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A CLASS OF HOLOMORPHIC FUNCTIONS DEFINED BY INTEGRAL OPERATOR

Camelia M˘ad˘alina B˘al˘aet¸i

Abstract. By using the integral operator Imf(z), z U (Definition 4), we introduce a class of holomorphic functions, denoted by Im(α), and we obtain inclusion relations related to this class and some differential subordina-tions.

Keywords: differential subordination, dominant, integral operator.

2000 Mathematics Subject Classification: 30C45.

1. Introduction and preliminaries Denote by U the unit disc of the complex plane:

U ={z ∈C: |z|<1}.

Let H[U] be the space of holomorphic functions inU. We let:

An ={f ∈ H[U], f(z) =z+an+1zn +1

+. . . , z ∈U} with A1 =A.

We let H[a, n] denote the class of analytic functions inU of the form f(z) =a+anzn

+an+1zn +1

+. . . , z ∈U. Let

K =

f ∈A: Re zf ′′

(z)

(2)

If f and g are analytic functions in U, then we say that f is subordinate tog, written f ≺g, or f(z)≺g(z), if there is a function wanalytic in U with w(0) = 0, |w(z)|<1, for all z ∈U such thatf(z) =g[w(z)] for z ∈U. Ifg is univalent, then f ≺g if f(0) =g(0) and f(U)⊂g(U).

Definition 1 [1] Let ψ : C3

×U → C and let h be univalent in U. If p is

analytic in U and satisfies the (second-order) differential subordinations

ψ p(z), zp′

(z), z2

p′′

(z) ;z

≺h(z), (1)

then pis called a solution of the differential subordination.The univalent

func-tion q is called a dominant of the solutions of the differential subordination,

if p ≺ q for all p satisfying (1). A dominant ∼q that satisfies ∼q ≺ p for all

dominants q of (1) is said to be the best dominant of (1).

Note that the best dominant is unique up to a rotation of U. We use the following subordination results:

Lemma 2 (Hallenbeck and Ruscheweyh [1]) Let h be a convex function with

h(0) ≡a and let γ ∈C∗

be a complex number withRe γ ≥0. If p∈ H[U]with

p(0) =a and

p(z) + 1 γzp

(z)≺h(z)

then

p(z)≺g(z)≺h(z)

where

g(z) = γ nznγ

−1

Z z

0

h(t)tγn

−1

dt.

The function g is convex and is the best dominant.

Lemma 3 (Miller and Mocanu [2]) Let g be a convex function inU and let h(z) = g(z) +nαzg′

(z)

where α >0 and n is a positive integer.

If p(z) = g(0) +pnzn+. . . is holomorphic in U and p(z) +αzp′

(z)≺h(z),

then

p(z)≺g(z)

(3)

Definition 4 [5] For f A and mN we define the operator Imf by I0f(z) = f(z)

I1

f(z) = If(z) = Z z

0

f(t)t−1

dt

Imf(z) =I Im−1f(z)

, z ∈U.

Remark 5 If f ∈ H(U) then Imf(z) =P∞ j=1j

−majzj.

Remark 6 For m= 1, Imf is the Alexander operator. 2.Main results

Definition 7 If0α <1andmN, letIm(α)denote the class of functions

f ∈A which satisfy the inequality:

Re [Im f(z)]′

> α.

Remark 8 For m= 0, we obtain

Ref′

(z)> α, z ∈U. Theorem 9 If 0α <1 and mN, then we have

Im(α)⊂ Im+1

(δ), (2)

where

δ=δ(α) = 2α−1 + 2(1−α) ln 2. (3)

The result is sharp.

Proof. Assume that f ∈ Im(α). Then we have Im

f(z) =z[Im+1

f(z)]′

, z∈U. (4)

and differentiating this equality we obtain [Im

f(z)]′ =

Im+1f(z)′

+zIm+1f(z)′′

(4)

If p(z) = [Im+1

f(z)]′

, then (5) becomes [Imf

(z)]′

=p(z) +zp′

(z), z∈U. Since f ∈ Im(α), from definition 7 we have

Re [p(z) +zp′

(z)]> α, which is equivalent to

p(z) +zp′

(z)≺ 1 + (2α−1)z

1 +z ≡h(z). Therefore, from lemma 2 results that

p(z)≺g(z)≺h(z), z ∈U

where

g(z) = 1 z

Z z

0

1 + (2α−1)t 1 +t dt = 2α−1 + 2(1−α)ln (1 +z)

z , z∈U. Moreover, the function g is convex and is the best dominant.

From p(z)≺q(z), z∈U, results that

Re p(z)>Reg(1) =δ(α) = 2α−1 + 2(1−α) ln 2, hence we can prove that Im(α)⊂ Im+1

(δ).

Theorem 10 Let g be a convex function, g(0) = 1 and let h be a function

such that

h(z) = g(z) +zg′

(z), z∈U.

If f ∈A verifies the differential subordination

[Im f(z)]′

≺h(z), z∈U (6)

then

[Im+1

f(z)]′

≺g(z), z ∈U

(5)

Proof. By using the properties of the operator Imf and differentiating we obtain

[Imf(z)]′ =

Im+1

f(z)′ +z

Im+1

f(z)′′

, z ∈U.

If we let

p(z) = [Im+1

f(z)]′ ,

then we obtain

[Imf(z)]

=p(z) +zp′ (z) and (6) becomes

p(z) +zp′

(z)≺g(z) +zg′

(z)≡h(z). By using lemma 3, we have

p(z)≺g(z),

i.e.

Im+1f(z)′

≺g(z), z∈U and this result is sharp.

Theorem 11 Let g be a convex function, g(0) = 1, and h(z) = g(z) +zg′

(z), z∈U.

If f ∈A and verifies the differential subordination

[Im f(z)]′

≺h(z), z ∈U, (7)

then

Imf(z)

z ≺g(z), z ∈U

where

g(z) = 1 z

Z z

0

h(t)dt, z ∈U

(6)

Proof. If

p(z) = I mf(z)

z , z ∈U (8)

then results that

Imf(z) =zp(z). (9)

Differentiating (9), we obtain [Im

f(z)]′

=p(z) +zp′

(z), z ∈U, hence (7) becomes

p(z) +zp′

(z)≺h(z)≡g(z) +zg′ (z). Therefore, from lemma 2 results that

p(z)≺g(z), z ∈U

i.e.

Imf(z)

z ≺g(z), z∈U.

Theorem 12 Let h ∈ H[U], with h(0) = 1, h

(0) 6= 0, which verifies the

inequality

Re

1 + zh ′′

(z) h′

(z)

>−1

2, z ∈U.

If f ∈A and verifies the differential subordination

[Im f(z)]′

≺h(z), z ∈U, (10)

then

[Im+1

f(z)]′

≺g(z)

where

g(z) = 1 z

Z z

0

h(t)dt, z∈U.

(7)

Proof. A simple application of the differential subordinations technique [1, Corollary 2.6g.2, p. 66] shows that the functiong is convex. From

Im

f(z) = z[Im+1

f(z)]′

, z ∈U

we obtain

[Im f(z)]′

=

Im+1f(z)′

+zIm+1f(z)′′ .

If we assume

p(z) = [Im+1

f(z)]′ then

[Im f(z)]′

=p(z) +zp′

(z), z∈U, hence (10) becomes

p(z) +zp′

(z)≺h(z). Moreover, from lemma 2 results that

p(z)≺g(z) = 1 z

Z z

0

h(t)dt.

Theorem 13 Let h∈ H(U), h(0) = 1, h

(0) 6= 0, which satisfy the inequality

Re

1 + zh ′′

(z) h′(z)

>−1

2, z ∈U.

If f ∈A and verifies the differential subordination

[Im f(z)]′

≺h(z), z ∈U, (11)

then

Imf(z)

z ≺g(z), z ∈U, z 6= 0,

where

g(z) = 1 z

Z z

0

h(t)tdt, z ∈U.

(8)

Proof. A simple application of the differential subordinations technique [1, Corollary 2.6g.2, p. 66] shows that the functiong is convex.

If

p(z) = I mf(z)

z , z∈U, z 6= 0. (12) then differentiating relation (12) we obtain

[Im f(z)]′

=p(z) +zp′ (z), so (11) becomes

p(z) +zp′

(z)≺h(z), z ∈U. Therefore, from lemma 2 results that p(z)≺g(z) where

g(z) = 1 z

Z z

0

h(t)dt, z ∈U,

and g is convex and is the best dominant.

Similar results for differential operator were obtained by G. I. Oros in [4]. References

[1] S. S. Miller , P. T. Mocanu, Differential Subordinations. Theory and Applications, Marcel Dekker Inc., New York, Basel, 2000.

[2] S. S. Miller , P. T. Mocanu, On some classes of first-order differential

subordinations, Michigan Math. J., 32(1985), 185-195.

[3] P. T. Mocanu, T. B. Bulboac˘a, G. S¸t. S˘al˘agean, Teoria geometric˘a a funct¸iilor univalente, Casa C˘art¸ii de S¸tiint¸˘a, Cluj, 1999.

[4] G. I. Oros, A class of holomorphic functions defined using a differential

operator, General Mathematics, 13, 4(2005), 13-18.

[5] G. S¸t. S˘al˘agean, Subclasses of univalent functions, Lecture Notes in Math. (Springer Verlag) 1013(1983), 362-372.

Author:

Camelia M˘ad˘alina B˘al˘aet¸i

Department of Mathematics and Computer Science University of Petro¸sani

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