1. C
8− 1 3= 1
8 1 3
=31
√
8= 1 22. C
7 8 6=7
6 6+
2 6=7
6 6×7
2
6=71×7 1
3=7×3
√
7=73√
73. B 1
1+xp−q+ 1
1+xq−p= 1
1+x p xq
+1
1+x q xp
=1 xq xq+
xp xq
+1 xp xp+
xq xp
=1 xq+xp xq
+1 xq+xp xp =x
q xq+xp+
xp
xq+xp=
xq+xp xq+xp=1
4. A
(
x
+
y
)
3a+1(
x
+
y
)
2a+5=(
x
+
y
)
3a+1−(2a+5)
=
(
x
+
y
)
3a+1−2a−5=(
x
+
y
)
a−45. B
(
a2bc2
)
3×b
4
ac3=
(
a2×3b3
c2×3
)
×b4
ac3=
a6
a ×
b3×b4
1 ×
1
c6×c3
=a6−1×b3+4×1
c6+3=
a5b7
c9
6. B
(
3
x+
3
−x)
2=(
6
)
2(
3
x)
2+
2
(
3
x)(
3
−x)
+
(
3
−x)
2=
36
(
a
1 2
−
a
−1 2
)
2
(
a
1 2
+
a
−1 2
)
2
=
[
(
a
1 2
−
a
−1 2
)(
a
1 2
+
a
−1
2
)
]
=
[
(
a
1 2)
2
−
(
a
−1 2
)
2
]
=
(
a
1−
a
−1)
2=
(
a
−
1
a
)
2
=
(
a
)
2−
2
(
a
)
(
1
a
)
+
(
1
a
)
2
=
a
2−
2
+
1
a
2=
a
4−
2
a
2+
1
a
2=
1
a
2(
a
2
−
1
)
211. B
p
2−
2
=
(
1
+
√
3
)
2−
2
=
[
(
1
2)
+
2
(
1
)
(
√
3
)
+
(
√
3
)
2]
−
2
=
(
1
+
2
√
3
+
3
)
−
2
=
4
+
2
√
3
−
2
=
2
+
2
√
3
=
2
(
1
+
√
3
)
=
2
p
12. B
f
(
x
)
f
(
y
)=
f
(
x
+
y
)
a
x⋅
a
y=
a
x+ya
x+y=
a
x+y13. A
(
−
z
5u
5)
3=
(
−
z
5u
5)
×
(
−
z
5u
5)
×
(
−
z
5u
5)
=−
z
15u
1514. C
(
x
2y
3)
6
:
(
y
6x
−4)
−3
=
(
x
12
y
18)
:
(
y
−18x
12)
=
(
x
12y
18)
×
(
x
12y
−18)
=
x
12+12y
18−18=
x
24y
0=
x
24
15. E
√
0, 0036 0,3 =√
36 10000
3 10
=
6 100
3 10
= 6
100× 10
5
−
6
⋅
5
+
1
=
0
5
2x⋅
5
1−
6
⋅
5
x+
1
=
0
5
⋅
(
5
x)
2−
6
⋅
5
x+
1
=
0
Misalkan
5
x=
a
5
a
2−
6
a
+
1
=
0
(
5
a
−
1
)(
a
−
1
)=
0
5
a
−
1
=
0
∨
a
−
1
=
0
5
a
=
1
a
=
1
a
=
1
5
5
x
=
1
5
x=
1
5
x
=
0
x
=−
1
20. A
9
3x−
2
⋅
3
3x+1−
27
=
0
(
3
2)
3x−
2
⋅
3
3x⋅
3
1−
27
=
0
(
3
3x)
2−
6
⋅
3
3x−
27
=
0
Misalkan
3
3x=
a
a
2−
6
a
−
27
=
0
(
a
−
9
) (
a
+
3
)
=
0
a
−
9
=
0
∨
a
+
3
=
0
a
=
9
a
=−
3
3
3x=
3
23
3x=−
3
3
x
=
2
x
=
tidak ada
x
=
2
3
21. E
(
2− 6 5)
3 =2−
18 5= 1
2 18
5 = 1
23 3 5
= 1 23×2
3 5
=1 8×
1 5
23. A
√
10
−
√
5
√
5
=
√
10
√
5
−
√
5
√
5
=
√
10
5
−
1
=
√
2
−
1
=−
1
+
√
2
24. D
5
3
√
2
−
√
3
=
5
3
√
2
−
√
3
×
3
√
2
+
√
3
3
√
2
+
√
3
=
5
(
3
√
2
+
√
3
)
(
3
√
2
)
2−
(
√
3
)
2=
15
√
2
+
5
√
3
18
−
3
=
15
√
2
+
5
√
3
15
=
15
√
2
15
+
5
√
3
15
=
√
2
+
√
3
3
=
√
2
+
1
3
√
3
25. A
√
18
+
√
50
−
√
72
=
√
9
⋅
2
+
√
25
⋅
2
−
√
36
⋅
2
=
3
√
2
+
5
√
2
−
6
√
2
=
2
√
2
26. A
√
31
+
√
936
−
√
21
−
√
416
=
√
31
+
√
4
×
234
−
√
21
−
√
4
×
104
=
√
31
+
2
√
234
−
√
21
−
2
√
104
=
√
(
18
+
13
)
+
2
√
(
18
×
13
)
−
√
(
13
+
8
)
−
2
√
(
13
×
8
)
=
(
√
18
+
√
13
)
−
(
√
13
−
√
8
)
=
√
18
+
√
8
=
√
9
×
2
+
√
4
×
2
=
3
√
2
+
2
√
2
=
5
√
2
27. B
√
2
−
√
3
√
2
+
√
3
=
√
2
−
√
3
√
2
+
√
3
×
√
2
−
√
3
√
2
−
√
3
=
(
√
2
)
2−
2
(
√
2
) (
√
3
)
+
(
√
3
)
2(
√
2
)
2−
(
√
3
)
2=
2
−
2
√
6
+
3
2
−
3
=
5
−
2
√
6
−
1
=−
5
+
2
√
6
a
=−
5
b
=
2
a
+
b
=−
5
+
2
=−
3
28. A
m
√
n√
a
p=
(
√
na
p)
1
m
=
(
(
a
p)
1
n
)
1
m
=
a
(
m
−
7
√
2
)(
m
+
7
√
2
)
=
m
2−
(
7
√
2
)
2=
m
2−
98
=
(
√
18
+
√
80
)
2−
98
=
(
√
9
⋅
2
+
√
16
⋅
5
)
2−
98
=
(
3
√
2
+
4
√
5
)
2−
98
=
(
3
√
2
)
2+
2
(
3
√
2
)(
4
√
5
)
+
(
4
√
5
)
2−
98
=
18
+
24
√
10
+
80
−
98
=
24
√
10
30. C
2
√
8
+
√
18
+
1
4
√
32
+
√
200
=
2
√
4
⋅
2
+
√
9
⋅
2
+
1
4
√
16
⋅
2
+
√
100
⋅
2
=
4
√
2
+
3
√
2
+
√
2
+
10
√
2
=
18
√
2
31. C
3
√
49
⋅
3√
49
⋅
√
349
⋅
3√⋯=
a
⇔
49
⋅
3
√
49
⋅
√
349
⋅
3√⋯=
a
3⇔
49
⋅
a
=
a
3⇔
49
=
a
2⇔
7
=
a
32. D
3
√
24
−
2
√
18
−
√
2
=
3
√
24
−
√
2
−
2
√
18
−
√
2
=−
3
√
24
2
+
2
√
18
2
=−
3
√
12
+
2
√
9
=−
3
√
4
⋅
3
+
2
⋅
3
=−
6
√
3
+
6
33. D
(
5
+
√
2
)
x
=
√
(
5
+
√
2
)
2+
(
5
−
√
2
)
2=
√
(
25
+
10
√
2
+
2
)
+
(
25
−
10
√
2
+
2
)
=
√
25
+
25
+
10
√
2
−
10
√
2
+
2
+
2
=
√
54
=
√
9
×
6
=
3
√
6
(
5
−
√
2
)
Keliling =
(
5
+
√
2
)
+
(
5
−
√
2
)
+
3
√
6
=
10
+
3
√
6
cm 34. EL=4πr2
L
=
4
⋅
π
⋅
(
2
√
2
+
√
6
)
235. B
f (x+3)
f (x−1)=
2x+3 2x−1=
2x⋅23 2x 21
=2x⋅23×2
1
2x=2
3⋅21=24=f(4)
36. D
(
3
3
x−2)
2
=
3√
1
9
(
3
23
2(x−2))
=
(
1
9
)
1 3
3
23
2x−4=
(
3
−2
)
1 33
2−2x+4=
3
−2 3
6
−
2
x
=−
2
3
18
−
6
x
=−
2
−
6
x
=−
20
x
=
20
6
=
10
3
37. B
3
x+3=
√
527
x−53
x+3=
(
27
x−5)
1 53
x+3=
3
3(x−5)× 1 53
x+3=
3
3 5(x−5)x
+
3
=
3
5
(
x
−
5
)
5
x
+
15
=
3
x
−
15
5
x
−
3
x
=−
15
−
15
2
x
=−
30
(
0,25)
x+4=√
82x−5(
1 4)
x+4
=
(
82x−5)
1 2
(
4−1)
x+4=(
23(2x−5))
1 2
2−2(x+4)=
(
26x−15)
1 22−2x−8=23x−
15 2
−2x−8=3x−15
2
−4x−16=6x−15
−4x−6x=−15+16
−10x=1
x=−1
10=−0,1
39. A
√
108
−
2
3
−
√
27
=
√
36
×
3
−
(
2
3
−
√
27
×
3
+
√
27
3
+
√
27
)
=
6
√
3
−
(
6
+
2
√
27
9
−
27
)
=
6
√
3
−
(
6
+
2
√
27
−
18
)
=
6
√
3
−
(
6
−
18
+
2
√
27
−
18
)
=
6
√
3
+
1
3
+
1
9
√
9
⋅
3
=
6
√
3
+
1
3
+
1
9
√
9
⋅
3
=
6
√
3
+
1
3
+
1
3
√
3
=
19
√
3
+
1
3
40. C
(
3p−2q3)
−2(
32p−1q2)
−3=(
32p−1q2)
3(
3p−2q3)
2=32×3p−1×3q2×3 31×2p−2×2q3×2=
36p−3q6 32p−4q6=3
