BAB 7 PERENCANAAN SLOOF mmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

BAB VII

PERENCANAAN SLOOF

 PERENCANAAN SLOOF MEMANJANG (25 X 50 )

 Direncanakan :

Dimensi sloof : 25/50 Tulangan Sengkang : Ø10 mm

Fc’ : 25 Mpa

Fy : 400 Mpa

Selimut beton : 30 mm

 PERBANDINGAN KEKAKUAN SLOOF TERHADAP KOLOM (EI/L) sloof = ^{121 � 25 � 50}₅₅₀ ³ = 473,48 Cm2

(EI/L) Kolom = ^{121 � 50 � 50}₆₀₀ ³ = 868,05 Cm2

(EI/L) Kolom > (EI/L) sloof (OK) 1. Pembebanan sloof

- akibat beban mati

Berat sendiri sloof = 0,25x 0,50 x 24 KN/m = 3 KN/m

Berat dinding bata = 8 x 0,1 x 12 KN/m = 9,6 KN/m + qd = 12,6 KN/m -Beban terfaktor (qu) = 1,4 (qu)

= 1,4 (12,6)

= 17,64 KN/m

Penulangan Tumpuan Balok Sloof Memanjang

fc’ = 25 Mpa

fy = 400 Mpa

lebar balok (b) = 250 mm tinggi balok (h)

Mu = 42,740 kNm

= 500 mm

 d rencana = h-50 ; dengan d’ = 50 mm

= 500 – 50

= 450 mm

 Rn

= 42,740 x 10^6 0.9 � 250� 450^2

= 0,938 Nmm

 m =

=_0.85�25⁴⁰⁰ = 18,823Nmm

� ����� =

^{0,85 ��}_�� ^'

1 − 1 −

_{0,85 ��}^2�� _'

= 0,85� 25

400 1 − 1 − 2� 0,938

0,85�25 = 0,00239

� min = 1,4

�� = 1,4

400 = 0,0035

�� = 0,85 ��

^'

�1

�� . 600 600 + ��

= 0,85 � 25�0,85

400 . 600

600 + 400 = 0,0270

� max = 0,75 �� = 0,75 � 0,0270 = 0,0202

Maka,

� perlu = 0,0035

(As) = = 0,0035.250 450

=393,75 mm2

 Dipakai tulangan = 4 = 804 ² As Perlu = 804 ²

 d pakai = h – selimut beton – sengkang – ½ D

= 500 – 30 – 10 – ½ (16)

= 452 > 450 d rencana (OK) Tulangan Bagi

As = 0,0014 x b x d

= 0,0014 x 250 x 452

= 158,2 mm

²

Dipakai tulangan = 3D12 = 339 m

� =

_{0,85 ��}^{�� ��}_'�

=

0,85� 25 � 250^{804 � 400}

= 60,536

� =

_�^�

=

^60,536_0,85

= 71,218

Kontrol

 Mn = As x fy

= 804 x 400 x (452-30,268)x10^-6

= 135,629 kNm

 MR = Mn

= 0,85 (135,629)

= 115,284 kNm Syarat kontrol kekauan MR> Mu

115,284 kNm > 42,740 kNm

PENULANGAN TUMPUAN SLOOF MEMANJANG

Penulangan Lapangan Balok Sloof Memanjang

fc’ = 25 Mpa

fy = 400 Mpa

lebar balok (b) = 250 mm tinggi balok (h)

Mu = 47,040 kNm

= 500 mm

 d rencana = h-50 ; dengan d’ = 50 mm

= 500 – 50

= 450 mm

 Rn

= 47,040x 10^6 0.9 � 250� 450^2

= 0,836 Nmm

 m =

=_0.85�25⁴⁰⁰ = 18,823Nmm

� ����� =

^{0,85 ��}_�� ^'

1 − 1 −

_{0,85 ��}^2�� _'

= 0,85� 25

400 1 − 1 − 2� 0,836

0,85�25 = 0,00213

� min = 1,4

�� = 1,4

400 = 0,0035

�� = 0,85 ��

^'

�1

�� . 600 600 + ��

= 0,85 � 25�0,85

400 . 600

600 + 400 = 0,0270

� max = 0,75 �� = 0,75 � 0,0270 = 0,0202

Maka,

� perlu = 0,0035

(As) = = 0,0035.250 450

=393,75 mm2

 Dipakai tulangan = 4D16= 804 ² As Perlu = 804 ²

 d pakai = h – selimut beton – sengkang – ½ D

= 500 – 30 – 10 – ½ (16)

= 452 > 450 d rencana (OK) Tulangan Bagi

As = 0,0014 x b x d

= 0,0014 x 250 x 452

= 158,9 mm

²

Dipakai tulangan = 3D12 = 339 m

� = �� ��

0,85 ��

^'

� = 679 � 400

0,85� 25 � 250 = 51,124

� =

_�^�

=

^51,164_0,85

= 60,192

Kontrol

 Mn = As x fy

= 679 x 400 x (554-25,562)x10^-6

= 116,363 kNm

 MR = Mn

= 0,85 (116,363)

= 98,908 kNm Syarat kontrol kekauan MR> Mu

98,908 kNm > 47,040 kNm

PENULANGAN LAPANGAN SLOOF MEMANJANG

PERHITUNGAN TULANGAN GESER BALOK SLOOF MEMANJANG

b = 250 mm ,

h = 500 mm

Fc’ = 25 Mpa Fy = 240 Mpa d = h – 50

= 500 – 50

= 450 mm

Perhitungan tulangan geser untuk sloof didasarkan pada jarak minumun

S = d/2

= 450/2

= 225 mm

MAKA DIPASANG SENGKANG Ø10-275

 PERENCANAAN SLOOF MELINTANG (25 X 50 )

 Direncanakan:

Dimensi sloof : 25/50 Tulangan Sengkang : Ø10 mm

Fc’ : 25 Mpa

Fy : 400 Mpa

Selimut beton : 30 mm

 PERBANDINGAN KEKAKUAN SLOOF TERHADAP KOLOM (EI/L) sloof = ^{121 � 25 � 50}₅₀₀ ³ = 520 Cm2

(EI/L) Kolom = ^{121 � 50 � 50}₅₀₀ ³ = 1041 Cm2

(EI/L) Kolom > (EI/L) sloof (OK) 1. Pembebanan sloof

- akibat beban mati

Berat sendiri sloof = 0,25 x 0,50 x 24 KN/m = 3 KN/m

Berat dinding bata = 8 x 0,1 x 12 KN/m = 9,6 KN/m + qd = 12,6 KN/m -Beban terfaktor (qu) = 1,4 (qu)

= 1,4 (12,6)

= 17,64 KN/m

Penulangan Tumpuan Balok Sloof melintang

fc’ = 25 Mpa

fy = 400 Mpa

lebar balok (b) = 250 mm tinggi balok (h)

Mu = 11,858 kNm

= 500 mm

 d rencana = h-50 ; dengan d’ = 50 mm

= 500 – 50

= 450 mm

 Rn

= 11,858 x 10^6 0.9 � 250� 450^2

= 0,260 Nmm

 m =

=_0.85�25⁴⁰⁰ = 18,823Nmm

� ����� =

^{0,85 ��}_�� ^'

1 − 1 −

_{0,85 ��}^2�� _'

= 0,85� 25

400 1 − 1 − 2� 0,260

0,85�25 = 0,00113

� min =

^1,4_��

=

₄₀₀^1,4

= 0,0035

�� = 0,85 ��

^'

�1

�� . 600 600 + ��

= 0,85 �25�0,85

400 . 600

600 + 400 = 0,0270

� max = 0,75 �� = 0,75 � 0,0270 = 0,0202

Maka,

� perlu = 0,0035

(As) = = 0,0035 x 250 450

=393,75 mm2

 Dipakai tulangan = 5D13 = 664 ² As Perlu = 664 ²

 d pakai = h – selimut beton – sengkang – ½ D

= 500 – 30 – 10 – ½ (13)

= 453 > 450 d rencana (OK) Tulangan Bagi

As = 0,0014 x b x d

= 0,0014 x 250 x 453

= 158,5 mm

²

Dipakai tulangan = 2D13 = 265 m

� =

_{0,85 ��}^{�� ��}_'�

=

0,85� 25 � 250^{664 � 400}

= 49,995

� =

_�^�

=

^49,995_0,85

= 58,817

Kontrol

 Mn = As x fy

= 664 x 400 x (453-24,997) x10^-6

= 113,677 kNm

 MR = Mn

= 0,85 (113,677)

= 117,812 kNm Syarat kontrol kekauan MR> Mu

96,625 kNm > 11,858 kNm

PENULANGAN TUMPUAN SLOOF MEMANJANG

Penulangan Lapangan Balok Sloof melintang

fc’ = 25 Mpa

fy = 400 Mpa

lebar balok (b) = 250 mm tinggi balok (h)

Mu = 8,291 kNm

= 500 mm

 d rencana = h-50 ; dengan d’ = 50 mm

= 500 – 50

= 450 mm

 Rn

= 8,291x 10^6 0.9 � 250� 450^2

= 0,181 Nmm

 m =

=_0.85�25⁴⁰⁰ = 18,823Nmm

� ����� =

^{0,85 ��}_�� ^'

1 − 1 −

_{0,85 ��}^2�� _'

= 0,85� 25

400 1 − 1 − 2� 0,181

0,85�25 = 0,00045

� min = 1,4

�� = 1,4

400 = 0,0035

�� = 0,85 ��

^'

�1

�� . 600 600 + ��

= 0,85 � 25�0,85

400 . 600

600 + 400 = 0,0270

� max = 0,75 �� = 0,75 � 0,0270 = 0,0202

Maka,

� perlu = 0,0045

(As) = = 0,0045 x 250 450

=506,25 mm2

 Dipakai tulangan = 5D13 = 664 ² As Perlu = 664 ²

 d pakai = h – selimut beton – sengkang – ½ D

= 500 – 30 – 10 – ½ (13)

= 453 > 450 d rencana (OK) Tulangan Bagi

As = 0,0014 x b x d

= 0,0014 x 250 x 453

= 158,5 mm

²

Dipakai tulangan = 2D13 = 265 m

� =

_{0,85 ��}^{�� ��}'�

=

0,85� 25 � 250^{664 � 400}

= 49,995

� =

_�^�

=

^49,995_0,85

= 58,817

Kontrol

 Mn = As x fy

= 664 x 400 x (453-24,997)x10^-6

= 113,677 kNm

 MR = Mn

= 0,85 (113,667)

= 96,625 kNm Syarat kontrol kekauan MR> Mu

96,625 kNm > 8,291 kNm

PENULANGAN LAPANGAN SLOOF MEMANJANG

PERHITUNGAN TULANGAN GESER BALOK SLOOF MELINTANG

b = 250 mm ,

h = 500 mm

Fc’ = 25 Mpa Fy = 240 Mpa d = h – 50

= 500 – 50

= 450 mm

Perhitungan tulangan geser untuk sloof didasarkan pada jarak minumun

S = d/2

= 450/2

= 225 mm

MAKA DIPASANG SENGKANG Ø10-225

Ø10-225 Ø10-225 Ø10-225

TABEL PENULANGAN MEMANJANG BALOK SLOOF

Jenis

Momen

Dimensi (cm)

Mu (kNm)

���� � ����� ����

As hitung (mm²)

As pakai (mm²)

MR(kNm) Tulangan

Tumpuan 25/50 42,270 0,0035 0,00239 0,0202 393,75 804 115,284 4D16

Lapangan 25/50 47,040 0,0035 0,00213 0,0202 393,75 804 98,908 4D16

TABEL PENULANGAN MELINTANG BALOK SLOOF

Jenis

Momen

Dimensi (cm)

Mu (kNm)

���� � ����� ����

As hitung (mm²)

As pakai (mm²)

MR(kNm) Tulangan

Tumpuan 25/50 11,858 0,0035 0,00113 0,0202 393,75 664 96,625 5D13

Lapangan 25/50 8,291 0,0035 0,00045 0,0202 506,25 664 96,625 5D13