LAPORAN TUGAS BESAR STRUKTUR BAJA II

(1)

(2)

A. Perhitungan Sudut

tanα =

α = 36,23˚

B. Perhitungan Panjang

X2 = H2 +L2

X2 = 18,52+ 25,52

X = 18,52+ 25,52

X2 = 31,3 meter

C. Pembebanan pada Gording

I. Beban tetap

i. Beban mati

Untukα= 36,23˚profil kanal yang digunakan baja kanal CNP 160. 65. 10,5. 7,5

Periksa kesetabilan penampang

Baja Canal CNP 160. 65. 10,5. 7,5 h = 160 mm

d = 10.5 mm A = 24,0 cm2

Ix = 925 cm4

Iy = 85,3 cm4

ix = 6,21cm

iy = 1,89 cm

Wx = 116 cm3

Wy = 18,3 cm3

Berat = 18,8 kg/m 25,25 M

18,5 M 

25,25 M

18,5 M 

(3)

Flans / Flange = √

√

…….OK!!!!

Web = √

√

…….OK!!!!

Beban atap (qat) = BebanAtap (genteng) x JarakGording (i)

= 6,5 kg/m2 x 0,8 m

= 5,2 kg/m’

qatap =

Berat sendiri (qbs)dari tabel kanal baja = 18,8

Berat mati(qbm) =Beban atap + Beban sendiri

= + 18,8

= 25,25 kg/m

Beban aksesoris 15 % = 15% x qbm

= 15% x 25,25

= 3, 78 kg/m

qbmtotal = qbm+ Bebana sesoris

= 25,25 + 3,78

= 29,03kg/m

ii. Beban hidup

Beban orang (PH) = 100 kg

Beban hujan (PH) = W hujan x Luas daerah pembebanan

= 20 kg/ m2 x jarak gording x jarak kuda- kuda = 20 x 0,8 x 7,4

(4)

Beban hujan Beban orang,maka yang digunakan beban hujan Pengaruh kemiringan atap

Px = PH x

= 118,4 x = 69,97 kg/m

qx = q bmx

= 29,09 x = 17,16 kg/m

Py = PH x

= 118,4 x = 95,50 kg/m

qy = q bmx

= 29,09 x = 23,41 kg/m

Mmax = qx L2 + PX L

Mbhx = +

= 117,46 + 129,44 = 246,9 kg/m

Mbhy = qyL2 + Py L

= +

=160,24 + 176,68 = 336,92 kg/m Periksa tegangan lentur

=

= 290,44 kg/cm

=

(5)

total = √

= √

= 1380,08 1600 …..OK!!!!

iii. Periksa tegangan geser

VAX =

x q

bmx x j +

x

Px

=

x

17,16 x 7,4

+

x

69,97

= 63,49 + 34,98

= 98,48 kg

VAy =

x q

bmy x j +

x

Py

=

x

23,41 x 7,4

+

x

95,50

= 68,62 + 47,75

= 134,37 kg

x =

=

= 22,46 kg/m

y =

=

= 28,16 kg/m

totatotal = √

= √

(6)

ijin = 0,6 x

= 0,6 x 1600 kg/m

= 960 kg/m

Maka 36,01 960 …..OK!!!!

iv. Periksa tengangan Huber Henky

i =

= √

= 1381,49 kg/m 1600 kg/m ….. OK !!!!!!

v. Periksa kekakuan lendutan pada gording

X =

=

0,344 + 0,034

= 0,648 cm

y =

=

5,102 + 4,5

= 9,602 cm

total = √

(7)

Lendutan Ijin =

=

3,083

Maka 9,624 3,083 cm….. NOT OK !!!!!!

vi. Desain Trekstang

=

= 380

Lendutan Ijin =

=

1,583

X =

=

0,02 + 0,04

= 0,06 cm

y =

=

0,354 + 0,609

= 0,963 cm

total = √

= √

(8)

II.Beban sementara

C = (0,02 x

)

– 0,4

= (0,02 x 36,23)-0,4 = 0,324

qangin = Wangin x C x i

= 45 x 0,324s x

=

14,48

M

angin

=

x

qangin x j2

=

x

14,48 x 7,42

=

99.11

qay = qangin = 14,48

qax = 0

Max = 0

May = 99.11

i. Bentuk kekuatan lentur akibat beban sementara

X =

= 290,44 + 0 = 290,44

y =

=

1350, 034

Periksa kelenturan

p = √

= √

(9)

ii. Periksa kekuatan geser akibat bebabn sementara

VAX =

x q

bmx x l +

x

Px +

x q

ax x l

= x 23,41 x 7,4 + x 69,97 + x 0 x 7,4

= 63,49 + 34,98 + 0

= 98,48 kg

VAy =

x q

bmy x j +

x

Py + +

x q

ay x l

= x 23,41 x 7,4 + x 95,50 + x 14,48 x 7,4

= 68,62 + 47,75 + 53,576

= 187,943 kg

x =

=

= 16,4 kg/m

y =

=

= 53,76 kg/m

= √

= 56,205 kg/m

ijin = 0,6 x

= 0,6 x 1600 kg/m

= 960 kg/m

(10)

iii. Periksa idiil

i = √ x 1,25

= √ 1600 x 1,25

= 1384,34 kg/m 2000 kg/m ….. OK !!!!!!

(11)

(12)

A.

BebanMati

I. BebanAtap

 BebanMati

q

atap= Watapx j

= 6,5 x 7,4

= 48,1 ⁄

 BebanAsesoris (15%) = 7,22 ⁄

q

total

=

48,1+7,22

= 55,32 ⁄



q

a =

=

= 68, 37 ⁄

Pa1 =

q

ax ( a ) = 68, 37 x (8) = 273,28 ⁄

Pa2 =

q

ax ( a+b ) = 68, 37 x ( 8+8 ) = 546,96 ⁄

Pa3 =

q

ax ( b+c ) = 68, 37 x ( 8+4 ) = 410,22 ⁄

Pa4 =

q

ax ( c+d ) = 68, 37 x ( 4+5,25 ) = 316,21 ⁄

Pa5 =

q

ax ( d+e ) = 68, 37 x ( 5,25+11,75 ) = 581,15 ⁄

Pa6 =

q

ax ( e+f ) = 68, 37 x ( 11,75+4 ) = 538,41 ⁄

Pa7 =

q

ax ( f+g ) = 68, 37 x ( 4+9,5 ) = 461,49 ⁄

(13)

II. BebanHidup

Beban Orang = 100 kg

BebanHujan = Whujanx Jarakgording x jarakKuda-kuda

= 20 x 0,4 x 7,4 = 118,4 kg

PH1 = 118,4 x 8 = 473,6 ⁄

PH 2 = 118,4 x ( 8+8 ) = 947,2 ⁄

PH 3 = 118,4 x ( 8+4 ) = 710,4 ⁄

PH 4= 118,4 x ( 4+5,25 ) = 547,6 ⁄

PH 5 = 118,4 x ( 5,25+11,75 ) = 1006,4 ⁄

PH 6 = 118,4 x ( 11,75+4 ) = 932,4 ⁄

PH 7 = 118,4 x ( 4+9,5 ) = 799,2 ⁄

(14)

III. BeratGording

G =

q

gordingx j

= 18,8 x 7,4 = 139,12 kg

PG1 = 6,5 x G = 6,5 x 139,12 = 904,28 kg

PG2 = 6,5 x G + 6 x G = 12,5 x 139,12 = 1739 kg

PG3 = 6 x G +3 x G = 9 x 139,12 = 1252,08 kg

PG4 = 3 x G +4 x G = 7 x 139,12 = 973,84 kg

PG5 = 4 x G +9 x G = 13 x 139,12 = 1808,56 kg

PG6 = 3 x G +9 x G = 12 x 139,12 = 1669,44 kg

PG7 = 3 x G +7,5 x G = 10,5 x 139,12 = 1460,79 kg

(15)

IV. BeratSendiri Kuda - Kuda

NO. BATANG PANJANG (m) NO. BATANG PANJANG (M)

S1 9,92 S14 8,00

S2 9,92 S15 5,86

S3 4,96 S16 9,92

S4 6,51 S17 11,72

S5 14,57 S18 10,75

S6 4,96 S19 12,90

S7 11,78 S20 13,93

S8 9,50 S21 16,75

S9 4,37 S22 14,29

S10 11,75 S23 8,14

S11 5,25 S24 6,57

S12 4,37 S25 6,96

S13 8,00

(16)

Rangka Kuda-Kuda Anak ( batang S5, L = 14,57 M )

NO. BATANG PANJANG (m)

a1 3,85

a2 3,85

a3 3,85

a4 3,85

a5 -

a6 -

a7 -

a8 -

a9 1,25

a10 4,42

a11 2,50

a12 4,42

a13 1,25

(17)

Rangka Kuda-Kuda Anak ( batang S19, L = 12,90 M )

a1 3,31

a2 3,31

a3 3,31

a4 3,31

a5 -

a6 -

a7 -

a8 -

a9 0,75

a10 3,31

a11 1,50

a12 3,31

a13 0,75

= 22,86

a1 3,56

a2 3,56

a3 3,56

a4 3,56

a5 -

a6 -

a7 -

a8 -

a9 0,75

a10 3,56

a11 1,50

a12 3,56

a13 0,75

(18)

a1 4,37

a2 4,37

a3 4,37

a4 4,37

a5 -

a6 -

a7 -

a8 -

a9 1,25

a10 4,88

a11 2,50

a12 4,88

a13 1,25

(19)

a1 3,79

a2 3,79

a3 3,79

a4 3,79

a5 -

a6 -

a7 -

a8 -

a9 1,25

a10 4,36

a11 2,50

a12 4,36

a13 1,25

(20)

S₅

S

1

9

S 2 0

S

2

1

S2 2

 Menentukan Profil Rangka Kuda-Kuda Utama



 m

S7 = 11,78 m (Terpanjang)

Profil siku 200.200.18 ix = 6,13

6,13 ≥ 5,89 ok…!!!!

 Struktur Utama

Panjang total = 231,65 x 2 = 463,3 m

(21)

Q_bs =

=

= 498.162 kg

Asesoris (15 %) = 498.162 x 15 %

= 74,72 kg

Q_bs ₌498.162 + 74,72

= 572,88 kg

Pbs1 = 572,88 x

8 = 2291,52 ⁄

Pbs2 = 572,88 x

x

( 8+8 ) = 4583,04 ⁄

Pbs3 = 572,88 x

x

( 8+4 ) = 3437,28 ⁄

Pbs4= 572,88 x

x

( 4+5,25 ) = 2649,57 ⁄

Pbs5 = 572,88 x

x

( 5,25+11,75 ) = 4869,48 ⁄

Pbs6 = 572,88 x ( 11,75+4 ) = 4511,43 ⁄

Pbs7 = 572,88 x ( 4+9,5 ) = 3866,94 ⁄

(22)

 Menentukan Profil Rangka Kuda-Kuda Anak

2.44 ≤ ix

Gunakan Profil Siku 90.90.13 2.44 ≤ 2.69 …. Ok!!!

S5 = Panjang total x Berat sendiri profil x 2

= 29,24 x 17.1x 2 = 1000 kg

Berat Asesoris (15 %) = 1000 x 15 % = 150 kg

Total = 1000 + 150 = 1150 kg

= 22,86 x 17,1 x 2 = 781,812 kg

Berat Asesoris (15 %) = 781,812 x 15 % = 117,27 kg

Total = 781,812 + 117,27 = 899,083 kg

= 24,36 x 17,1 x 2 = 833,112 kg

Total = 833,112 + 124,966 = 958,078 kg

= 32,24 x 17,1 x 2 = 1102,608 kg

Total = 1102,608 + 165,391 = 1267,99 kg

= 28,88 x 17,1 x 2 = 987,696 kg

(23)

qbx4 = Berat total (S19 +S20)

= 899,083 + 958,078 = 1857,161 kg

qbx5 = Berat total (S5 +S20+S21+S22)

= + 958,078 + 1267,99 + 1135,8504 = 4511,9184 kg

qbx6 = Berat total (S5 +S22)

= 1150 + 1135,8504 = 2285,8504 kg

Pbs1 = 2291,52 ⁄

Pbs2 = 4583,04 ⁄

Pbs3 = 3437,28 ⁄

Pbs4 = 2649,57 + ( 1857,161 ) = 3578,1505 ⁄

Pbs5 = 4869,48 + ( 4511,9184 ) = 7125,439 ⁄

Pbs6 = 4511,43 + ( 2285,8504) = 5654,3552 ⁄

Pbs7 = 3866,94 ⁄

(24)

B.

BebanSementara

I. P. AnginKiri

B E B A N A K I B A T A N G IN K IR I

 MukaAngin

q

angin = Wanginx j x c c = ( 0,02 x ) – 0,14

= 45 x 7,4 x 0,3246 = ( 0,02 x 36,23 ) – 0,14

= 108,092 ⁄ = 0,3246

Pag1 =

q

anginx ( a ) = 108,092 x ( 9,92 ) = 536,136 ⁄

Pag2 =

q

anginx ( a+b ) = 108,092 x ( 9,92+9,92 ) = 1072,27 ⁄

Pag3 =

q

anginx ( b+c ) = 108,092 x ( 9,92+4,96 ) = 804,20 ⁄

Pag4 =

q

anginx ( c+d ) = 108,092 x ( 4,96+6,51 ) = 887,98 ⁄

(25)

 MukaAngin

q

angin = Wanginx j x c

= 45 x 7,4 x 0,4

= 133,2 ⁄

Pag5’ =

q

anginx ( e ) = 133,2 x ( 14,57 ) = 970,362 ⁄

Pag6 =

q

anginx ( e+f ) = 133,2 x ( 14,57+4,96 ) = 1300,698 ⁄

Pag7 =

q

anginx ( f+g ) = 133,2 x ( 4,96+11,78 ) = 1114,884 ⁄

Pag8 =

q

anginx ( g ) = 133,2 x ( 11,78 ) = 784,548 ⁄

II. P. AnginKanan

(26)

 MukaAngin

q

= 45 x 7,4 x 0,3246

= 108,092 ⁄

Pag8 =

q

anginx ( g ) = 108,092 x ( 11,78 ) = 636,66 ⁄

Pag7 =

q

anginx ( g+f ) = 108,092 x ( 11,78+4,96 ) = 904,730 ⁄

Pag6 =

q

anginx ( f+e ) = 108,092 x ( 4,96+14,57 ) =1055,518 ⁄

Pag5' =

q

anginx ( e ) = 108,092 x ( 14,57 ) = 787,450 ⁄

 MukaAngin

q

= 45 x 7,4 x 0,4

= 133,2 ⁄

Pag5 =

q

anginx ( d ) = 108,092 x ( 6,51) = 433,566 ⁄

Pag4 =

q

anginx ( d+c ) = 108,092 x ( 6,51+4,96) = 763,902 ⁄

Pag3 =

q

anginx ( c+b ) = 108,092 x ( 4,96+9,92 ) = 991,008 ⁄

Pag2 =

q

anginx ( b+a ) = 108,092 x ( 9,92+9,92 ) = 1321,344 ⁄

(27)

No. Batang

TABEL KOMBINASI PEMBEBANAN PADA STRUKTUR RANGKA KUDA-KUDA

COMB1 (Kg) COMB2 (Kg) COMB3 (Kg) BATANG YANG DIPILIH (Ton)

Tarik Tekan Tarik Tekan Tarik Tekan Tarik Tekan

S1 -38356,45 -38282,26 -37527,88 38,36

S2 -31743,95 -31330,91 -31332,95 31,74

S3 -32314,54 -32386,9 -31354,95 32,38

S4 -26303,14 -25909,39 -25906,53 26,30

S5 -26303,14 -26877,89 -25012,16 26,88

S6 -41782,47 -41129,67 -41405,16 41,78

S7 -37693,02 -37033,48 -37481,66 37,69

S8 30405,41 30336,95 29858,73 30,41

S9 33187,97 33113,25 32591,27 33,19

S10 33704,2 34299,92 32489,09 34,30

S11 26066,81 29163,55 22585,5 29,16

S12 27949,94 31421,35 23993,91 31,42

S13 30940,57 35027,84 26198,66 35,03

S14 30940,57 35027,84 26198,66 35,03

S15 4583,04 4583,04 4583,04 4,58

S16 -6612,5 -7736,77 -5227,07 7,74

S17 -3857,48 -4584,42 -3090,65 4,58

S18 1236,42 1011,78 1620,62 1,62

S19 13633,46 15233,36 11691,22 15,23

S20 -12866,99 -14836,56 -10464,27 14,84

S21 27695,11 28300,9 26412,33 28,30

S22 -15190,81 -13051,16 -16846,19 16,85

S23 14659,71 13764,6 15291,25 15,29

S24 5417,22 6507,93 4319,52 6,51

(28)

I. Desain Batang Tarik

Dipilih Profil 2L 200. 200. 18

W = 54,30 x 2 = 108.60 kg/m

Ab = 69,10 x 2 = 138,20 cm2

Ixo = Iyo = 2600 cm4

ixo = iyo = 6,13 cm

a = 2ey + t

= 2 x (5,6) + 1,9 = 13,1

ijin = 1600 kg/ cm2

 Analisa kelangsingan batang tarik

Batang tarik terpanjang : 11,75 m (S10) ix = ixo = 6,13 cm

Iy = √

= √

= 14,373 cm4

λ =

=

= 191.68 < 200 …. Ok !!!

 Luas penampang efektif profil

An = 0,85 x Ab

= 0,85 x 138,20

= 117,47 cm2

Analisa kekuatan batang tarik

Batang tarik dengan gaya tarik maksimum adalah : 35,03

σtr =

=

(29)

II. Desain Batang Tarik

 Analisa kelangsingan batang tekan majemuk

Batang tekan yang terpanjang : 11,78 m (S7) Desain tekuk terhadap sumbu bahan

ix = ixo = 6,13 cm

= 14,373 cm4

λx =

=

= 192,17 < 200 …. Ok !!! Desain terhadap batang tekuk ix = ixo = 6,13 cm

Iy = √

= √

= 14,373 cm4

λy =

=

= 81,96< 200 …. Ok !!!

λw = √

= √

m = 2

Desain optimim ( λw ≤ λx ) λx2 _{= λy}2 _{+ λ}

12

λ12 = λx2 - λy2

= 36929,18 – 6717,52

λ1 =

= 173,82 cm

(30)

L1 = λ1 x

i

1

=

173,82 x 2.93

= 509,28 cm Jumlah medan

n =

=

= 2,31 3 buah

L1 =

=

= 392,67 cm (jarak kopel)

λ1 =

=

134,02

Periksa kelangsingan terhadap sumbu bebas bahan

λw = √ λx

= 192,17

= 156,825 192,17 …..Ok!!!

 Periksa kekuatan batang tekan

Batang tekan dengan gaya maksimum : 41,78 ton

λc = x

√

=

x

√

= 1,69 1,20 maka w = 1,25

w = 1,25 λc²

= 1,25 x 1,692 = 3,56

tekan =

=

(31)

III. Desain plat koppel

Gaya tekan maksimum = 41,78 ton Menggunakan Profil 2L 200. 200. 18

a = 13

L1 = 392,67

I1 = 2600

 Syarat kekakuan plat koppel

10

I

koppel = 1/12 x t h3

Maka,

1/12 x t h3 10 x xa

t h3 10 x

x 13,1 x 12

t h3 10408,83

Dicoba plat Koppel tebal : 0,64 cm

t h3 10408,83

h3

h3 16263,79

h 25,34 28 cm

b = (15x2) + 1.9

= 31,9 cm

Ukuran pelat koppel : 31.90 x 28 x 0,64

 Periksa kekuatan plat koppel

L = 2% x 41780

= 835,60 kg

Atau

L =

(32)

T =

=

= 55783,09 kg

Sy = A1 x 1/2 a

= 42,74 x 6,5

= 277,81 cm2

Iy = 2 (Iyo) + 2A(1/2 a)2

= 2 x 2600 + 85,48 x 43

= 8867,31 cm4

T =

x

<

Tijin

=

x

<

0,6 x σijin

= 91,80

<

960 ….Ok!!!!

Jadi ukuran plat koppel b = 31.90 ; h = 28 ; t = 0.64 dapat dipakai

Jumlah Koppel = 3 buah

Jarak Koppel = 392,67 cm

(33)

Tabel Perhitungan Las

NO

BTNG SUDUT

GAYA

BTNG P BAR A a ln lbr lbr total

8

0

30.41

7.60 0.0082 1.27 0.0065 3.82 4.00

10 34.3 8.58 0.0093 1.27 0.0073 3.82 4.00

11 29.16 7.29 0.0079 1.27 0.0062 3.82 4.00

13 35.03 8.76 0.0095 1.27 0.0075 3.82 4.00

14 35.03 8.76 0.0095 1.27 0.0075 3.82 4.00

22 34.72 16.85 4.21 0.0040 1.27 0.0032 3.81 4.00

1

36.23

38.36

9.59 0.0091 1.27 0.0072 3.82 4.00

2 31.74 7.94 0.0075 1.27 0.0059 3.82 4.00

3 32.38 8.10 0.0077 1.27 0.0061 3.82 4.00

4 26.3 6.58 0.0062 1.27 0.0049 3.81 4.00

9 33.19 8.30 0.0079 1.27 0.0062 3.82 4.00

12 31.42 7.86 0.0075 1.27 0.0059 3.82 4.00

24 52.49 6.51 1.63 0.0013 1.27 0.0011 3.81 4.00

15

90

4.58

1.15 0.0007 1.27 0.0006 3.81 4.00

17 4.58 1.15 0.0007 1.27 0.0006 3.81 4.00

19 15.23 3.81 0.0036 1.27 0.0028 3.81 4.00

21 28.3 7.08 0.0044 1.27 0.0035 3.81 4.00

23 15.29 3.82 0.0024 1.27 0.0019 3.81 4.00

25 9.44 2.36 0.0015 1.27 0.0012 3.81 4.00

18

111.86

1.62

0.41 0.0003 1.27 0.0002 3.81 4.00

20 14.84 3.71 0.0026 1.27 0.0021 3.81 4.00

5

143.77

26.88

6.72 0.0064 1.27 0.0050 3.82 4.00

6 41.78 10.45 0.0099 1.27 0.0078 3.82 4.00

7 37.69 9.42 0.0090 1.27 0.0070 3.82 4.00

(34)

Perhitungan las

 Batang S1

α = 36.23˚

p = = 9,59 cm

p =

A =

= √

=0,0091

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0072 cm

lbr = ln + 3 x a

= 0,0072 + 3 x 1,27

=3,82 cm 4 cm

 Batang S2

α = 36.23˚

p = = 7,94 cm

p =

A =

= √

=0,0075

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0059 cm

lbr = ln + 3 x a

= 0,0059 + 3 x 1,27

(35)

 Batang S3

α = 36.23˚

p = = 8,10 cm

p =

A =

= √

=0,0077

profil 200. 200. 18

a = 1,82 = 1,27 cm

ln = =

= = 0,0061 cm

lbr = ln + 3 x a

= 0,0061 + 3 x 1,27

=3,82 cm 4 cm

 Batang S4

α = 36.23˚

p = = 6,58 cm

p =

A =

= √

=0,0062

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0049 cm

lbr = ln + 3 x a

= 0,0049 + 3 x 1,27

(36)

 Batang S5

α = 143,77 ˚

p = = 6,72 cm

p =

A =

= √

=0,0064

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0050cm

lbr = ln + 3 x a

= 0,0050 + 3 x 1,27

=3,82 cm 4 cm

 Batang S6

α = 143,77 ˚

p = = 10,45cm

p =

A =

= √

=0,0099

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0078 cm

lbr = ln + 3 x a

= 0,0078 + 3 x 1,27

(37)

 Batang S7

α = 143,77 ˚

p = = 9,42 cm

p =

A =

= √

=0,0090

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0070cm

lbr = ln + 3 x a

= 0,0070 + 3 x 1,27

=3,82 cm 4 cm

 Batang S8

α = 0˚

p = = 7,60 cm

p =

A =

=

=0,0082

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0065 cm

lbr = ln + 3 x a

= 0,0065 + 3 x 1,27

(38)

 Batang S9

α = 36,23˚

p = = 8,30 cm

p =

A =

= √

=0,0079

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0062 cm

lbr = ln + 3 x a

= 0,0062 + 3 x 1,27

=3,82 cm 4 cm

 Batang S10

α = 0˚

p = = 8,58 cm

p =

A =

=

=0,0093

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0073 cm

lbr = ln + 3 x a

= 0,0073 + 3 x 1,27

(39)

 Batang S11

α = 0˚

p = = 7,29 cm

p =

A =

=

=0,0079

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0062 cm

lbr = ln + 3 x a

= 0,0062 + 3 x 1,27

=3,82 cm 4 cm

 Batang S12

α = 36,23˚

p = = 7,86 cm

p =

A =

= √

=0,0075

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0059 cm

lbr = ln + 3 x a

= 0,0059 + 3 x 1,27

(40)

 Batang S13

α = 0˚

p = = 8,76 cm

p =

A =

=

=0,0095

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0075 cm

lbr = ln + 3 x a

= 0,0075 + 3 x 1,27

=3,82 cm 4 cm

 Batang S14

α = 0˚

p = = 8,76 cm

p =

A =

=

=0,0095

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0075 cm

lbr = ln + 3 x a

= 0,0075 + 3 x 1,27

(41)

 Batang S15

α = 90˚

p = = 1,15 cm

p =

A =

=

=0,0007

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0006 cm

lbr = ln + 3 x a

= 0,0006 + 3 x 1,27

=3,81 cm 4 cm

 Batang S16

α = 143,77 ˚

p = = 1,94 cm

p =

A =

= √

=0,0018

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0014 cm

lbr = ln + 3 x a

= 0,0014 + 3 x 1,27

=3,81 cm 4 cm

(42)

 Batang S17

α = 90˚

p = = 1,15 cm

p =

A =

=

=0,0007

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0006 cm

lbr = ln + 3 x a

= 0,0006 + 3 x 1,27

=3,81 cm 4 cm

 Batang S18

α = 111,86˚

p = = 0,4 cm

p =

A =

= √

=0,0003

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0002 cm

lbr = ln + 3 x a

= 0,0002 + 3 x 1,27

(43)

 Batang S19

α = 90˚

p = = 3,81 cm

p =

A =

=

=0,0036

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0028 cm

lbr = ln + 3 x a

= 0,0028 + 3 x 1,27

=3,81 cm 4 cm

 Batang S20

α = 112,14˚

p = = 3,71 cm

p =

A =

= √

=0,0026

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,00021 cm

lbr = ln + 3 x a

= 0,0021 + 3 x 1,27

(44)

 Batang S21

α = 90˚

p = = 7,08 cm

p =

A =

=

=0,0044

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0035cm

lbr = ln + 3 x a

= 0,0035+ 3 x 1,27

=3,81 cm 4 cm

 Batang S22

α = 34,72˚

p = = 4,21cm

p =

A =

= √

=0,0040

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,00032 cm

lbr = ln + 3 x a

= 0,0032 + 3 x 1,27

(45)

 Batang S23

α = 90˚

p = = 3,82 cm

p =

A =

=

=0,0024

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0019cm

lbr = ln + 3 x a

= 0,0019 + 3 x 1,27

=3,81 cm 4 cm

 Batang S24

α = 52,49˚

p = = 1,61 cm

p =

A =

= √

=0,0013

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,00011 cm

lbr = ln + 3 x a

= 0,0011 + 3 x 1,27

(46)

 Batang S25

α = 90˚

p = = 2,36 cm

p =

A =

=

=0,0015

profil 200. 200. 18

a =

=

= 1,27 cm

ln = =

= 0,0012 cm

lbr = ln + 3 x a

= 0,0012 + 3 x 1,27

(47)

(48)

(49)

(50)

(51)

(52)

(53)

(54)

(55)