ax + by + c = 0
20p + 30q = 20(4000)+30(1000) = 80.000 + 30.000
Pada gambar di samping:
M o A
Jumlah bilangan terbesar dan terkecil = 2
3 × jml ketiga bilangan
= 2
Sudut keliling menghdp busur yg sama maka ABE = ACE = ADE ABE = 96
3 = 32
AOE = 2 × ABE = 2 × 32 = 64
= 676−100 = 576 = 24 luar = 262− 12−2 2 = 676− 102
LOBC =
×
= 120 50 × 30
= 72
Panjang rusuk 1 balok = 4 (p + l + t) = 4 (40 + 24 + 36) = 4 (100) = 400 cm = 4 m Kawat tersedia = 10 m
Banyak kerangka balok yg dibuat = 10
4 = 2,5 2
Garis pelukis
BC =
4 =
72 4 = 18
t
9 15 t = 152− 92= 225−81
dbola = rusuk kubus dbola = 30, maka : r = 30
2 = 15
Vbola = 4 3π r
3 = 4
3π × 15 3
= 4
3π × 3.375 = 4 π × 1.125 = 4.500 π
Ldinding = 2 (pt + lt) = 2(8 × 5 + 6 × 5) = 2(40 + 30) = 2(70) = 140
Biaya = 140 × Rp 50.000,- = Rp 7.000.000,-
s2 + s2 = 8 2 2 2 s2 = 64 × 2 2 s2 = 128
s2 = 64 s = 64 = 8 8 2 s
s
Lkubus = 6 s2 = 6 × 8 2 = 6 × 64 = 384
d = 28 r = 14
Ltabung= 2πr (r + t) = 2 × 22
7 × 14 (14 + 26) = 88 (40) = 3.520
Jumlah siswa = 18 + 22 = 40 anak
Jml tinggi = 18 × 156 + 22 × 152 = 2.808 + 3.344 = 6.152
Rata-rata tinggi = �� = 6.152
40 = 153,8
Data 5 6
7 8
9 frekuensi 2 3 4 3 232 30
n(S) = 2 × 2 × 2 = 8 3 gambar = GGG
P (3 gambar) = 1 8
6
5 5
2 2
4
3 3
Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30 Kelereng merah = 6
P ( 1 merah) = 6
