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Statistics for Managers

Using Microsoft® Excel

5th Edition

Chapter 5

(2)

Learning Objectives

In this chapter, you will learn:

The properties of a probability distribution

To compute the expected value and variance of a

probability distribution

To calculate the covariance and understand its use in

finance

To compute probabilities from the binomial, Poisson,

and hypergeometric distributions

How to use these distributions to solve business

(3)

Definitions

Random Variables

A

random variable

represents a possible

numerical value from an uncertain event.

Discrete

random variables produce outcomes

that come from a counting process (i.e.

number of classes you are taking).

Continuous

random variables produce

(4)

Discrete Random Variables

Examples

Discrete random variables can only assume a countable number of

values

Examples:

Roll a die twice

Let X be the number of times 4 comes up (then X could be 0,

1, or 2 times)

Toss a coin 5 times.

(5)

Definitions

Random Variables

Random

Variables

Discrete

Random Variable

Continuous

Random Variable

(6)

Definitions

Probability Distribution

A

probability distribution for a discrete random

variable

is a mutually exclusive listing of all possible

numerical outcomes for that variable and a particular

probability of occurrence associated with each outcome.

Number of Classes Taken

Probability

2

0.2

3

0.4

4

0.24

(7)

Definitions

Probability Distribution

Experiment: Toss 2 Coins. Let X = # heads.

Probability Distribution

X Value Probability

0 1/4 = .25

1 2/4 = .50

2 1/4 = .25

0 1 2 X

.50

.25

P

ro

b

ab

ili

ty

(8)

Discrete Random Variables

Expected Value

Expected Value (or mean) of a discrete distribution

(Weighted Average)

Example: Toss 2 coins, X = # of heads,

Compute expected value of X:

E(X) = (0)(.25) + (1)(.50) + (2)(.25)

= 1.0

N

i

i

i

P

X

X

1

)

(

E(X)

(9)

Discrete Random Variables

Expected Value

Compute the expected

value for the given

distribution:

Number of

Classes Taken

Probability

2

0.2

3

0.4

4

0.24

5

0.16

E(X) = 2(.2) + 3(.4) + 4(.24) + 5(.16) = 3.36

(10)

Discrete Random Variables

Dispersion

Variance of a discrete random variable

Standard Deviation of a discrete random variable

where:

(11)

Discrete Random Variables

Dispersion

Example: Toss 2 coins, X = # heads, compute

standard deviation (recall that E(X) = 1)

(12)

Covariance

The covariance measures the strength of the

linear relationship between two numerical

random variables X and Y.

A positive covariance indicates a positive

relationship.

A negative covariance indicates a negative

(13)

Covariance

Covariance formula:

)

(

)]

(

)][(

(

[

σ

1

N

i

i

i

i

i

XY

X

E

X

Y

E

Y

P

X

Y

where: X = discrete variable X

X

i

= the i

th

outcome of X

Y = discrete variable Y

Y

i

= the i

th

outcome of Y

(14)

Investment Returns

The Mean

Consider the return per $1000 for two types of

investments.

Economic

P(X

i

Y

i

) Condition

Investment

Passive Fund X Aggressive Fund Y

0.2 Recession

- $25

- $200

0.5 Stable Economy

+ $50

+ $60

(15)

Investment Returns

The Mean

E(X) = μ

X

= (-25)(.2) +(50)(.5) + (100)(.3) = 50

E(Y) = μ

Y

= (-200)(.2) +(60)(.5) + (350)(.3) = 95

(16)

Investment Returns

Standard Deviation

43.30

Interpretation: Even though fund Y has a higher

(17)

Investment Returns

Covariance

8250

95)(.3)

50)(350

(100

95)(.5)

50)(60

(50

95)(.2)

200

-50)(

(-25

σ

XY

Interpretation: Since the covariance is large and

(18)

The Sum of Two Random

Variables: Measures

Expected Value:

Variance:

Standard deviation:

XY

Y

X

Y

X

Y

X

)

σ

σ

σ

Var(

2

2

2

)

(

)

(

)

(

X

Y

E

X

E

Y

E

2

σ

(19)

Portfolio Expected Return and

Expected Risk

Investment portfolios usually contain several

different funds (random variables)

The expected return and standard deviation

of two funds together can now be calculated.

Investment Objective: Maximize return

(20)

Portfolio Expected Return and

Expected Risk

Portfolio expected return (weighted average return):

Portfolio risk (weighted variability)

where w = portion of portfolio value in asset X

(1 - w) = portion of portfolio value in asset Y

)

(

)

1

(

)

(

E(P)

w

E

X

w

E

Y

XY

2

Y

2

2

X

2

P

w

σ

(

1

w

)

σ

2w(1

-

w)σ

(21)

Portfolio Expect Return and

Expected Risk

Recall: Investment X: E(X) = 50

σ

X

= 43.30

Investment Y: E(Y) = 95

σ

Y

= 193.21

σ

XY

= 8250

Suppose 40% of the portfolio is in Investment X and 60% is in Investment Y:

The portfolio return is between the values for investments X and Y

considered individually.

(22)

Probability Distribution

Overview

Continuous

Probability

Distributions

Binomial

Hypergeometric

Poisson

Probability

Distributions

Discrete

Probability

Distributions

Normal

Uniform

Exponential

(23)

The Binomial Distribution:

Properties

A fixed number of observations, n

ex. 15 tosses of a coin; ten light bulbs taken from a

warehouse

Two mutually exclusive and collectively exhaustive

categories

ex. head or tail in each toss of a coin; defective or not

defective light bulb; having a boy or girl

Generally called “success” and “failure”

Probability of success is p, probability of failure is 1 – p

Constant probability for each observation

ex. Probability of getting a tail is the same each time we

(24)

The Binomial Distribution:

Properties

Observations are independent

The outcome of one observation does not affect the

outcome of the other

Two sampling methods

(25)

Applications of the

Binomial Distribution

A manufacturing plant labels items as either

defective or acceptable

A firm bidding for contracts will either get a contract

or not

A marketing research firm receives survey responses

of “yes I will buy” or “no I will not”

New job applicants either accept the offer or reject it

Your team either wins or loses the football game at

(26)

The Binomial Distribution

Counting Techniques

Suppose success is defined as flipping heads

at least two times out of three with a fair

coin. How many ways is success possible?

Possible Successes: HHT, HTH, THH, HHH,

So, there are four possible ways.

This situation is extremely simple. We need

(27)

Counting Techniques

Rule of Combinations

The number of combinations of selecting X

objects out of n objects is:

X)!

(n

X!

n!

X

n

C

X

n

where:

(28)

Counting Techniques

Rule of Combinations

How many possible 3 scoop combinations could you

create at an ice cream parlor if you have 31 flavors

to select from?

(29)

The Binomial Distribution

Formula

X

n

X

(1

)

X)!

(n

X!

n!

P(X)

p

p

P(X) = probability of

X

successes in

n

trials,

with probability of success

p

on each trial

X = number of ‘successes’ in sample,

(X = 0, 1, 2, ..., n)

n = sample size (number of trials

or observations)

p = probability of “success”

Example: Flip a coin four

times, let x = # heads:

n = 4

p = 0.5

1 - p = (1 - .5) = .5

(30)

The Binomial Distribution

What is the probability of one success in five

observations if the probability of success is .1?

(31)

The Binomial Distribution

Example

Suppose the probability of purchasing a defective

computer is 0.02. What is the probability of

purchasing 2 defective computers is a lot of 10?

(32)

The Binomial Distribution

Shape

n = 5 p = 0.1

0

.2

.4

.6

0

1

2

3

4

5

X

P(X)

n = 5 p = 0.5

.2

.4

.6

P(X)

0

The shape of the binomial

distribution depends on the

values of p and n

Here, n = 5 and p = .1

(33)

The Binomial Distribution

Using Binomial Tables

(34)

The Binomial Distribution

Characteristics

Mean

Variance and Standard Deviation

p

n

E(x)

μ

)

-(1

n

σ

2

p

p

σ

n

p

(1

-

p

)

(35)
(36)

The Poisson Distribution

Definitions

An

area of opportunity

is a continuous unit

or interval of time, volume, or such area in

which more than one occurrence of an event

can occur.

(37)

The Poisson Distribution

Properties

Apply the Poisson Distribution when:

You wish to count the number of times an event occurs in a

given area of opportunity

The probability that an event occurs in one area of opportunity is

the same for all areas of opportunity

The number of events that occur in one area of opportunity is

independent of the number of events that occur in the other areas

of opportunity

The probability that two or more events occur in an area of

opportunity approaches zero as the area of opportunity becomes

smaller

(38)

The Poisson Distribution

Formula

X!

λ

e

P(X)

x

λ

where:

X = the probability of X events in an area of opportunity

= expected number of events

(39)

The Poisson Distribution

Example

Suppose that, on average, 5 cars enter a parking

lot per minute. What is the probability that in a

given minute, 7 cars will enter?

So, X = 7 and λ = 5

0.104

7!

5

e

X!

λ

e

P(7)

7

5

x

λ

(40)

The Poisson Distribution

Using Poisson Tables

X

0.10

0.20

0.30

0.40

0.50

0.60

0.70

0.80

0.90

(41)
(42)

The Poisson Distribution

Shape

0.00 0.05 0.10 0.15 0.20 0.25

1 2 3 4 5 6 7 8 9 10 11 12

x

P

(x

)

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

0 1 2 3 4 5 6 7

P

(x

)

= 0.50

= 3.00

The shape of the Poisson Distribution depends

(43)

The Hypergeometric

Distribution

The

binomial distribution

is applicable

when selecting from a finite population with

replacement or from an infinite population

without replacement.

The

hypergeometric distribution

is

(44)

The Hypergeometric

Distribution

“n” trials in a sample taken from a finite

population of size N

Sample taken without replacement

Outcomes of trials are dependent

Concerned with finding the probability of “X”

(45)

The Hypergeometric

Distribution

Where

N = population size

A = number of successes in the population

N – A = number of failures in the population

n = sample size

(46)

The Hypergeometric Distribution

Characteristics

The mean of the hypergeometric distribution is:

N

nA

E(x)

μ

The standard deviation is:

1

-N

n

-N

N

A)

-nA(N

σ

2

1

-N

n

-N

(47)

The Hypergeometric Distribution

Example

Different computers are checked from 10 in the

department. 4 of the 10 computers have illegal

software loaded. What is the probability that 2 of the

3 selected computers have illegal software loaded?

So, N = 10, n = 3, A = 4, X = 2

The probability that 2 of the 3 selected computers

(48)

Chapter Summary

In this chapter, we have

Addressed the probability of a discrete random

variable

Defined covariance and discussed its application

in finance

Discussed the Binomial distribution

Reviewed the Poisson distribution

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