekuensi 2 3 2 4 1

Modus

32 ₃₀

(10)

n(S) = 2 × 2 × 2 = 8

2 angka 1 gambar = AAG, AGA, GAA

P (2 angka 1 gambar) = 3

8

6

5 5

2 2

4

3 3

Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30 Kelereng merah = 6