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. Jiii TAPCmKHOABQC,TRtieiNGBAlH0CH<Ms'»ffC.S6».art:"

~ 111!

KY THUAT G L 4 I B A I TOAN VE KHI CACBONIC P H A N tlTVG |

VOfI DUNG DJCH BAZO M4J«a ,|!!i Ll Tbi Hpa', Hi Thj Phisnt?

TOMTAT

Khi CO2 Id mdt oxtt axit nin cdphdn ing Igo muii vHtta^dich baza mgnh iMr NaOH,Ca(OH)2...

Bii Viet ndy giai thieu cdc iy thugt gidi bii t^ hda hgaemTaiiegcbenic vUdung dich baza mgnh, nhdm mt/c dich ren luyen cho hgc sinh, cac thao lac ttr duy nhir phdn tich, ting hgp, so sdnh, khdi qudt hoa...

Tii khoa: ATj/ thuit, khi cacbonic, dur^ dieh baza mgnh. 11

l . D A T V A N D E J Trong vijc phat tiife ntag Inc cfa fapc surii, khto tinng lim l i phit tiife tOtig Inc

tu toy, ttong do cfe djc b i ^ chu y rto luyto oho hpc sinh cta fliao tfc tii duy nfan phta tt'cfa, tdng hpp, so sinh, khai qfat hda v i ba phnong phip htoh ttiinh phfa dota mdi [1].

De htoh ttitah cic ttiao ttc til duy dd ttri giio vien ota x i y dnng cac ky ttiujt giii bii tjp | | | |

cbo ttog vfe d l v i U t o tapng hda hpc cp flil [2], Jill

2.N0IDUNG ? ' "

2.1. Cff s d l j thuyit 2.1.1. Nhiim vu cua khi cacbonic Nhilm vii i : tjo muoi COi^'

CO2 + 20H- > CO32- + H2O (1) Nhilm vg 2: chuyfe COi^" v l HCO3"

CO2 -^ COi'- -1- H2O > 2HCO3- (2) 2.1.2. Xic dinh cdc muii tgo Ihanh dtra vao ty 1$ visi mol cua OH- vi C02

Tnrdng hifp I: 1m_ > 2 flri cU tjo mudi COs^".

n^Q

Thuang h^2:\< . V ^ < 2 thi tao ca hai lo^i mu6i HCO3- vk COa^-

? vien khoa Khoa hgc Tft nhiin, Tnmng Dgi hpc Hong Diic 84

(2)

TjyCHt KHOA H p c , TRgftNGBAIHOC H 6 N G BlJC - S6 29.20It

Thudng hep 3: -^^s 1 flri eU tjo muoi HCOi"

"cn 2.1.3. Bgc ciim cua ion C032-

+ COi^' fcio kit tiia vdi Ca^+ v i Ba^+:

COs^- + Ca^* > CaCOi i (3) COi^- + Ba^* > BaCOs i (4)

+ COi^" cd kfai ntag nhta proton: — C O i ^ + H * i-HCOj- (5)

HCOi- + i r >C02 + H20 (6) 2.1.4. Bgc diim cia ion HC03-

+ Ion HCOi- bj nUjt phta ngay kU dun ndng dung dich.

2HC03- - ^ CO3'- + CO2 + H2O (7) + Ion HCO3- vfa cd khi ntag cho, v t a cd khi ntag nhta proton.

HCO3- + H* > CO2 + H2O (8) HCO3- + OH- > C03^- + H2O (9) 2.1.5. Biln lugn theo dinh lugt bia loan khii Itrgng

+ Nfe kfaii lupng dung dich kfadng ddi ttudc v i sau phta fag flri

•"CO, phin lmg = tokSt tiia Bo thjnli

+D0 giim khii inpng cfa dmig dich ttndc phta fag so vdi dung dich sau phta tog:

"1 = mdd d v i c p h i n tog m^d , , „ p|,j„ ^ g = m k f t u a t,o thSnh nico,phS„ tag +DO tfag kfaii lupng cfa dung dich sau phta tog so vdi dung dich ttndc pfata tog:

» = mdd,auphintoE " d d p h i n t o g m r t c toco.phlntag ttt^tiv,t,oaiinlHnh,:t^

2.2. C i c bil tjp vjn dyng

Vi dM 1. Hip flm 6,72 lit kU CO2 d dktc vta dmig dicfa chfa 0,22 mol Ca(0H)2 vi 0.06 mol KOH sau phta tog hota tota ttiu dupc m gam kit ttia. Gii tti cfa m btag

' ^ ' ' ^ B-22. C.18. *D.20 Ldi giii:

BtrdcT.Xdc dinh nhilm vg cua CO2 dua vio ty le si mol cua OH vd CO,

(3)

T A P C t f K H i t t 3 B e C ^ T l » r c » M G « » i a O C B f t » 6 « < ) e - S d » . 2 M . t :

' * ~ ^ ° TTJ " f * 2 n t o C Q j f t o l i a i ! Q J i m u i i C 0 3 ^ ' v i H C 0 3 - : i'

"c(?, 0,3 3 , ;;

+ Phfa tog: , ,

CO2 + 20H- > C03^ + KiO (1) CO2 + OH- »HC03- (2) Btrac 2: Tinh si mol CO^-sinh rad (I):

+ Gii Sli n^^,_ = x mol v i n = y mol

+Tii(l)vi(2)tec6: "co^ = x + y = 0 , 3 v 4 Bg^ = 2 x + y = 0 , 5 n t o x = 0 , 2 v 4 y = 0 , i . : Budc3: Tinhm

+Phfa tog tjo kit tfa:

COi^' + C a ^ >CaC03 4, (3) 0,2 » 0,2 mol + Tii (3) ttri m = 0,2 .100 = 20 gam (chpn D).

Vf dij 2. Hip flip hit V lit kU CO2 d dkte vta dung djch X chfa 0,3 mol KOH v i 0,25 mol Na2C03 sau phfa fag hota tota ttm dnpc dung djch A. Chd Iupng dn dung dich CaCl2 dn vto dung djch A sau phta fag hota tota ttm dnpc 20 gam kit tto. Gii ttj cfa V btag

A. 4,48. *B.7,84. C. 11,2. D. 8,96.

Ldi giii:

Budcl: Tinh si mol ion COr'-ci tt-ong dung dich A:

+Ca^* + C03^' >CaC03j, (1) ; 0,2 < 0,2 mol ii + Tii (1) ta cd: «^„.. (ttoug dd A) = 0,2 mol 1 i

' hi

Budc 2: Xdc djnh nhilm vg cua khi CO2:

+ ^ ' "coi- '^''™8 dd A) < n„^,^ ( dd X) nto CO2 ttinc U t o bai nUtoi vy sau:

CO2 + KOH >KHC03 (2)

0.3 < - 0,3 ^ i CO2 + Na2C03 + H2O >NaHC03 (3)

0,05^-0,25-0,2 mol .JII

+ Tii (2) v4 (3) a cd: Heo, = 0,3 + 0,05 = 0,35 moi nto V - 7,84 Ut (chpn B).

(4)

T ^ CHI KHOA HQC, TRlT^G BAl HQC H6NG BtTC - S6 29.2016 VI dn 3. Hfa tan hfe hpp X gim a moi K v i b mol Ca vao 200 ml dung djch Ca(OH)2 IM ttm dupc dung dich A va V Bt kU H2 d dkte. Sue ta ta kU CO2 tiji dn vio dung djch A, kit qfa ttri ngUOm dupc bife ttri bdi d i ttri sau:

Sd mol CaC03

so mol CO2

D. 26,88.

1.2 1,7 Gii ttj cfa V bfeg:

' A . 14,56. B. 19,04. C.22,4.

Ldi giii:

Budc I. Tinh b:

+ KU «cq = 1,7-1,2 = 0,5 mol flri C O i l i m n b i t o i v u h d a t i m h l t x m o l k l t n l a :

C03^- + Ca^+ » CaCOi i (2) CO2 + CaC03 + H2O >Ca(HC03)2 (1)

0 , 5 - ^ 0 , 5 „,„, + Theo djnh lujt bio tota khdi Inpng nguydn td Ca ttii tti (1) ta cd:

"cJ- = "axq nen 0,5 = X = 0,2 + b nen b = 0,3 Budc 2. Tinh a:

+ KU Wco, = 1,2 - x= 1,2 - 0,5 = 0,7 mol ttii COi Iim nUem vy phta fag vdi KOH trong dung dich A cU tao muii axri:

CO; + KOH > KHCO3 (3)

0 . 7 - 0 , 7 „ o l + Theo djnb lujt bio tota khii lupng nguyen td K til cd:

K > KOH (4)

» > a mol 87

(5)

Tir (4) tiled: a = 0,7mol Budc3. TinhV:

+ Cic phfa fag tao kU Hi:

2K + 2H2O » 2K0H + H2

0,7 < 0,35 Ca + 2H2O » Ca(0H)2 + H2

0,3 > 0,3

• " ' :

(5) mol (6) mol + Til (5) v i (6) taeo:

" H , = 0,35 + 0,3 = 0,65 mol nen V = 14,56 Ht

VI dy 4. Hfe fliu hit 8,96 Ht kU CO2 d dktc vta m gam dung djch chfa 0,25 mol Ba(0H)2 v4 a mol KOH tfiu dupc kit tiia A va ( m-21,8) gam dung djch B. Gii tit Gto a bing A. 0,4. *B.0,1. C.0,2. D.0,3.

Ldi giii:

Buic T. Xdc dinh si mol kit tua A(BaCOs):

+ Theo djnh lujt bio tota khii lupng:

Am = 21,8 = mA - "^5= mA - 0,4.44 ndn mA = 39,4 gam + Pfata fag Uo kit tfa A:

CO2 + Ba^+ > BaC03 i (1) 0,2 0,2 < 39,4:197 mol Budc 2: Tinh a:

+ Vi tiong dung djcfa B cfafa Ba^* nto khdng cfafa CCfe^' vjy nUtoi vy ciia CO214:

CO2 + 20H- + Ba^+ > BaC03 4, (2) 0,2 0,4 < 0,2 mol CO2 1- OH- > HCO3- (3)

0 , 4 - 0 , 2 - ^ 0 , 2 „ „ 1 + Tn(2)v4(3)tocd:

%„ = 0,25.2 + a = 0,4 + 0,2 nto a = 0,1 (cfapn B)

VI du 5. Syc ta tir kU CO2 v4o dung dich Ca(0H)2 11,1% sau phta fag faoto tota

ttiu dnpc dung djch A. Kit qfa ttri ngUtoi dupe biiu ttri bdi d i ttij sau: ,

(6)

TAP c m KHOA HQC •mCONG BAI HQC H6NG BU'C - SO 29.2016

SdmolCaCO,

s i mol khi CO2

D. 16.875%

Ndng dp phfe ttam cua dung djch A 14:

A. 16.2% B. 14,59% * c . 15,28%

Ldi glii:

Budc I: Tinh khii lugng dung dich Ca(0H)2 11,1%:

"*• Khi "co, = 0,3 mol ttri kit tiia teo ttianfa Ito nfait vi nUtoi vy cfa 0,3 mol CO2 li:

'"ddCa(0H)^]l,l% "

CO2 + Ca(OH) 0,3 >0,3

0,3.74 11,1

CaC03 I + H2O 0,3 100= 200 gam

(1) mol

Budc 2: Tinh ndng dgphin tidm cua dung dich A:

+ NUem vy cfa 0,5 mol kU CO2:

C02 + Ca(OH)2 .CaCOj i- +H2O 0,3 >0,3 0,3 CO2 CaCOj + H2O >Ca(HC03)2 0,5 - 0,3 > 0,2 0,2 + Sau(2) v4 (3) ttri:

- So mol k l . taa CaCOj chna bi bda Km: 0.3 - 0,2 = 0.1 mol - Theo dinh luj. bao .ota khii lupng tii cd:

™<ldA= m,uc,iOH),ii.w. +"hq-'ncxo, =200 + 0.5.44-0.1.100-212 gam - Chi. ton duy nhi. tiong dung djch A la Ca(HC03)2: 0.2 mol

(2) mol (3) mol

„ . . . 0,2x162 .„

C^ddA = - — _ - _ . 100= 15,28% 212

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