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ELA

INTEGRAL REPRESENTATION OF THE DRAZIN INVERSE∗

N. CASTRO GONZ ´ALEZ†, J. J. KOLIHA, AND YIMIN WEI§

Abstract. In this note we present an integral representation for the Drazin inverse AD of a

complex square matrixA. This representation does not require any restriction on its eigenvalues.

Key words. Drazin inverse, Integral representation.

AMS subject classifications. 15A09, 65F20

1. Introduction. It is a well-known fact that if the eigenvalues ofA∈Cn×n lie

in the open right halfplane, then the inverse ofAcan be represented by

A−1=

0

exp(−tA)dt.

This representation was extended to the Drazin inverse by Koliha and Straˇskraba [2, Theorem 6.3] in the form

AD=

0

exp(−tA)(I−Aπ)dt

for those singular matrices whose nonzero eigenvalues lie in the open right halfplane and for which ind(A) = 1; hereAπ is the eigenprojection of A corresponding to the

eigenvalue 0. Recall that ind(A), the index ofA, is the least nonnegativekfor which the nullspace ofAk coincides with the nullspace ofAk+1.

Recently, Castro, Koliha and Wei [1, Corollary 2.5] obtained a simple integral representation of the Drazin inverseAD for matrices ACn×n (and more generally

elements of a Banach algebra) for which the nonzero eigenvalues ofAm+1 lie in the open right halfplane for somem≥ind(A):

AD=

0

exp(−tAm+1)Amdt.

It is natural to ask whether we can drop the restriction on the spectrum ofAm+1. In this note we will establish an integral representation for the Drazin inverse AD which holds without any restriction on the eigenvalues ofA.

Received by the Editors on 5 September 2001. Final manuscript accepted for publication on 11

July 2002. Handling Editor: Daniel Hershkowitz.

Facultad de Inform´atica, Universidad Polit´ecnica de Madrid, Campus de Montegancedo, Boadilla

del Monte, 28660 Madrid, Spain ([email protected]).

Department of Mathematics and Statistics, University of Melbourne, VIC 3010, Australia

([email protected]).

§Department of Mathematics and Laboratory of Mathematics for Nonlinear Sciences, Fudan

University, Shanghai 200433, People’s Republic of China ([email protected]). Supported by the National Natural Science Foundation of China (under grant 19901006) and the Doctoral Point Foundation of China. Partial work was done when this author visited Harvard University, supported by the ChinaScholarship Council.

129

The Electronic Journal of Linear Algebra ISSN 1081-3810 A publication of the International Linear Algebra Society Volume 9, pp. 129-131, August 2002

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ELA

130 N. Ca stro, J. J. Koliha , a nd Yimin Wei

2. Integral representation for the Drazin inverse AD. We mention that for the Moore–Penrose inverseA† of a matrixA Cn×n (and more generally of a

bounded Hilbert space operator Awith closed range) there is a well known integral representation due to Showalter [3],

A† =

0

exp(−tA∗A)A∗dt,

generalized recently by Wei and Wu to the weighted Moore–Penrose inverse [4]. Our main result which follows bears a certain resemblance to this representation.

Theorem 2.1. Suppose that ACn×n andk= ind(A). Then

Proof. For each matrixA∈Cn×n there exists a nonsingular matrixP such that

A=P

whereC is a nonsingular matrix andN is a nilpotent matrix of indexk; either block C or blockN may be empty.

The Drazin inverse ofAcan be then expressed by

AD=P patible with the above partitioning ofA(andAD):

P∗P = tricesP11 andQ11. By a direct computation we obtain

Ak(A2k+1)∗Ak =P

The Electronic Journal of Linear Algebra ISSN 1081-3810 A publication of the International Linear Algebra Society Volume 9, pp. 129-131, August 2002

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ELA

Representation of the Drazin Inverse 131

Writeσ(A) for the spectrum ofA(that is, the set of all eigenvalues ofA). Then

σ[CkQ11(C2k+1)∗P11Ck+1] =

σ[Q11(C2k+1)∗P11C2k+1]

=σ[Q111/2(C

2k+1)P1/2 11 P

1/2 11 C

2k+1 Q111/2]

=σ[(P111/2C 2k+1

Q111/2)∗(P 1/2 11 C

2k+1 Q111/2)],

where the last spectrum is positive being the spectrum of a positive definite Hermitian matrix. Thus

0

exp[−tAk(A2k+1)∗Ak+1]Ak(A2k+1)∗Akdt

=P

0 exp[−tC

kQ11(C2k+1)P11Ck+1] dt 0

0 0

CkQ11(C2k+1)∗P11Ck 0

0 0

P−1

=P

[CkQ11(C2k+1)∗P11Ck+1]−1 0

0 0

CkQ11(C2k+1)∗P11Ck 0

0 0

P−1

=P

C−1 0

0 0

P−1

=AD.

This completes the proof.

REFERENCES

[1] N. Castro Gonz´alez, J. J. Koliha, and Yimin Wei. On integral representations of the Drazin inverse in Banach algebras. Proceedings of the Edinburgh Mathematical Society, 45:327– 331, 2002.

[2] J. J. Koliha and Ivan Straˇskraba. Power bounded and exponentially bounded matrices. Appli-cations of Mathematics, 44:289–308, 1999.

[3] D. Showalter. Representation and computation of the pseudoinverse. Proceedings of the Amer-ican Mathematical Society, 18:584–586, 1967.

[4] Yimin Wei and Hebing Wu. The representation and approximation for the weighted Moore-Penrose inverse. Applied Mathematics and Computation, 121:17–28, 2001.

The Electronic Journal of Linear Algebra ISSN 1081-3810 A publication of the International Linear Algebra Society Volume 9, pp. 129-131, August 2002

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